Sql 从具有不同关键字的同一列复制列中的值
我在博士后有下表Sql 从具有不同关键字的同一列复制列中的值,sql,postgresql,Sql,Postgresql,我在博士后有下表 id | col1 |col2 |col3 |col4 66 | AfBLy_2_d1_1 | Sample |6798 | Day 1 67 | AfBLy_2_d1_6 | Sample |8798 | Day 2 66 | AfBLy_2_d1_4 | Sample |6776 | Day 7 69 | AfBLy_2_d1_9 | Sample |6789 | Day 5 66 | AfBLy_2_d1_1 | Sampl
id | col1 |col2 |col3 |col4
66 | AfBLy_2_d1_1 | Sample |6798 | Day 1
67 | AfBLy_2_d1_6 | Sample |8798 | Day 2
66 | AfBLy_2_d1_4 | Sample |6776 | Day 7
69 | AfBLy_2_d1_9 | Sample |6789 | Day 5
66 | AfBLy_2_d1_1 | Sample Type | | Day 1
69 | AfBLy_2_d1_6 | Sample Type | | Day 2
66 | AfBLy_2_d1_4 | Sample Type | | Day 7
67 | AfBLy_2_d1_9 | Sample Type | | Day 5
如何将第3列col2=Sample的值复制到第3列col2=Sample Type对应的col1和id值
with cte as (
select * from your_table
where col2 = 'Sample'
)
update your_table as t1
set t1.col3 = t2.col3
from cte as t2
where t1.col2 = 'Sample Type'
and t1.col1 = t2.col1
and t1.id = t2.id;
您可以如下方式更新表:
with cte as (
select * from your_table
where col2 = 'Sample'
)
update your_table as t1
set t1.col3 = t2.col3
from cte as t2
where t1.col2 = 'Sample Type'
and t1.col1 = t2.col1
and t1.id = t2.id;