Sql 以升序获取连接的行

可能重复：

脚本：-

CREATE TABLE Category (
  ID int,
  ErrorMessage nvarchar(200)
)


INSERT INTO Category 
  (ID, ErrorMessage)
VALUES
  (1, 'efgh')

INSERT INTO Category 
  (ID, ErrorMessage)
VALUES
  (1, 'abcd')

INSERT INTO Category 
  (ID, ErrorMessage)
VALUES
  (1, 'ijkl')

INSERT INTO Category 
  (ID, ErrorMessage)
VALUES
  (2, 'efgh')

INSERT INTO Category 
  (ID, ErrorMessage)
VALUES
  (2, 'abcd')

INSERT INTO Category 
  (ID, ErrorMessage)
VALUES
  (2, 'ijkl')

预期产量

Id                 ErrorMessage
----------------------------------
1                  abcd,efgh,ijkl
2                  abcd,efgh,ijkl

---

请注意，类别ID已分组，以逗号分隔的消息按升序排列。

您可以在不使用XML类型和值提取的情况下获得XML实体化您可以在不使用XML类型和值提取的情况下获得XML实体化

Select C.Id
    , Stuff(
        (
        Select ', ' + C1.ErrorMessage
        From Category As C1
        Where C1.Id = C.Id
        Order By C1.ErrorMessage
        For Xml Path('')
        ), 1, 2, '') As Categories
From Category As C
Group By C.Id

select A.ID, STUFF((
    select ','+B.ErrorMessage
    from Category B
    where B.ID = A.ID
    order by B.ErrorMessage
    for xml path ('a'), type).value('.','nvarchar(max)'),1,1,'')
from Category A
group by A.ID
order by A.ID