Sql 在多列选择中求和1列

我试图对select查询中的quantity字段求和（）并按日期值对它们进行分组，但Sql不断给我错误，说不是所有列都在我的GroupBy中分组，而是我只想按日期对它们进行分组

这是我的疑问：

SELECT   Date, Clave_PDV, Che, Lin, Dish, Dish_Name, Type, 
sum(Quantity) as Quant, Price, Total, Tur, Tur_Name, Group, 
Group_Name, Pdv_Name, St_Pla, St_Che
FROM  Dish_Sales
GROUP BY Date

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如何按日期对它们进行分组求和（数量）？

您将删除所有不需要的列：

SELECT Date, sum(Quantity) as Quant
FROM Dish_Sales
GROUP BY Date;

---

您将删除所有不需要的列：

SELECT Date, sum(Quantity) as Quant
FROM Dish_Sales
GROUP BY Date;

---

如果你想在日期前得到这笔钱，你应该告诉我们

SELECT   Date, sum(Quantity) as Quant
FROM  Dish_Sales
GROUP BY Date

否则，应将group by用于所有未聚合的列

SELECT   Date, Clave_PDV, Che, Lin, Dish, Dish_Name, Type, 
sum(Quantity) as Quant, Price, Total, Tur, Tur_Name, Group, 
Group_Name, Pdv_Name, St_Pla, St_Che
FROM  Dish_Sales
GROUP BY Date, Clave_PDV, Che, Lin, Dish, Dish_Name, Type, 
     Price, Total, Tur, Tur_Name, Group, 
      Group_Name, Pdv_Name, St_Pla, St_Che

---

如果你想在日期前得到这笔钱，你应该告诉我们

SELECT   Date, sum(Quantity) as Quant
FROM  Dish_Sales
GROUP BY Date

否则，应将group by用于所有未聚合的列

SELECT   Date, Clave_PDV, Che, Lin, Dish, Dish_Name, Type, 
sum(Quantity) as Quant, Price, Total, Tur, Tur_Name, Group, 
Group_Name, Pdv_Name, St_Pla, St_Che
FROM  Dish_Sales
GROUP BY Date, Clave_PDV, Che, Lin, Dish, Dish_Name, Type, 
     Price, Total, Tur, Tur_Name, Group, 
      Group_Name, Pdv_Name, St_Pla, St_Che

---

我只想按日期对它们进行分组

，那么您应该如何选择

Che

或

Lin

的值，例如？显示不属于聚合的列是没有意义的。在这种情况下显示哪一行？

我只想按日期对它们进行分组，那么您应该如何选择
Che
或
Lin
的值呢？例如，显示不属于聚合的列是没有意义的。在这种情况下显示哪一行？