查找具有定义结束的连续相同值的行组（SQL红移）

我有一个表，其中包含任何给定日期的用户订阅状态。数据如下所示

+------------+------------+--------------+
| account_id |    date    | current_plan |
+------------+------------+--------------+
| 1          | 2019-08-01 | free         |
| 1          | 2019-08-02 | free         |
| 1          | 2019-08-03 | yearly       |
| 1          | 2019-08-04 | yearly       |
| 1          | 2019-08-05 | yearly       |
| ...        |            |              |
| 1          | 2020-08-02 | yearly       |
| 1          | 2020-08-03 | free         |
| 2          | 2019-08-01 | monthly      |
| 2          | 2019-08-02 | monthly      |
| ...        |            |              |
| 2          | 2019-08-31 | monthly      |
| 2          | 2019-09-01 | free         |
| ...        |            |              |
| 2          | 2019-11-26 | free         |
| 2          | 2019-11-27 | monthly      |
| ...        |            |              |
| 2          | 2019-12-27 | monthly      |
| 2          | 2019-12-28 | free         |
| 3          | 2020-05-31 | monthly      |
| 3          | 2020-06-01 | monthly      |
| 4          | 2019-08-01 | yearly       |
| ...        |            |              |
| 4          | 2020-06-01 | yearly       |
+------------+------------+--------------+

我想有一个表格，提供订阅的开始和结束日期。它看起来像这样。请注意，重要的是，此表中不包括帐户ID 3和4，因为截至2020年6月1日，它们仍在订阅中。我只想要一份从订阅中移出的人的摘要

+------------+------------+------------+-------------------+
| account_id | start_date |  end_date  | subscription_type |
+------------+------------+------------+-------------------+
|          1 | 2019-08-03 | 2020-08-02 | yearly            |
|          2 | 2019-08-01 | 2019-08-31 | monthly           |
|          2 | 2019-11-27 | 2019-12-27 | monthly           |
+------------+------------+------------+-------------------+

目前，我有以下非常接近，但仍然给我的用户没有退出订阅

select account_id, current_plan, min(date), max(date)
from (select d.*,
             row_number() over (partition by account_id order by date) as seqnum,
             row_number() over (partition by account_id, current_plan order by date) as seqnum_2
      from data d
     ) d
where current_plan not in ('free', 'trial')
group by account_id, current_plan, (seqnum - seqnum_2);

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如果您想对截至目前已退出的用户进行非常简单的筛选，只需添加：

有maxdate