Sql 如何在oracle select中按等级或秒获取第一个值

我使用

rank（）对（按ASC按顺序划分）

Function进行排名。它工作得很好。但是，如果特定的

应用程序id

的最大rnk值为1，则我需要取1stfalue，否则2nd1

表是这样的

  APPLICATION_ID    |  EMP_CODE   | DATE_ACTION   | ACTION_ID
----------------------------------------------------------------
    24744           |  110147     | 2016-09-13    | -1
    24746           |  162286     | 2016-09-12    |  0 

我的选择如下：

SELECT APPLICATION_ID,EMP_CODE,DATE_ACTION,ACTION_ID,
           rank() OVER (PARTITION BY APPLICATION_ID
                  ORDER BY DATE_ACTION ASC) as rnk
FROM TABLE WHERE ACTION_ID = -1

结果是：

RNK  | APPLICATION_ID    |  EMP_CODE   | DATE_ACTION   | ACTION_ID
------------------------------------------------------------
1    | 53207             | 260829      | 2020-03-03    | -1
2    | 53207             | 161938      | 2020-03-03    | -1
3    | 53207             | 161938      | 2020-03-03    | -1
1    | 51372             | 163668      | 2020-03-04    | -1
1    | 52819             | 260829      | 2020-03-02    | -1
2    | 52819             | 161938      | 2020-03-02    | -1
3    | 52819             | 161938      | 2020-03-02    | -1
4    | 52819             | 161938      | 2020-03-02    | -1

但结果应该是这样的：

RNK  | APPLICATION_ID    |  EMP_CODE   | DATE_ACTION   | ACTION_ID
------------------------------------------------------------
2    | 53207             | 161938      | 2020-03-03    | -1
1    | 51372             | 163668      | 2020-03-04    | -1
2    | 52819             | 161938      | 2020-03-02    | -1

SELECT t.APPLICATION_ID, t.EMP_CODE, t.DATE_ACTION, t.ACTION_ID
FROM (
  SELECT APPLICATION_ID,EMP_CODE,DATE_ACTION,ACTION_ID,
    RANK() OVER (PARTITION BY APPLICATION_ID ORDER BY DATE_ACTION DESC) as rnk,
    COUNT(*) OVER (PARTITION BY APPLICATION_ID) counter
  FROM tablename WHERE ACTION_ID = -1
) t
WHERE t.rnk = CASE WHEN t.counter = 1 THEN 1 ELSE 2 END

您可以像这样使用

COUNT（）

分析函数：

RNK  | APPLICATION_ID    |  EMP_CODE   | DATE_ACTION   | ACTION_ID
------------------------------------------------------------
2    | 53207             | 161938      | 2020-03-03    | -1
1    | 51372             | 163668      | 2020-03-04    | -1
2    | 52819             | 161938      | 2020-03-02    | -1

SELECT t.APPLICATION_ID, t.EMP_CODE, t.DATE_ACTION, t.ACTION_ID
FROM (
  SELECT APPLICATION_ID,EMP_CODE,DATE_ACTION,ACTION_ID,
    RANK() OVER (PARTITION BY APPLICATION_ID ORDER BY DATE_ACTION DESC) as rnk,
    COUNT(*) OVER (PARTITION BY APPLICATION_ID) counter
  FROM tablename WHERE ACTION_ID = -1
) t
WHERE t.rnk = CASE WHEN t.counter = 1 THEN 1 ELSE 2 END

---

更新了我的问题。我只是把我的查询结果放在这里。检查我的答案。