如何使用SQL知道一个月内剩余的周一、周二、周三……和周日的数量?
我想更新具有日期列的行的值,并且我想生成该月的RemainingMondays、RemainingTuesdays等列值。如何使用SQL知道一个月内剩余的周一、周二、周三……和周日的数量?,sql,datetime,weekday,Sql,Datetime,Weekday,我想更新具有日期列的行的值,并且我想生成该月的RemainingMondays、RemainingTuesdays等列值。 例如,如果我有2019-03-20(2019年3月20日),我需要用下一列值更新该行。RemainingMondays->2,RemainingTuesdays->1,Remaining周三->1,RemainingUrsday->2,RemainingFridays->2,RemainingSaturdays->2,RemainingSundays->2,(如您所见)我不
例如,如果我有2019-03-20(2019年3月20日),我需要用下一列值更新该行。RemainingMondays->2,RemainingTuesdays->1,Remaining周三->1,RemainingUrsday->2,RemainingFridays->2,RemainingSaturdays->2,RemainingSundays->2,(如您所见)我不想计算当天的工作日(这意味着在一个月的最后一天,所有列值都将为0)。如何在SQL中实现这一点 我用MySQL测试了这个解决方案,但它应该可以在任何SQL引擎中运行 测试数据:
CREATE TABLE test_date (
date date NOT NULL
);
INSERT INTO test_date VALUES
('2019-03-01'),
('2019-03-20'),
('2019-03-21'),
('2019-03-22'),
('2019-03-23'),
('2019-03-24'),
('2019-03-25'),
('2019-03-26');
用于获取数据的查询:
SELECT
td2.date,
/*
To calculate remaining of a weekday, you can then use this formula:
if desired_week_day_number > week_day_number
and desired_week_day_number <= (week_day_number + remaining_days_after_weeks):
remaining_weeks + 1
elseif desired_week_day_number <= (week_day_number + remaining_days_after_weeks - 7):
remaining_weeks + 1
else remaining_weeks
*/
CASE WHEN (1 > td2.week_day_number AND 1 <= (td2.week_day_number + td2.remaining_days_after_weeks))
OR 1 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
THEN td2.remaining_weeks + 1
ELSE td2.remaining_weeks
END remaining_sundays,
CASE WHEN (2 > td2.week_day_number AND 2 <= (td2.week_day_number + td2.remaining_days_after_weeks))
OR 2 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
THEN td2.remaining_weeks + 1
ELSE td2.remaining_weeks
END remaining_mondays,
CASE WHEN (3 > td2.week_day_number AND 3 <= (td2.week_day_number + td2.remaining_days_after_weeks))
OR 3 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
THEN td2.remaining_weeks + 1
ELSE td2.remaining_weeks
END remaining_tuesdays,
CASE WHEN (4 > td2.week_day_number AND 4 <= (td2.week_day_number + td2.remaining_days_after_weeks))
OR 4 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
THEN td2.remaining_weeks + 1
ELSE td2.remaining_weeks
END remaining_wednesdays,
CASE WHEN (5 > td2.week_day_number AND 5 <= (td2.week_day_number + td2.remaining_days_after_weeks))
OR 5 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
THEN td2.remaining_weeks + 1
ELSE td2.remaining_weeks
END remaining_thursdays,
CASE WHEN (6 > td2.week_day_number AND 6 <= (td2.week_day_number + td2.remaining_days_after_weeks))
OR 6 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
THEN td2.remaining_weeks + 1
ELSE td2.remaining_weeks
END remaining_fridays,
CASE WHEN (7 > td2.week_day_number AND 7 <= (td2.week_day_number + td2.remaining_days_after_weeks))
OR 7 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
THEN td2.remaining_weeks + 1
ELSE td2.remaining_weeks
END remaining_saturdays,
td2.*
FROM (
SELECT
td.date,
day(td.date) day_number,
dayofweek(td.date) week_day_number,
dayname(td.date) week_day_name,
day(last_day(td.date)) nb_month_days,
day(last_day(td.date)) - day(td.date) remaining_days,
floor((day(last_day(td.date)) - day(td.date)) / 7) remaining_weeks,
day(last_day(td.date)) - day(td.date) -
floor((day(last_day(td.date)) - day(td.date)) / 7) * 7 remaining_days_after_weeks
FROM test_date td
) AS td2
ORDER BY td2.date;
选择
td2.1日期,
/*
要计算工作日的剩余时间,可以使用以下公式:
如果需要,周日号>周日号
我用MySQL测试了这个解决方案,但是它应该可以在任何SQL引擎中运行
测试数据:
CREATE TABLE test_date (
date date NOT NULL
);
INSERT INTO test_date VALUES
('2019-03-01'),
('2019-03-20'),
('2019-03-21'),
('2019-03-22'),
('2019-03-23'),
('2019-03-24'),
('2019-03-25'),
('2019-03-26');
用于获取数据的查询:
SELECT
td2.date,
/*
To calculate remaining of a weekday, you can then use this formula:
if desired_week_day_number > week_day_number
and desired_week_day_number <= (week_day_number + remaining_days_after_weeks):
remaining_weeks + 1
elseif desired_week_day_number <= (week_day_number + remaining_days_after_weeks - 7):
remaining_weeks + 1
else remaining_weeks
*/
CASE WHEN (1 > td2.week_day_number AND 1 <= (td2.week_day_number + td2.remaining_days_after_weeks))
OR 1 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
THEN td2.remaining_weeks + 1
ELSE td2.remaining_weeks
END remaining_sundays,
CASE WHEN (2 > td2.week_day_number AND 2 <= (td2.week_day_number + td2.remaining_days_after_weeks))
OR 2 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
THEN td2.remaining_weeks + 1
ELSE td2.remaining_weeks
END remaining_mondays,
CASE WHEN (3 > td2.week_day_number AND 3 <= (td2.week_day_number + td2.remaining_days_after_weeks))
OR 3 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
THEN td2.remaining_weeks + 1
ELSE td2.remaining_weeks
END remaining_tuesdays,
CASE WHEN (4 > td2.week_day_number AND 4 <= (td2.week_day_number + td2.remaining_days_after_weeks))
OR 4 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
THEN td2.remaining_weeks + 1
ELSE td2.remaining_weeks
END remaining_wednesdays,
CASE WHEN (5 > td2.week_day_number AND 5 <= (td2.week_day_number + td2.remaining_days_after_weeks))
OR 5 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
THEN td2.remaining_weeks + 1
ELSE td2.remaining_weeks
END remaining_thursdays,
CASE WHEN (6 > td2.week_day_number AND 6 <= (td2.week_day_number + td2.remaining_days_after_weeks))
OR 6 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
THEN td2.remaining_weeks + 1
ELSE td2.remaining_weeks
END remaining_fridays,
CASE WHEN (7 > td2.week_day_number AND 7 <= (td2.week_day_number + td2.remaining_days_after_weeks))
OR 7 <= (td2.week_day_number + td2.remaining_days_after_weeks - 7)
THEN td2.remaining_weeks + 1
ELSE td2.remaining_weeks
END remaining_saturdays,
td2.*
FROM (
SELECT
td.date,
day(td.date) day_number,
dayofweek(td.date) week_day_number,
dayname(td.date) week_day_name,
day(last_day(td.date)) nb_month_days,
day(last_day(td.date)) - day(td.date) remaining_days,
floor((day(last_day(td.date)) - day(td.date)) / 7) remaining_weeks,
day(last_day(td.date)) - day(td.date) -
floor((day(last_day(td.date)) - day(td.date)) / 7) * 7 remaining_days_after_weeks
FROM test_date td
) AS td2
ORDER BY td2.date;
选择
td2.1日期,
/*
要计算工作日的剩余时间,可以使用以下公式:
如果需要,周日号>周日号
欢迎来到SO。请阅读。使用适当的数据库平台标记,并显示您尝试了什么。这将取决于您使用的数据库引擎。请使用您的DBMS标记问题。欢迎使用SO。请阅读。使用适当的数据库平台标记,并显示您尝试了什么。这将取决于您使用的数据库引擎。请使用您的DBMS标记问题。