SQLITE Vlookup在两个不同的表中

我有两个表，其中一个是银行数据，另一个是付款确认，我需要执行查找

我尝试了几个

left join

示例，但未能获得所需的输出。 我正在使用

Sqlite3

请建议

表格-付款详情

Payment_Date    TranNo      RefNo       ChequeNo
11-Nov-19       tran001     ref001      chq001
11-Nov-19       tran001     ref002      chq005
12-Nov-19       tran003     ref003      chq007
13-Nov-19       tran017     ref001      chq005

CustomerID      Payment_No      Match_Status        Payment_date
cust_1      ref003              
cust_2      tran001             
cust_3      ref002              
cust_4      tran019             
cust_5      tran001             
cust_6      chq005              
cust_7      tran019             

CustomerID  Payment_No Match_Status   Payment_date
cust_1      ref003      TRUE          12-Nov-19
cust_2      tran001     TRUE          11-Nov-19
cust_3      ref002      TRUE          11-Nov-19
cust_4      tran019     FALSE         FALSE
cust_5      tran001     TRUE          11-Nov-19
cust_6      chq005      TRUE          11-Nov-19
cust_7      tran019     FALSE         FALSE

表格-付款确认

Payment_Date    TranNo      RefNo       ChequeNo
11-Nov-19       tran001     ref001      chq001
11-Nov-19       tran001     ref002      chq005
12-Nov-19       tran003     ref003      chq007
13-Nov-19       tran017     ref001      chq005

CustomerID      Payment_No      Match_Status        Payment_date
cust_1      ref003              
cust_2      tran001             
cust_3      ref002              
cust_4      tran019             
cust_5      tran001             
cust_6      chq005              
cust_7      tran019             

CustomerID  Payment_No Match_Status   Payment_date
cust_1      ref003      TRUE          12-Nov-19
cust_2      tran001     TRUE          11-Nov-19
cust_3      ref002      TRUE          11-Nov-19
cust_4      tran019     FALSE         FALSE
cust_5      tran001     TRUE          11-Nov-19
cust_6      chq005      TRUE          11-Nov-19
cust_7      tran019     FALSE         FALSE

输出表-付款确认

Payment_Date    TranNo      RefNo       ChequeNo
11-Nov-19       tran001     ref001      chq001
11-Nov-19       tran001     ref002      chq005
12-Nov-19       tran003     ref003      chq007
13-Nov-19       tran017     ref001      chq005

CustomerID      Payment_No      Match_Status        Payment_date
cust_1      ref003              
cust_2      tran001             
cust_3      ref002              
cust_4      tran019             
cust_5      tran001             
cust_6      chq005              
cust_7      tran019             

CustomerID  Payment_No Match_Status   Payment_date
cust_1      ref003      TRUE          12-Nov-19
cust_2      tran001     TRUE          11-Nov-19
cust_3      ref002      TRUE          11-Nov-19
cust_4      tran019     FALSE         FALSE
cust_5      tran001     TRUE          11-Nov-19
cust_6      chq005      TRUE          11-Nov-19
cust_7      tran019     FALSE         FALSE

请尝试以下操作：

表架构：

CREATE TABLE Payment_Details(
  Payment_Date DATETIME,
  TranNo VARCHAR(20),
  RefNo VARCHAR(20),
  ChequeNo VARCHAR(20));

 INSERT INTO Payment_Details VALUES
('11-Nov-19','tran001','ref001','chq001'),
('11-Nov-19','tran001','ref002','chq005'),
('12-Nov-19','tran003','ref003','chq007'),
('13-Nov-19','tran017','ref001','chq005');

 CREATE TABLE Payment_Confirmations(
  CustomerId VARCHAR(20),
  Payment_No VARCHAR(20),
  Match_Status VARCHAR(20),
  Payment_date DATETIME);

INSERT INTO Payment_Confirmations(CustomerId,Payment_No) VALUES
('cust_1','ref003'),
('cust_2','tran001'),
('cust_3','ref002'),
('cust_4','tran019'),
('cust_5','tran001'),
('cust_6','chq005'),
('cust_7','tran019');

SELECT DISTINCT A.CustomerID,
    A.Payment_No,
    CASE WHEN B.ChequeNo IS NULL THEN 'FALSE' ELSE 'TRUE' END Match_Status,
    IFNULL(b.Payment_date,'FALSE') Payment_date
FROM Payment_Confirmations A
LEFT JOIN Payment_Details B ON A.Payment_No=B.TranNo OR A.Payment_No=B.RefNo OR A.Payment_No=B.ChequeNo;

SQL查询：

CREATE TABLE Payment_Details(
  Payment_Date DATETIME,
  TranNo VARCHAR(20),
  RefNo VARCHAR(20),
  ChequeNo VARCHAR(20));

 INSERT INTO Payment_Details VALUES
('11-Nov-19','tran001','ref001','chq001'),
('11-Nov-19','tran001','ref002','chq005'),
('12-Nov-19','tran003','ref003','chq007'),
('13-Nov-19','tran017','ref001','chq005');

 CREATE TABLE Payment_Confirmations(
  CustomerId VARCHAR(20),
  Payment_No VARCHAR(20),
  Match_Status VARCHAR(20),
  Payment_date DATETIME);

INSERT INTO Payment_Confirmations(CustomerId,Payment_No) VALUES
('cust_1','ref003'),
('cust_2','tran001'),
('cust_3','ref002'),
('cust_4','tran019'),
('cust_5','tran001'),
('cust_6','chq005'),
('cust_7','tran019');

SELECT DISTINCT A.CustomerID,
    A.Payment_No,
    CASE WHEN B.ChequeNo IS NULL THEN 'FALSE' ELSE 'TRUE' END Match_Status,
    IFNULL(b.Payment_date,'FALSE') Payment_date
FROM Payment_Confirmations A
LEFT JOIN Payment_Details B ON A.Payment_No=B.TranNo OR A.Payment_No=B.RefNo OR A.Payment_No=B.ChequeNo;

---

检查中的结果，因此，基本上，您需要检查

Payment\u Confirmation

中的

Payment\u No

是否与

ranNo

或

RefNo

或

ChequeNo

匹配，然后更新状态和提取日期。。谢谢您的

付款编号
栏为什么同时包含交易编号和参考编号？那没有多大意义。这些是不同的东西，它们应该在不同的列中。@Tomalak，Payment\u No可以有3个refno或tran No或check No，也请注意相同的Payment\u No值可以用于多个客户。。。cust_2和cust_5感谢Dinesh、、tran001对不同的客户使用了2次，客户总数为7…您的查询创建了2行。对于trann001的同一客户……客户2 tran001于2019年11月11日生效…………客户2 tran001于2019年11月11日生效。。cust_5 tran001输入正确。。。。。。不存在…并向上移动了1个单元格，因此状态显示到客户6。。。。