SQL-数据已分组时运行总计

我正在尝试对一些数据进行汇总，并且已经看到了简单的方法。然而，我已经对一些数据进行了分组，这是我的代码。我目前有日期和付款类型，以及与之相关的总额

我目前的情况是：

create table #testdata
(
mdate date,
pmttype varchar(64),
totalpmtamt int
)

insert into #testdata
select getdate()-7, 'DD', 10
union
select getdate() -7, 'SO', 12
union
select getdate()-6, 'DD', 3
union
select getdate()-5, 'DD', 13
union
select getdate()-5, 'SO', 23
union
select getdate()-5, 'PO', 8

我想要的是：

mdate       |  paymenttype  |  totalpmtamt  |  incrtotal
2016-08-29  |  DD           |  10           |  10
2016-08-29  |  SO           |  12           |  22
2016-08-30  |  DD           |  3            |  25
2016-08-31  |  DD           |  13           |  38
2016-08-31  |  SO           |  8            |  46
2016-08-31  |  PO           |  23           |  69

我尝试将我在此处找到的其他代码改编为：

select  t1.mdate, 
        t1.pmttype,
        t1.totalpmtamt, 
        SUM(t2.totalpmtamt) as runningsum
     from #testdata t1
join #testdata t2 on t1.mdate >= t2.mdate and t1.pmttype >= t2.pmttype
group by t1.mdate, t1.pmttype, t1.totalpmtamt
order by t1.mdate

但我得到的只是

mdate       |  paymenttype  |  totalpmtamt  |  incrtotal
2016-08-29  |  DD           |  10           |  10
2016-08-29  |  SO           |  12           |  22
2016-08-30  |  DD           |  3            |  13
2016-08-31  |  DD           |  13           |  26
2016-08-31  |  SO           |  8            |  34
2016-08-31  |  PO           |  23           |  69

---

有人能帮忙吗？

ANSI计算累计总和的标准方法是：

select t.*, sum(totalpmtamt) over (order by mdate) as runningsum
from #testdata t
order by t.mdate;

并非所有数据库都支持此功能

如果您的数据库不支持该功能，我将使用相关子查询：

select t.*,
       (select sum(t2.totalpmtamt)
        from #testdata t2
        where t2.mdate <= t.mdate
       ) as runningsum
from #testdata
order by t.mdate;

---

ANSI累积求和的标准方法是：

select t.*, sum(totalpmtamt) over (order by mdate) as runningsum
from #testdata t
order by t.mdate;

并非所有数据库都支持此功能

如果您的数据库不支持该功能，我将使用相关子查询：

select t.*,
       (select sum(t2.totalpmtamt)
        from #testdata t2
        where t2.mdate <= t.mdate
       ) as runningsum
from #testdata
order by t.mdate;

---

使用下面的查询获得SQL Server所需的结果

with cte_1
     as
     (SELECT *,ROW_NUMBER() OVER(order by mdate  ) RNO
     FROM #testdata)
     SELECT mdate,pmttype,totalpmtamt,(select sum(c2.totalpmtamt)
        from cte_1 c2
        where c2.RNO <= c1.RNO
       ) as incrtotal
     FROM cte_1 c1

DECLARE @testdata TABLE
    (
      mdate DATE ,
      pmttype VARCHAR(64) ,
      totalpmtamt INT
    );

INSERT  INTO @testdata
        ( mdate, pmttype, totalpmtamt )
VALUES  ( GETDATE() - 7, 'DD', 10 ),
        ( GETDATE() - 7, 'SO', 12 ),
        ( GETDATE() - 6, 'DD', 3 ),
        ( GETDATE() - 5, 'DD', 13 ),
        ( GETDATE() - 5, 'SO', 23 ),
        ( GETDATE() - 5, 'PO', 8 );

SELECT  *,
        SUM(totalpmtamt) OVER ( ORDER BY mdate ROWS UNBOUNDED PRECEDING )
        AS RunningTotal
FROM    @testdata t;

输出：

---

使用下面的查询获得SQL Server所需的结果

with cte_1
     as
     (SELECT *,ROW_NUMBER() OVER(order by mdate  ) RNO
     FROM #testdata)
     SELECT mdate,pmttype,totalpmtamt,(select sum(c2.totalpmtamt)
        from cte_1 c2
        where c2.RNO <= c1.RNO
       ) as incrtotal
     FROM cte_1 c1

DECLARE @testdata TABLE
    (
      mdate DATE ,
      pmttype VARCHAR(64) ,
      totalpmtamt INT
    );

INSERT  INTO @testdata
        ( mdate, pmttype, totalpmtamt )
VALUES  ( GETDATE() - 7, 'DD', 10 ),
        ( GETDATE() - 7, 'SO', 12 ),
        ( GETDATE() - 6, 'DD', 3 ),
        ( GETDATE() - 5, 'DD', 13 ),
        ( GETDATE() - 5, 'SO', 23 ),
        ( GETDATE() - 5, 'PO', 8 );

SELECT  *,
        SUM(totalpmtamt) OVER ( ORDER BY mdate ROWS UNBOUNDED PRECEDING )
        AS RunningTotal
FROM    @testdata t;

输出：

---

听起来像SQL Server

with cte_1
     as
     (SELECT *,ROW_NUMBER() OVER(order by mdate  ) RNO
     FROM #testdata)
     SELECT mdate,pmttype,totalpmtamt,(select sum(c2.totalpmtamt)
        from cte_1 c2
        where c2.RNO <= c1.RNO
       ) as incrtotal
     FROM cte_1 c1

DECLARE @testdata TABLE
    (
      mdate DATE ,
      pmttype VARCHAR(64) ,
      totalpmtamt INT
    );

INSERT  INTO @testdata
        ( mdate, pmttype, totalpmtamt )
VALUES  ( GETDATE() - 7, 'DD', 10 ),
        ( GETDATE() - 7, 'SO', 12 ),
        ( GETDATE() - 6, 'DD', 3 ),
        ( GETDATE() - 5, 'DD', 13 ),
        ( GETDATE() - 5, 'SO', 23 ),
        ( GETDATE() - 5, 'PO', 8 );

SELECT  *,
        SUM(totalpmtamt) OVER ( ORDER BY mdate ROWS UNBOUNDED PRECEDING )
        AS RunningTotal
FROM    @testdata t;

---

听起来像SQL Server

with cte_1
     as
     (SELECT *,ROW_NUMBER() OVER(order by mdate  ) RNO
     FROM #testdata)
     SELECT mdate,pmttype,totalpmtamt,(select sum(c2.totalpmtamt)
        from cte_1 c2
        where c2.RNO <= c1.RNO
       ) as incrtotal
     FROM cte_1 c1

DECLARE @testdata TABLE
    (
      mdate DATE ,
      pmttype VARCHAR(64) ,
      totalpmtamt INT
    );

INSERT  INTO @testdata
        ( mdate, pmttype, totalpmtamt )
VALUES  ( GETDATE() - 7, 'DD', 10 ),
        ( GETDATE() - 7, 'SO', 12 ),
        ( GETDATE() - 6, 'DD', 3 ),
        ( GETDATE() - 5, 'DD', 13 ),
        ( GETDATE() - 5, 'SO', 23 ),
        ( GETDATE() - 5, 'PO', 8 );

SELECT  *,
        SUM(totalpmtamt) OVER ( ORDER BY mdate ROWS UNBOUNDED PRECEDING )
        AS RunningTotal
FROM    @testdata t;

---

用你正在使用的数据库标记你的问题。你可以使用更简单的值。。。在创建示例数据时。使用正在使用的数据库标记您的问题。您可以使用更简单的值。。。在创建示例数据时。我对您的条目进行了投票，但您应该按mdate排序，而不是选择1。@cetin yes。UpdatedI更新了您的条目，但您应该按mdate排序，而不是选择1。@cetin yes。更新了汉克斯·戈登。我将pmtttype添加到overorderbymdate中，它按单独的行进行分解，而不仅仅是将日期分组在一起。工作得像个骗子汉克斯·戈登。我将pmtttype添加到overorderbymdate中，它按单独的行进行分解，而不仅仅是将日期分组在一起。工作得很有魅力