与计数记录的SQL相关的查询

我有一个反馈表，在其中我从客户那里得到反馈。他的桌子看起来像这样

ID  Service      Food      Behavior  Environment   OverallExprience  Flight    Date

1   Excellent   VeryGood    Good     Bad            Poor             EK0603  2018-03-29 
2   Excellent   Good      VeryGood   Excellent      Poor             EK0603  2018-03-29 

              Excellent        Very Good    Good     Bad     poor
Service         2                 0           0       0        0

Food            0                 1           1       0        0

Behavior        0                 1           1       0        0

Environment     1                 0           0       1        0

我只想从员工那里搜索日期（from->to）并获得简要报告，其中包括

• 优秀学生人数
• 数量非常好
• 货物数量
• 坏的数量
• 可怜的

对于所有给定的选项。 如果雇员选择的日期范围为2018-03-29至2018-03-29

所以他可以看到这样的记录

ID  Service      Food      Behavior  Environment   OverallExprience  Flight    Date

1   Excellent   VeryGood    Good     Bad            Poor             EK0603  2018-03-29 
2   Excellent   Good      VeryGood   Excellent      Poor             EK0603  2018-03-29 

              Excellent        Very Good    Good     Bad     poor
Service         2                 0           0       0        0

Food            0                 1           1       0        0

Behavior        0                 1           1       0        0

Environment     1                 0           0       1        0

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困在这里需要帮助。如果答案是在LINQ query中，这将非常有用，因为您想将列转换为行，我想您需要一些联合。 对于每个“类别”，您可能需要一个不同的查询，对于每个类别，您应该计算每个选项的投票数

请尝试此查询，它应该执行以下操作：

SELECT MAX('Service') AS Category,
       COUNT(CASE WHEN t.Servive = 'Excellent' THEN 1 END) AS Excellent,
       COUNT(CASE WHEN t.Servive = 'VeryGood' THEN 1 END) AS Very_Good,
       COUNT(CASE WHEN t.Servive = 'Good' THEN 1 END) AS Good,
       COUNT(CASE WHEN t.Servive = 'Bad' THEN 1 END) AS Bad,
       COUNT(CASE WHEN t.Servive = 'Poor' THEN 1 END) AS Poor
  FROM table1 t
 WHERE t.Date BETWEEN '2018-03-29' AND '2018-03-29'
UNION
SELECT MAX('Food') AS Category,
       COUNT(CASE WHEN t.Food = 'Excellent' THEN 1 END) AS Excellent,
       COUNT(CASE WHEN t.Food = 'VeryGood' THEN 1 END) AS Very_Good,
       COUNT(CASE WHEN t.Food = 'Good' THEN 1 END) AS Good,
       COUNT(CASE WHEN t.Food = 'Bad' THEN 1 END) AS Bad,
       COUNT(CASE WHEN t.Food = 'Poor' THEN 1 END) AS Poor
  FROM table1 t
 WHERE t.Date BETWEEN '2018-03-29' AND '2018-03-29'
UNION
SELECT MAX('Behavior') AS Category,
       COUNT(CASE WHEN t.Behavior = 'Excellent' THEN 1 END) AS Excellent,
       COUNT(CASE WHEN t.Behavior = 'VeryGood' THEN 1 END) AS Very_Good,
       COUNT(CASE WHEN t.Behavior = 'Good' THEN 1 END) AS Good,
       COUNT(CASE WHEN t.Behavior = 'Bad' THEN 1 END) AS Bad,
       COUNT(CASE WHEN t.Behavior = 'Poor' THEN 1 END) AS Poor
  FROM table1 t
 WHERE t.Date BETWEEN '2018-03-29' AND '2018-03-29'
UNION
SELECT MAX('Environment') AS Category,
       COUNT(CASE WHEN t.Environment = 'Excellent' THEN 1 END) AS Excellent,
       COUNT(CASE WHEN t.Environment = 'VeryGood' THEN 1 END) AS Very_Good,
       COUNT(CASE WHEN t.Environment = 'Good' THEN 1 END) AS Good,
       COUNT(CASE WHEN t.Environment = 'Bad' THEN 1 END) AS Bad,
       COUNT(CASE WHEN t.Environment = 'Poor' THEN 1 END) AS Poor
  FROM table1 t
 WHERE t.Date BETWEEN '2018-03-29' AND '2018-03-29'

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所以你只是想让人们为你编写解决方案？不是真的，只是想得到查询的提示你到目前为止尝试了什么？从简单开始，然后展开。从“反馈”组中选择“计数（*），方法是使用过多的经验，这样做，但不能在一次中获得所需的输出query@FaizanNaeem看起来不像LINQ？也许我的朋友能帮你？谢谢。通过执行此命令获得所需的输出