Sqlite 从递归查询的结果创建表（with语句）

我想根据SQLite中递归查询的结果创建一个新的持久表。 例如，让我们用列n，fct创建一个表，其中n表示一个自然数，fct表示其阶乘：

-- factorial of n = 0, 1, ..., 5
WITH RECURSIVE fact_i (n, fct) AS (
     VALUES (0, 1)
     UNION ALL
     SELECT n+1, fct * (n+1) FROM fact_i
     WHERE n < 5)
SELECT * FROM fact_i;

但是，我希望将结果存储在一个持久表中，比如阶乘

我试过了

CREATE TABLE factorials (n, fct) AS
WITH RECURSIVE fact_i (n, fct) AS (
     VALUES (0, 1)
     UNION ALL
     SELECT n+1, fct * (n+1) FROM fact_i
     WHERE n < 5)
SELECT * FROM fact_i;

或

但这两种方法都会导致语法错误。

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有没有办法在SQLite中创建这样一个表？

是的，可以使用附加的SELECT*FROM进行包装：

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第9行末尾的最后s是什么？@AlQuemist子查询别名，但子查询部分可以跳过，请检查修订版

CREATE TABLE factorials (n, fct) AS
WITH RECURSIVE fact_i (n, fct) AS (
     VALUES (0, 1)
     UNION ALL
     SELECT n+1, fct * (n+1) FROM fact_i
     WHERE n < 5)
SELECT * FROM fact_i;

WITH RECURSIVE fact_i (n, fct) AS (
     VALUES (0, 1)
     UNION ALL
     SELECT n+1, fct * (n+1) FROM fact_i
     WHERE n < 5)
CREATE TABLE factorials (n, fct) AS
SELECT * FROM fact_i;

CREATE TABLE factorials AS
SELECT *
FROM (
WITH RECURSIVE fact_i (n, fct) AS (
     VALUES (0, 1)
     UNION ALL
     SELECT n+1, fct * (n+1) FROM fact_i
     WHERE n < 5)
SELECT * FROM fact_i) s;

CREATE TABLE factorials AS
WITH RECURSIVE fact_i (n, fct) AS (
     VALUES (0, 1)
     UNION ALL
     SELECT n+1, fct * (n+1) FROM fact_i
     WHERE n < 5)
SELECT * FROM fact_i;