如何使用表中的数据作为SQL中键值的实体？

我有如下表格：

是否有任何SELECT查询以以下形式显示表

---

非常感谢。

您可以尝试以下代码：

SELECT post_id,
       (SELECT meta_value from test where meta_key='_total') AS _total,
       (SELECT meta_value from test where meta_key='_phone') AS _phone,
       (SELECT meta_value from test where meta_key='_address') AS _address 
FROM test
GROUP BY post_id

更新 由于该表包含更多post_id，请检查以下更新

SELECT post_id,
       (SELECT meta_value from test t2 where meta_key='_total' AND t1.post_id=t2.post_id) AS _total,
       (SELECT meta_value from test t2 where meta_key='_phone' AND t1.post_id=t2.post_id) AS _phone,
       (SELECT meta_value from test t2 where meta_key='_address' AND t1.post_id=t2.post_id) AS _address
FROM test t1
GROUP BY post_id

---

我认为不需要访问同一个表四次

您可以按如下方式使用

条件聚合

：

SELECT post_id,
       max(case when meta_key='_total' then meta_value end) AS _total,
       max(case when meta_key='_phone' then meta_value end) AS _phone,
       max(case when meta_key='_address' then meta_value end) AS _address 
FROM test
GROUP BY post_id

---

我认为这与jquery没有任何关系。它返回的错误子查询返回的值大于1row@WebDesign，我已更新我的答案。请检查。我想加入并用另一个表输出您的查询，可能吗？非常感谢，我也会检查。