Sql 显示每周总数

我正在尝试创建一个报告，显示一周内使用的总时间。我仅成功地使用以下公式显示了每日使用的总量：

select left(report_date, 11) as week_start,
       case
         when id is null then
          'Enterprise'
         else
          id
       end id,
       case
         when id in ('CN','NQ','AR','DA','PR','FM') then
          'West'
         when id = 'Enterprise' then
          'ALL'
         else
          'East'
       end as Region,
       sum(actual_seconds) / 3600 as Actual_Hours,
       sum(goal_seconds) / 3600 as Goal_Hours,
       sum(goal_seconds * 1.0) / nullif(sum(actual_seconds * 1.0), 0) * 100 as Performance
  from summary_table
 where report_date > '2019-01-01 00:00:00.000'
 group by rollup(id), report_date
 order by report_date

如果可能的话，我还想知道“东”和“西”的总数

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任何帮助都将不胜感激，提前谢谢

我能够按周进行总结，但按地区添加总数仍然存在问题

Select
    dateadd(day, -(datepart(weekday, report_date) + 6 ) % 7, report_date) as week_start, 
   case
         when id is null then
          'Enterprise'
         else
          id
       end id,
       case
         when id in ('CN','NQ','AR','DA','PR','FM') then
          'West'
         when id = 'Enterprise' then
          'ALL'
         else
          'East'
       end as Region,  
        sum(actual_seconds)/3600.0 as Actual_Hours,
        sum(goal_seconds)/3600.0 as Goal_Hours,
        sum(goal_seconds*1.0)/NULLIF(sum(actual_seconds*1.0),0)*100 as performance 
    from     summary_table
    where        dateadd(day, -(datepart(weekday, report_date) + 6 ) % 7, report_date) >= 
                      dateadd(day, -365 - datepart(dw, getdate()), getdate())
    group by    dateadd(day, -(datepart(weekday, report_date) + 6 ) % 7, report_date), rollup(id)

---

我能够按周进行总结，但在按地区添加总数时仍然存在问题

Select
    dateadd(day, -(datepart(weekday, report_date) + 6 ) % 7, report_date) as week_start, 
   case
         when id is null then
          'Enterprise'
         else
          id
       end id,
       case
         when id in ('CN','NQ','AR','DA','PR','FM') then
          'West'
         when id = 'Enterprise' then
          'ALL'
         else
          'East'
       end as Region,  
        sum(actual_seconds)/3600.0 as Actual_Hours,
        sum(goal_seconds)/3600.0 as Goal_Hours,
        sum(goal_seconds*1.0)/NULLIF(sum(actual_seconds*1.0),0)*100 as performance 
    from     summary_table
    where        dateadd(day, -(datepart(weekday, report_date) + 6 ) % 7, report_date) >= 
                      dateadd(day, -365 - datepart(dw, getdate()), getdate())
    group by    dateadd(day, -(datepart(weekday, report_date) + 6 ) % 7, report_date), rollup(id)

---

将您的

区域表达式添加到
分组依据
？我尝试过，但似乎没有任何效果…按周数分组可以工作->日期部分（周，报告日期）作为周否？我会将区域（还没有做任何数学）添加到子查询中，然后在外部查询中进行数学运算，然后您应该能够按区域分组。但奇怪的是，现在按它分组是如何不起作用的呢？欢迎来到堆栈溢出！一些示例数据和基于该示例的预期结果将非常有用。将您的
区域
表达式添加到
分组依据
？我尝试了此方法，但似乎没有任何效果…按周数分组可以工作->日期部分（周，报告日期）作为周号？我会添加区域（还没有做任何数学计算）到子查询，然后在外部查询中进行计算，然后您应该能够按区域分组。但奇怪的是，现在按它分组是如何不起作用的呢？欢迎来到堆栈溢出！一些样本数据和基于该样本的预期结果将非常有用。