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如何使用SQL知道一个月内剩余的周一、周二、周三……和周日的数量?_Sql_Datetime_Weekday - Fatal编程技术网

如何使用SQL知道一个月内剩余的周一、周二、周三……和周日的数量?

如何使用SQL知道一个月内剩余的周一、周二、周三……和周日的数量?,sql,datetime,weekday,Sql,Datetime,Weekday,我想更新具有日期列的行的值,并且我想生成该月的RemainingMondays、RemainingTuesdays等列值。 例如,如果我有2019-03-20(2019年3月20日),我需要用下一列值更新该行。RemainingMondays->2,RemainingTuesdays->1,Remaining周三->1,RemainingUrsday->2,RemainingFridays->2,RemainingSaturdays->2,RemainingSundays->2,(如您所见)我不

我想更新具有日期列的行的值,并且我想生成该月的RemainingMondays、RemainingTuesdays等列值。
例如,如果我有2019-03-20(2019年3月20日),我需要用下一列值更新该行。RemainingMondays->2,RemainingTuesdays->1,Remaining周三->1,RemainingUrsday->2,RemainingFridays->2,RemainingSaturdays->2,RemainingSundays->2,(如您所见)我不想计算当天的工作日(这意味着在一个月的最后一天,所有列值都将为0)。如何在SQL中实现这一点

我用MySQL测试了这个解决方案,但它应该可以在任何SQL引擎中运行

测试数据:

CREATE TABLE test_date (
  date date NOT NULL
);

INSERT INTO test_date VALUES
('2019-03-01'),
('2019-03-20'),
('2019-03-21'),
('2019-03-22'),
('2019-03-23'),
('2019-03-24'),
('2019-03-25'),
('2019-03-26');
用于获取数据的查询:

SELECT 
    td2.date,
    /* 
    To calculate remaining of a weekday, you can then use this formula:

    if desired_week_day_number > week_day_number
       and desired_week_day_number <= (week_day_number + remaining_days_after_weeks):
        remaining_weeks + 1
    elseif desired_week_day_number <= (week_day_number + remaining_days_after_weeks - 7):
        remaining_weeks + 1
    else remaining_weeks
    */
    CASE WHEN (1 > td2.week_day_number AND 1 <= (td2.week_day_number + td2.remaining_days_after_weeks))
              OR 1 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
         THEN td2.remaining_weeks + 1
         ELSE td2.remaining_weeks
    END remaining_sundays,
    CASE WHEN (2 > td2.week_day_number AND 2 <= (td2.week_day_number + td2.remaining_days_after_weeks))
              OR 2 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
         THEN td2.remaining_weeks + 1
         ELSE td2.remaining_weeks
    END remaining_mondays,
    CASE WHEN (3 > td2.week_day_number AND 3 <= (td2.week_day_number + td2.remaining_days_after_weeks))
              OR 3 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
         THEN td2.remaining_weeks + 1
         ELSE td2.remaining_weeks
    END remaining_tuesdays,
    CASE WHEN (4 > td2.week_day_number AND 4 <= (td2.week_day_number + td2.remaining_days_after_weeks))
              OR 4 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
         THEN td2.remaining_weeks + 1
         ELSE td2.remaining_weeks
    END remaining_wednesdays,
    CASE WHEN (5 > td2.week_day_number AND 5 <= (td2.week_day_number + td2.remaining_days_after_weeks))
              OR 5 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
         THEN td2.remaining_weeks + 1
         ELSE td2.remaining_weeks
    END remaining_thursdays, 
    CASE WHEN (6 > td2.week_day_number AND 6 <= (td2.week_day_number + td2.remaining_days_after_weeks))
              OR 6 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
         THEN td2.remaining_weeks + 1
         ELSE td2.remaining_weeks
    END remaining_fridays,
    CASE WHEN (7 > td2.week_day_number AND 7 <= (td2.week_day_number + td2.remaining_days_after_weeks))
              OR 7 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
         THEN td2.remaining_weeks + 1
         ELSE td2.remaining_weeks
    END remaining_saturdays,
    td2.*
FROM (
    SELECT
        td.date,
        day(td.date) day_number,
        dayofweek(td.date) week_day_number,
        dayname(td.date) week_day_name,
        day(last_day(td.date)) nb_month_days,
        day(last_day(td.date)) - day(td.date) remaining_days,
        floor((day(last_day(td.date)) - day(td.date)) / 7) remaining_weeks,
        day(last_day(td.date)) - day(td.date) -
            floor((day(last_day(td.date)) - day(td.date)) / 7) * 7 remaining_days_after_weeks
    FROM test_date td
) AS td2
ORDER BY td2.date;
选择
td2.1日期,
/* 
要计算工作日的剩余时间,可以使用以下公式:
如果需要,周日号>周日号

我用MySQL测试了这个解决方案,但是它应该可以在任何SQL引擎中运行

测试数据:

CREATE TABLE test_date (
  date date NOT NULL
);

INSERT INTO test_date VALUES
('2019-03-01'),
('2019-03-20'),
('2019-03-21'),
('2019-03-22'),
('2019-03-23'),
('2019-03-24'),
('2019-03-25'),
('2019-03-26');
用于获取数据的查询:

SELECT 
    td2.date,
    /* 
    To calculate remaining of a weekday, you can then use this formula:

    if desired_week_day_number > week_day_number
       and desired_week_day_number <= (week_day_number + remaining_days_after_weeks):
        remaining_weeks + 1
    elseif desired_week_day_number <= (week_day_number + remaining_days_after_weeks - 7):
        remaining_weeks + 1
    else remaining_weeks
    */
    CASE WHEN (1 > td2.week_day_number AND 1 <= (td2.week_day_number + td2.remaining_days_after_weeks))
              OR 1 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
         THEN td2.remaining_weeks + 1
         ELSE td2.remaining_weeks
    END remaining_sundays,
    CASE WHEN (2 > td2.week_day_number AND 2 <= (td2.week_day_number + td2.remaining_days_after_weeks))
              OR 2 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
         THEN td2.remaining_weeks + 1
         ELSE td2.remaining_weeks
    END remaining_mondays,
    CASE WHEN (3 > td2.week_day_number AND 3 <= (td2.week_day_number + td2.remaining_days_after_weeks))
              OR 3 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
         THEN td2.remaining_weeks + 1
         ELSE td2.remaining_weeks
    END remaining_tuesdays,
    CASE WHEN (4 > td2.week_day_number AND 4 <= (td2.week_day_number + td2.remaining_days_after_weeks))
              OR 4 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
         THEN td2.remaining_weeks + 1
         ELSE td2.remaining_weeks
    END remaining_wednesdays,
    CASE WHEN (5 > td2.week_day_number AND 5 <= (td2.week_day_number + td2.remaining_days_after_weeks))
              OR 5 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
         THEN td2.remaining_weeks + 1
         ELSE td2.remaining_weeks
    END remaining_thursdays, 
    CASE WHEN (6 > td2.week_day_number AND 6 <= (td2.week_day_number + td2.remaining_days_after_weeks))
              OR 6 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
         THEN td2.remaining_weeks + 1
         ELSE td2.remaining_weeks
    END remaining_fridays,
    CASE WHEN (7 > td2.week_day_number AND 7 <= (td2.week_day_number + td2.remaining_days_after_weeks))
              OR 7 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
         THEN td2.remaining_weeks + 1
         ELSE td2.remaining_weeks
    END remaining_saturdays,
    td2.*
FROM (
    SELECT
        td.date,
        day(td.date) day_number,
        dayofweek(td.date) week_day_number,
        dayname(td.date) week_day_name,
        day(last_day(td.date)) nb_month_days,
        day(last_day(td.date)) - day(td.date) remaining_days,
        floor((day(last_day(td.date)) - day(td.date)) / 7) remaining_weeks,
        day(last_day(td.date)) - day(td.date) -
            floor((day(last_day(td.date)) - day(td.date)) / 7) * 7 remaining_days_after_weeks
    FROM test_date td
) AS td2
ORDER BY td2.date;
选择
td2.1日期,
/* 
要计算工作日的剩余时间,可以使用以下公式:
如果需要,周日号>周日号

欢迎来到SO。请阅读。使用适当的数据库平台标记,并显示您尝试了什么。这将取决于您使用的数据库引擎。请使用您的DBMS标记问题。欢迎使用SO。请阅读。使用适当的数据库平台标记,并显示您尝试了什么。这将取决于您使用的数据库引擎。请使用您的DBMS标记问题。