Sql 连接两个表,并从第一个表中获取一些列,从第二个表中获取最大时间戳值
我有一张员工桌Sql 连接两个表,并从第一个表中获取一些列,从第二个表中获取最大时间戳值,sql,join,db2,max,left-join,Sql,Join,Db2,Max,Left Join,我有一张员工桌 empid empname status 1 raj active 2 ravi active 3 ramu active 4 dan active 5 sam inactive 我还有一张桌子叫“设施” empid timestamp 1 2014-12-28 1 2015-05-05 1 2015-06-05 2 2015-05-03 2 2015-0
empid empname status
1 raj active
2 ravi active
3 ramu active
4 dan active
5 sam inactive
我还有一张桌子叫“设施”
empid timestamp
1 2014-12-28
1 2015-05-05
1 2015-06-05
2 2015-05-03
2 2015-06-04
3 2015-02-01
我希望我的结果是一样的
empid empname status lastusedts
1 raj active 2015-06-05
2 ravi active 2015-06-04
3 ramu active 2015-02-01
4 dan active null
因此,我必须加入我的employee表和facilities表,并通过获取最大时间戳来查找员工上次使用设施的时间,对于未使用该时间戳的员工,时间戳值应为null,并且只提取活动员工。
请帮助我在db2中编写此查询
SELECT employee.empid, employee.empname, employee.status,facilities.timestamp as lastusedts
FROM employee
INNER JOIN facilities
ON employee.empid=facilities.empid;
使用
分组依据进行左连接
,以查找最大值
(时间戳):
或者,最大时间戳的相关子选择:
select e.empid, e.empname, e.status, max(timestamp) as lastusedts
from employee e
left join facilities f on e.empid = f.empid
where e.status = 'active'
group by e.empid, e.empname, e.status
select e.empid, e.empname, e.status, (select max(timestamp) from facilities f
where e.empid = f.empid) as lastusedts
from employee e
where e.status = 'active'
通用表表达式[CTE]是将问题分解为更简单的块的一种方法
with m as
(
select empid
,max(timestamp) as lastusedts
from facilities
group by e.empid
)
select e.empid
,e.empname
,e.status
,m.lastusedts
from employee e
left join m
on e.empid = m.empid
where e.status = 'active'
通用表表达式[CTE]是将问题分解为更简单的块的一种方法
with m as
(
-- get last timestamp per employee
select empid
,max(timestamp) as lastusedts
from facilities
group by e.empid
)
-- report employee info with last timestamp
select e.empid
,e.empname
,e.status
,m.lastusedts
from employee e
left join m
on e.empid = m.empid
where e.status = 'active'
但是我想要时间戳的最大值(即用户上次使用设施的时间),如果他根本没有使用设施,我应该得到null值,并且我应该只获取活动员工记录select employee.empid,employee.empname,employee.status,max(facilities.timestamp as lastusedts)从员工的内部连接设施。
with m as
(
-- get last timestamp per employee
select empid
,max(timestamp) as lastusedts
from facilities
group by e.empid
)
-- report employee info with last timestamp
select e.empid
,e.empname
,e.status
,m.lastusedts
from employee e
left join m
on e.empid = m.empid
where e.status = 'active'