Oracle SQL包含要显示的列,而不将其添加到GROUP BY中
我正在尝试在用户表中查找所有案例变体重复项:Oracle SQL包含要显示的列,而不将其添加到GROUP BY中,sql,oracle11g,group-by,case-insensitive,Sql,Oracle11g,Group By,Case Insensitive,我正在尝试在用户表中查找所有案例变体重复项: SELECT LOWER(EMAIL), COUNT(EMAIL) FROM USERS GROUP BY LOWER(EMAIL) HAVING COUNT (LOWER(EMAIL)) >= 3; 结果类似于: Emails Count (number of duplicates) bob@example.com 3 john.smith@example
SELECT LOWER(EMAIL), COUNT(EMAIL)
FROM USERS
GROUP BY LOWER(EMAIL)
HAVING COUNT (LOWER(EMAIL)) >= 3;
结果类似于:
Emails Count (number of duplicates)
bob@example.com 3
john.smith@example.com 3
blah@example.com 4
james.smith@example.com 3
问题是我需要每封电子邮件的ID,我如何才能做到这一点?我不能简单地将其添加到SELECT语句中,因为GROUP BY:
SELECT **ID**, LOWER(EMAIL), COUNT(EMAIL)
FROM USERS
GROUP BY **ID**, LOWER(EMAIL)
HAVING COUNT (LOWER(EMAIL)) >= 3;
上面会查找重复的电子邮件和ID,这不是我需要的。试试这个:
SELECT U.*, COUNT(LOWER(EMAIL)) OVER (PARTITION BY (LOWER(EMAIL)))
FROM USERS U WHERE LOWER(EMAIL) IN (SELECT LOWER(EMAIL)
FROM USERS
GROUP BY LOWER(EMAIL)
HAVING COUNT (LOWER(EMAIL)) >= 3);
试试这个:
SELECT U.*, COUNT(LOWER(EMAIL)) OVER (PARTITION BY (LOWER(EMAIL)))
FROM USERS U WHERE LOWER(EMAIL) IN (SELECT LOWER(EMAIL)
FROM USERS
GROUP BY LOWER(EMAIL)
HAVING COUNT (LOWER(EMAIL)) >= 3);
您可以在内嵌视图中使用:
SELECT ID, EMAIL, LOWER(EMAIL), HOW_MANY
FROM (
SELECT ID, EMAIL, COUNT(*) OVER (PARTITION BY LOWER(EMAIL)) AS HOW_MANY
FROM USERS
)
WHERE HOW_MANY >= 3
ORDER BY ID;
ID EMAIL LOWER(EMAIL) HOW_MANY
---------- ------------------------------ ------------------------------ ----------
1 bob@example.com bob@example.com 3
2 Bob@example.com bob@example.com 3
3 BOB@example.com bob@example.com 3
4 john.smith@example.com john.smith@example.com 3
5 John.smith@example.com john.smith@example.com 3
6 JOHN.smith@example.com john.smith@example.com 3
7 blah@example.com blah@example.com 4
8 BLAH@example.com blah@example.com 4
9 blAH@example.com blah@example.com 4
10 BLah@example.com blah@example.com 4
11 james.smith@example.com james.smith@example.com 3
12 James.smith@example.com james.smith@example.com 3
13 JAMES.smith@example.com james.smith@example.com 3
。分析的一个好处是,它只需在表中出现一次。您可以在一个在线视图中使用:
SELECT ID, EMAIL, LOWER(EMAIL), HOW_MANY
FROM (
SELECT ID, EMAIL, COUNT(*) OVER (PARTITION BY LOWER(EMAIL)) AS HOW_MANY
FROM USERS
)
WHERE HOW_MANY >= 3
ORDER BY ID;
ID EMAIL LOWER(EMAIL) HOW_MANY
---------- ------------------------------ ------------------------------ ----------
1 bob@example.com bob@example.com 3
2 Bob@example.com bob@example.com 3
3 BOB@example.com bob@example.com 3
4 john.smith@example.com john.smith@example.com 3
5 John.smith@example.com john.smith@example.com 3
6 JOHN.smith@example.com john.smith@example.com 3
7 blah@example.com blah@example.com 4
8 BLAH@example.com blah@example.com 4
9 blAH@example.com blah@example.com 4
10 BLah@example.com blah@example.com 4
11 james.smith@example.com james.smith@example.com 3
12 James.smith@example.com james.smith@example.com 3
13 JAMES.smith@example.com james.smith@example.com 3
。分析的一个好处是,它只需在表中显示一次。我尝试过类似的查询,但问题是,我无法显示计数(电子邮件)。我尝试过类似的查询,但问题是,我无法显示计数(电子邮件)。哦,酷,我以前从未听说过这一点(我是新手)。给我一点时间试试。非常感谢,这是最好的答案。这也是一个快速的答案:)。使用大数据运行良好。您的SQL小提琴也非常有用。我感谢你的帮助!哦,太酷了,我以前从未听说过(我是这方面的新手)。给我一点时间试试。非常感谢,这是最好的答案。也很快:)。使用大数据运行良好。您的SQL小提琴也非常有用。我感谢你的帮助!