SSAS MDX计算成员,多个作用域
想象一个具有尺寸的立方体——DimA、DimB、DimC和DimD 我想要一个计算过的成员,该成员只有在根据DimA或DimB切片时才应计算。如果仅针对DimC或DimD进行切片,则应返回Null 目前,我通过使用以下3个计算成员实现了这一点:SSAS MDX计算成员,多个作用域,ssas,mdx,Ssas,Mdx,想象一个具有尺寸的立方体——DimA、DimB、DimC和DimD 我想要一个计算过的成员,该成员只有在根据DimA或DimB切片时才应计算。如果仅针对DimC或DimD进行切片,则应返回Null 目前,我通过使用以下3个计算成员实现了这一点: Create Member CurrentCube.[Measures].[CalMeasure1] As Null, VISIBLE = 0; SCOPE([Measures].[CalcMeasure1]); SCOPE ([Di
Create Member CurrentCube.[Measures].[CalMeasure1] As Null, VISIBLE = 0;
SCOPE([Measures].[CalcMeasure1]);
SCOPE ([DimA].[DimA].[DimA]);
This = [Measures].[Camp Index];
END SCOPE;
END SCOPE;
Create Member CurrentCube.[Measures].[CalcMeasure2] As Null, VISIBLE = 0;
SCOPE([Measures].[CalcMeasure2]);
SCOPE ([DimB].[DimB].[DimB]);
This = [Measures].[Camp Index];
CREATE MEMBER CURRENTCUBE.[Measures].[CalcMeasure3]
AS IIF(ISEMPTY([Measures].[CalcMeasure1]),[Measures].[CalcMeasure2],[Measures].[CalcMeasure1]),
VISIBLE = 1 ;
END SCOPE;
END SCOPE;
我必须创建很多这样的度量值,所以理想情况下,我希望使用一个度量值,而不是三个单独的度量值。我已尝试创建嵌套范围。我还尝试将两个维度层次结构放在一个范围内。然而,这两种方法都不起作用。这两种方法都要求针对DimA和DimB对度量值进行切片。我需要它的工作,如果它是对DimA或DimB切片
注意我上面的代码确实有效,我只想将其压缩为单个计算成员
编辑:-不同透视表用法的预期结果
DimA Attribute CalcMeasure3
1 1.1
2 1.1
3 8.6
DimB Attribute CalcMeasure3
4 2.1
5 2.1
6 9.6
DimA Attribute DimC Attribute CalcMeasure3
1 A 1.1
2 B 1.1
3 C 8.6
DimB Attribute DimD Attribute CalcMeasure3
4 D 1.1
5 E 1.1
6 F 8.6
DimC Attribute CalcMeasure3
A (Null)
B (Null)
C (Null)
DimD Attribute CalcMeasure3
D (Null)
E (Null)
F (Null)
我的第一个猜测是:
Scope([Measures].[Camp Index]);
This = IIF(
[DimC].[DimC].[DimC].CurrentMember is [DimC].[DimC].[All]
and
[DimD].[DimD].[DimD].CurrentMember is [DimD].[DimD].[All]
[Measures].[Camp Index],
NULL
);
End Scope;
这个计算的度量值如何,没有范围:
WITH MEMBER [Camp Index] AS
IIF(
not ([DimA].[DimA].CurrentMember is [DimA].[DimA].[All]) or not([DimB].[DimB].CurrentMember is [DimB].[DimB].[All]),
[You Calcuate],
IIF(
not ([DimC].[DimC].CurrentMember is [DimC].[DimC].[All]) or not([DimD].[DimD].CurrentMember is [DimD].[DimD].[All]),
NULL,
[You Calcuate]
),
NULL
)
SELECT
{[Camp Index]} on 0
from [Adventure Works]
谢谢你是说[DimA].[DimA].[DimA]。当前成员是[DimA].[DimA].[All]和[DimB].[DimB].[DimB]。当前成员是[DimB].[DimB].[All]?如果是这样,则即使被DimA、DimB或两者分割,也始终返回null。被DimC、DimD或Dim(n)切片时也为空