Sql 如果嵌套案例的条件在不同的表上，则按分组

我的问题有点类似于问题，但有一点需要注意。在我的例子中，条件取决于不同的表，而不是一个表。给我带来麻烦的部分是

groupby

部分。以下是查询：

SELECT
    CASE 
        WHEN T1.ImportantColumn = 'Y'
        THEN 'Good'
        ELSE
            CASE
                WHEN T2.ImportantColumn = 1
                THEN 'Very Good'
                ELSE
                    CASE
                        WHEN T3.ImportantColumn IS NULL
                        THEN 'Bad'
                        ELSE T3.ImportantColumn
                    END
            END
    END AS WorkStatus,   
    SUM(case when T2.sex = 'M' THEN 1 ELSE 0 END) male , 
    SUM(case when T2.sex = 'F' THEN 1 ELSE 0 END) female , 
    COUNT(WorkStatus) AS [CountWorkStatus] 
FROM 
    Condition1Table T1 
    RIGHT JOIN Condition2Table T2 ON T1.city = T2.Code_id AND T1.field_name = 'cities' 
    INNER JOIN Condition3Table T3 ON T2.student_id = T3.student_id
GROUP BY T3.ImportantColumn, T2.ImportantColumn, T1.ImportantColumn -- <-- wrote this but I know it's wrong

你似乎在问“我如何在不重复整个案例陈述的情况下，按照一个巨大的案例陈述进行分组”

如果是这样，只需使用子查询

CASE语句的结果有一个列名，您可以引用它

这里几乎没有性能损失，子查询像宏一样展开。SQL是一种声明性语言，它只是一种用于表达待解决问题的语法。当它被编译下来时，有一个程序要运行。因此，在考虑SQL时，您只需要语法来表达您的问题

SELECT
    WorkStatus,
    SUM(case when sex = 'M' THEN 1 ELSE 0 END) male , 
    SUM(case when sex = 'F' THEN 1 ELSE 0 END) female , 
    COUNT(WorkStatus) AS [CountWorkStatus] 
FROM
(
    SELECT
        CASE 
            WHEN T1.ImportantColumn = 'Y'
            THEN 'Good'
            ELSE
                CASE
                    WHEN T2.ImportantColumn = 1
                    THEN 'Very Good'
                    ELSE
                        CASE
                            WHEN T3.ImportantColumn IS NULL
                            THEN 'Bad'
                            ELSE T3.ImportantColumn
                        END
                END
        END AS WorkStatus,
        T2.sex
    FROM 
        Condition1Table T1 
        RIGHT JOIN Condition2Table T2 ON T1.city = T2.Code_id AND T1.field_name = 'cities' 
        INNER JOIN Condition3Table T3 ON T2.student_id = T3.student_id
)
  AS StatusBySex
GROUP BY
  WorkStatus

---

不需要筑巢。简单地把不同的当在同一个情况下表达。

SELECT
    WorkStatus,
    SUM(case when sex = 'M' THEN 1 ELSE 0 END) male , 
    SUM(case when sex = 'F' THEN 1 ELSE 0 END) female , 
    COUNT(WorkStatus) AS [CountWorkStatus] 
FROM
(
    SELECT
        CASE 
            WHEN T1.ImportantColumn = 'Y'
            THEN 'Good'
            ELSE
                CASE
                    WHEN T2.ImportantColumn = 1
                    THEN 'Very Good'
                    ELSE
                        CASE
                            WHEN T3.ImportantColumn IS NULL
                            THEN 'Bad'
                            ELSE T3.ImportantColumn
                        END
                END
        END AS WorkStatus,
        T2.sex
    FROM 
        Condition1Table T1 
        RIGHT JOIN Condition2Table T2 ON T1.city = T2.Code_id AND T1.field_name = 'cities' 
        INNER JOIN Condition3Table T3 ON T2.student_id = T3.student_id
)
  AS StatusBySex
GROUP BY
  WorkStatus