String 从列表转换<;字符串>;列出<;性格>;JAVA
好的,一些可能的转换是String 从列表转换<;字符串>;列出<;性格>;JAVA,string,list,collections,java-8,character,String,List,Collections,Java 8,Character,好的,一些可能的转换是 List<String> stringList = integerList.stream().map(Object::toString) .collect(Collectors.toList()); List-stringList=integerList.stream().map(对象::toString) .collect(Collectors.toList()); 及 List i
List<String> stringList = integerList.stream().map(Object::toString)
.collect(Collectors.toList());
List-stringList=integerList.stream().map(对象::toString)
.collect(Collectors.toList());
及
List integerList=stringList.stream()
.map(Integer::valueOf).collect(Collectors.toList());
从字符串列表到字符列表是否有类似上述的转换??确定:
List<Character> result =
stringList.stream()
.flatMapToInt(String::chars)
.mapToObj(i -> Character.valueOf((char) i)
.collect(Collectors.toList());
列表结果=
stream()
.flatMapToInt(字符串::字符)
.mapToObj(i->Character.valueOf((char)i)
.collect(Collectors.toList());
或者干脆
List<Character> result =
stringList.stream()
.flatMapToInt(String::chars)
.mapToObj(i -> (char) i)
.collect(Collectors.toList());
列表结果=
stream()
.flatMapToInt(字符串::字符)
.mapToObj(i->(char)i)
.collect(Collectors.toList());
List<Character> result =
stringList.stream()
.flatMapToInt(String::chars)
.mapToObj(i -> (char) i)
.collect(Collectors.toList());