如何编写SQL以在一行中获取累积值和每月总数？

比如说，我有以下数据：

  select 1 id, date '2007-01-16' date_created, 5 sales, 'Bob' name from dual union all
  select 2 id, date '2007-04-16' date_created, 2 sales, 'Bob' name from dual union all
  select 3 id, date '2007-05-16' date_created, 6 sales, 'Bob' name from dual union all
  select 4 id, date '2007-05-21' date_created, 4 sales, 'Bob' name from dual union all
  select 5 id, date '2013-07-16' date_created, 24 sales, 'Bob' name from dual union all
  select 6 id, date '2007-01-17' date_created, 15 sales, 'Ann' name from dual union all
  select 7 id, date '2007-04-17' date_created, 12 sales, 'Ann' name from dual union all
  select 8 id, date '2007-05-17' date_created, 16 sales, 'Ann' name from dual union all
  select 9 id, date '2007-05-22' date_created, 14 sales, 'Ann' name from dual union all
  select 10 id, date '2013-07-17' date_created, 34 sales, 'Ann' name from dual

我希望得到如下结果：

Name        Total_cumulative_sales      Total_sales_current_month
Bob         41                          24
Ann         91                          34

在这个表中，对于Bob来说，从一开始他的总销售额是41。这个月，也就是7月份，他整个月的销售额是24。安也是如此

如何编写SQL以获得此结果

SELECT Name, 
SUM(Sales) Total_sales, 
SUM(CASE WHEN MONTH(date_created) = MONTH(GetDate()) AND YEAR(date_created) = YEAR(GetDate()) THEN Sales END) Total_sales_current_month
GROUP BY Name

应该可以，但可能有一种更优雅的方式来指定“当前月份”

应该可以，但是可能有一种更优雅的方式来指定“当前月份”。

尝试以下方式：

select name, sum(sales) as Total_cumulative_sales ,
       sum( 
            case trunc(to_date(date_created), 'MM')
              when  trunc(sysdate, 'MM') then sales
              else 0
            end
        ) as  Total_sales_current_month

from tab
group by name

SQL Fiddle

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更多信息

尝试以下方法：

select name, sum(sales) as Total_cumulative_sales ,
       sum( 
            case trunc(to_date(date_created), 'MM')
              when  trunc(sysdate, 'MM') then sales
              else 0
            end
        ) as  Total_sales_current_month

from tab
group by name

SQL Fiddle

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更多信息

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这应该适用于多年的销售。它将获得任意年份的累计销售额。如果最近一个月没有销售，它就不会创造记录

    WITH sales AS 
(select 1 id, date '2007-01-16' date_created, 5 sales, 'Bob' sales_name from dual union all
  select 2 id, date '2007-04-16' date_created, 2 sales, 'Bob' sales_name from dual union all
  select 3 id, date '2007-05-16' date_created, 6 sales, 'Bob' sales_name from dual union all
  select 4 id, date '2007-05-21' date_created, 4 sales, 'Bob' sales_name from dual union all
  select 5 id, date '2013-07-16' date_created, 24 sales, 'Bob' sales_name from dual union all
  select 6 id, date '2007-01-17' date_created, 15 sales, 'Ann' sales_name from dual union all
  select 7 id, date '2007-04-17' date_created, 12 sales, 'Ann' sales_name from dual union all
  select 8 id, date '2007-05-17' date_created, 16 sales, 'Ann' sales_name from dual union all
  select 9 id, date '2007-05-22' date_created, 14 sales, 'Ann' sales_name from dual union all
  select 10 id, date '2013-07-17' date_created, 34 sales, 'Ann' sales_name from dual)
  SELECT  sales_name
         ,total_sales
         ,monthly_sales
         ,mon 
  FROM (SELECT sales_name
              ,SUM(sales) OVER (PARTITION BY sales_name ORDER BY mon) total_sales
              ,SUM(sales) OVER (PARTITION BY sales_name,mon ORDER BY mon) monthly_sales
              ,mon 
              ,max_mon
        FROM (  SELECT sales_name
                      ,sum(sales) sales
                      ,mon
                      ,max_mon
                FROM   (SELECT sales_name
                              ,to_number(to_char(date_created,'YYYYMM')) mon
                              ,sales
                              ,MAX(to_number(to_char(date_created,'YYYYMM'))) OVER (PARTITION BY sales_name) max_mon
                        FROM sales
                        ORDER BY 2)
                GROUP BY sales_name
                        ,max_mon
                        ,mon
             )
        )
WHERE max_mon = mon

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)

这应该适用于多年的销售。它将获得任意年份的累计销售额。如果最近一个月没有销售，它就不会创造记录

    WITH sales AS 
(select 1 id, date '2007-01-16' date_created, 5 sales, 'Bob' sales_name from dual union all
  select 2 id, date '2007-04-16' date_created, 2 sales, 'Bob' sales_name from dual union all
  select 3 id, date '2007-05-16' date_created, 6 sales, 'Bob' sales_name from dual union all
  select 4 id, date '2007-05-21' date_created, 4 sales, 'Bob' sales_name from dual union all
  select 5 id, date '2013-07-16' date_created, 24 sales, 'Bob' sales_name from dual union all
  select 6 id, date '2007-01-17' date_created, 15 sales, 'Ann' sales_name from dual union all
  select 7 id, date '2007-04-17' date_created, 12 sales, 'Ann' sales_name from dual union all
  select 8 id, date '2007-05-17' date_created, 16 sales, 'Ann' sales_name from dual union all
  select 9 id, date '2007-05-22' date_created, 14 sales, 'Ann' sales_name from dual union all
  select 10 id, date '2013-07-17' date_created, 34 sales, 'Ann' sales_name from dual)
  SELECT  sales_name
         ,total_sales
         ,monthly_sales
         ,mon 
  FROM (SELECT sales_name
              ,SUM(sales) OVER (PARTITION BY sales_name ORDER BY mon) total_sales
              ,SUM(sales) OVER (PARTITION BY sales_name,mon ORDER BY mon) monthly_sales
              ,mon 
              ,max_mon
        FROM (  SELECT sales_name
                      ,sum(sales) sales
                      ,mon
                      ,max_mon
                FROM   (SELECT sales_name
                              ,to_number(to_char(date_created,'YYYYMM')) mon
                              ,sales
                              ,MAX(to_number(to_char(date_created,'YYYYMM'))) OVER (PARTITION BY sales_name) max_mon
                        FROM sales
                        ORDER BY 2)
                GROUP BY sales_name
                        ,max_mon
                        ,mon
             )
        )
WHERE max_mon = mon

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)

我认为这增加了同一个月不同年份的销售额。这就是我想要的吗？@Darkzaelus我已经把第一行改成了

2007-07-16

，它仍然可以工作，然后我收回，抱歉：）我必须阅读

trunc

函数，找出它是如何工作的哦，它不仅返回月份，还返回日期和其他不太相关的数据，基本上是向下舍入的。克利夫里认为，这增加了同一月份不同年份的销售额。这就是我想要的吗？@Darkzaelus我已经把第一行改成了

2007-07-16

，它仍然可以工作，然后我收回，抱歉：）我必须阅读

trunc

函数，找出它是如何工作的哦，它不仅返回月份，还返回日期和其他不太相关的数据，基本上是向下舍入的。聪明的