Subsonic 不支持“Equals”方法
如何使用.equals使用相同的方法???您是否尝试过以下方法:Subsonic 不支持“Equals”方法,subsonic,Subsonic,如何使用.equals使用相同的方法???您是否尝试过以下方法: public List<Health_Scheme_System.Employee> GetPenEmployeeTable() { Health_Scheme_System.Health_Scheme_SystemDB db = new Health_Scheme_System.Health_Scheme_SystemDB(); var x = (from c in db.Employees
public List<Health_Scheme_System.Employee> GetPenEmployeeTable()
{
Health_Scheme_System.Health_Scheme_SystemDB db = new Health_Scheme_System.Health_Scheme_SystemDB();
var x = (from c in db.Employees
where c.Pensioners.Equals (1)
select c);
return x.ToList();
}
//Selecting multiple columns from an HR view table together with the scheme name of scheme.
public List<EmployeesX> GetPensioners()
{
Health_Scheme_System.Health_Scheme_SystemDB db = new Health_Scheme_System.Health_Scheme_SystemDB();
List<Health_Scheme_System.EmployeeDirectory> listEmployeeView = GetPenEmployeeView();
List<Health_Scheme_System.Employee> listEmployeeTable = GetPenEmployeeTable();
List<Health_Scheme_System.Scheme> listSchemes = GetSchemes();
List<EmployeesX> listOfEmployees = new List<EmployeesX>();
//checking for comparision of getemployeeview to getemployee table and then to getschemes
//Then display the scheme name if they are similar.
for (int i = 0; i < listEmployeeView.Count; i++)
{
EmployeesX emp = new EmployeesX();
emp.ID_NO = listEmployeeView[i].ID_NO;
emp.FIRST_NAME = listEmployeeView[i].FIRST_NAME;
emp.LAST_NAME = listEmployeeView[i].LAST_NAME;
emp.LOCATION_CODE = listEmployeeView[i].LOCATION_CODE;
for (int j = 0; j < listEmployeeTable.Count; j++)
{
if (listEmployeeTable[j].EmployeeIDCard == listEmployeeView[i].ID_NO)
{
emp.Pensioners = listEmployeeTable[j].Pensioners;
for (int k = 0; k < listSchemes.Count; k++)
{
if (listEmployeeTable[j].SchemeID == listSchemes[k].SchemeID)
{
emp.SCHEME_NAME = listSchemes[k].Name;
emp.START_DATE = listEmployeeTable[j].StartSchemeDate;
}
}
}
}
listOfEmployees.Add(emp);
}
return listOfEmployees;
}
其他信息:
如果在linq查询中对对象使用方法,亚音速需要知道如何将其转换为pur SQL代码。这在默认情况下不起作用,如果与默认实现不同,则必须为每个数据提供程序的每个支持类型上的每个已知方法实现。因此,对于亚音速,有很多工作要做
了解支持什么和不支持什么的一个很好的起点是TSqlFormatter类。请看一看受保护的重写表达式VisitMethodCallMethodCallExpression m
已经有了Equals的实现
我想prensioners是一个整数类型,所以你基本上必须添加另一个else if,然后重新对亚音速进行压缩
这应该可以,但我还没有测试过
else if (m.Method.Name == "Equals")
{
if (m.Method.IsStatic && m.Method.DeclaringType == typeof(object))
{
sb.Append("(");
this.Visit(m.Arguments[0]);
sb.Append(" = ");
this.Visit(m.Arguments[1]);
sb.Append(")");
return m;
}
else if (!m.Method.IsStatic && m.Arguments.Count == 1 && m.Arguments[0].Type == m.Object.Type)
{
sb.Append("(");
this.Visit(m.Object);
sb.Append(" = ");
this.Visit(m.Arguments[0]);
sb.Append(")");
return m;
}
else if (m.Method.IsStatic && m.Method.DeclaringType == typeof(string))
{
//Note: Not sure if this is best solution for fixing side issue with Issue #66
sb.Append("(");
this.Visit(m.Arguments[0]);
sb.Append(" = ");
this.Visit(m.Arguments[1]);
sb.Append(")");
return m;
}
}
或者您也可以尝试上面示例中的==方法
else if (m.Method.Name == "Equals")
{
if (m.Method.IsStatic && m.Method.DeclaringType == typeof(object))
{
sb.Append("(");
this.Visit(m.Arguments[0]);
sb.Append(" = ");
this.Visit(m.Arguments[1]);
sb.Append(")");
return m;
}
else if (!m.Method.IsStatic && m.Arguments.Count == 1 && m.Arguments[0].Type == m.Object.Type)
{
sb.Append("(");
this.Visit(m.Object);
sb.Append(" = ");
this.Visit(m.Arguments[0]);
sb.Append(")");
return m;
}
else if (m.Method.IsStatic && m.Method.DeclaringType == typeof(string))
{
//Note: Not sure if this is best solution for fixing side issue with Issue #66
sb.Append("(");
this.Visit(m.Arguments[0]);
sb.Append(" = ");
this.Visit(m.Arguments[1]);
sb.Append(")");
return m;
}
}
else if (!m.Method.IsStatic && m.Method.DeclaringType == typeof(int))
{
sb.Append("(");
this.Visit(m.Arguments[0]);
sb.Append(" = ");
this.Visit(m.Arguments[1]);
sb.Append(")");
return m;
}