Swift中的drmohundro/SWXMLHash和转义值

我正在从事一个处理xml响应的项目。经过搜索，我在github上找到了一个库，它的灵感来自于“迅捷JSON”。使用它一段时间后，我意识到我无法通过转义值获得值

xml响应看起来像

let xmlResponseString = "<TrackList><Entry><Id>2</Id><Uri>/Input/E21u</Uri><Metadata><DIDL-Lite xmlns="urn:schemas-upnp-org:metadata-1-0/DIDL-Lite/" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:upnp="urn:schemas-upnp-org:metadata-1-0/upnp/"><item id="E21"><dc:title>Doing It To Death</dc:title><upnp:album>Ash & Ice</upnp:album><upnp:artist>The Kills</upnp:artist><upnp:class>object.item.audioItem.musicTrack</upnp:class><upnp:albumArtURI>http://192.168.1.106:8088/storage/emulated/0/record_cache/album_art/1535461905688.jpg</upnp:albumArtURI><res sampleFrequency="96000" bitsPerSample="24" bitrate="2304000" nrAudioChannels="2" protocolInfo="http-get:*:audio/mpeg" duration="00:04:07.431">/Input/E21</res></item></DIDL-Lite></Metadata></Entry></TrackList>"

此外，检查“xmlHash”时，错误似乎已经来自“SWXMLHash.parse（xmlResponseString）”

是否需要转义“xmlResponseString”？ 是不是图书馆处理得不好？ 还有别的选择吗

多谢各位

编辑 响应来自另一个OpenHome提供程序设备

最初的答复是：

<TrackList>
<Entry>
    <Id>2</Id>
    <Uri>/Input/E21u</Uri>
    <Metadata>&#60;DIDL-Lite xmlns="urn:schemas-upnp-org:metadata-1-0/DIDL-Lite/" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:upnp="urn:schemas-upnp-org:metadata-1-0/upnp/"&#62;&#60;item id="E21"&#62;&#60;dc:title&#62;Doing It To Death&#60;/dc:title&#62;&#60;upnp:album&#62;Ash &#38; Ice&#60;/upnp:album&#62;&#60;upnp:artist&#62;The Kills&#60;/upnp:artist&#62;&#60;upnp:class&#62;object.item.audioItem.musicTrack&#60;/upnp:class&#62;&#60;upnp:albumArtURI&#62;http://192.168.1.106:8088/storage/emulated/0/record_cache/album_art/1535461905688.jpg&#60;/upnp:albumArtURI&#62;&#60;res sampleFrequency="96000" bitsPerSample="24" bitrate="2304000" nrAudioChannels="2" protocolInfo="http-get:*:audio/mpeg" duration="00:04:07.431"&#62;/Input/E21&#60;/res&#62;&#60;/item&#62;&#60;/DIDL-Lite&#62;
    </Metadata>
</Entry>

2.
/输入/E21u
<DIDL-Lite xmlns=“urn:schemas-upnp-org:metadata-1-0/DIDL-Lite/”xmlns:dc=”http://purl.org/dc/elements/1.1/“xmlns:upnp=“urn:schemas-upnp-org:metadata-1-0/upnp/”><项目id=“E21”和#62<dc:标题>；干到死</dc:标题><upnp:album>；灰烬&；冰</upnp:album><upnp：艺术家>；死亡人数<人/upnp：艺术家><upnp:62级；object.item.audioItem.musicTrack</upnp:62级<upnp:albumArtURI和#62；http://192.168.1.106:8088/storage/emulated/0/record_cache/album_art/1535461905688.jpg</upnp:albumArtURI和#62<res sampleFrequency=“96000”bitsPerSample=“24”bitrate=“2304000”nrAudioChannels=“2”protocolInfo=“http://get:::audio/mpeg”duration=“00:04:07.431”和#62/输入/E21和#60/res></第62项</DIDL Lite和#62；

根据开发人员的说法，元数据值已被转义，因为它是XML中的XML。不知道这是否重要

因为我想创建一个通用解析函数来填充类，所以我创建了以下方法：

func unescapeXMLPredefinedCharacters(value:String?) -> String{

var audioString = ""

if value != nil{

    audioString = value!

    //Replace Unicode HTML Entity
    audioString = audioString.replacingOccurrences(of: """, with: "\"")
    audioString = audioString.replacingOccurrences(of: "&", with: "&")
    audioString = audioString.replacingOccurrences(of: "'", with: "'")
    audioString = audioString.replacingOccurrences(of: "&lt;", with: "<")
    audioString = audioString.replacingOccurrences(of: "&gt;", with: ">")


    //Replace Unicode Decimal
    audioString = audioString.replacingOccurrences(of: "&#34;", with: "\"")

    audioString = audioString.replacingOccurrences(of: "&#38;", with: "&")
    audioString = audioString.replacingOccurrences(of: "&#39;", with: "'")
    audioString = audioString.replacingOccurrences(of: "&#60;", with: "<")
    audioString = audioString.replacingOccurrences(of: "&#62;", with: ">")


    //Replace Unicode Hex
    audioString = audioString.replacingOccurrences(of: "&#x22;", with: "\"")
    audioString = audioString.replacingOccurrences(of: "&#x26;", with: "&")
    audioString = audioString.replacingOccurrences(of: "&#x27;", with: "'")
    audioString = audioString.replacingOccurrences(of: "&#x3c;", with: "<")
    audioString = audioString.replacingOccurrences(of: "&#x3e;", with: ">")

}

return audioString

}

func unescapeXMLPredefinedCharacters（值：String？）->String{
var audioString=“”
如果值！=nil{
audioString=值！
//替换Unicode HTML实体
audioString=audioString.replacingOccurrences（of:“”和“\”）
audioString=audioString.replacingOccurrences（of:“&；”，带“&”）
audioString=audioString.replacingOccurrences（of:“&apos；”，with:”）
audioString=audioString.replacingOccurrences（of:，with:）
//替换Unicode十进制
audioString=audioString.replacingOccurrences（of:"；”，带“\”）
audioString=audioString.replacingOccurrences（of:&；”，带“&”）
audioString=audioString.replacingOccurrences（of:'；”，带“”）
audioString=audioString.replacingOccurrences（of:<；，with:）
//替换Unicode十六进制
audioString=audioString.replacingOccurrences（of:"；，带“\”）
audioString=audioString.replacingOccurrences（of:&；”，带“&”）
audioString=audioString.replacingOccurrences（of:'；，带“”）
audioString=audioString.replacingOccurrences（of:<；，with:）
}
返回音频字符串
}

它不知道使用了哪种unicode类型来进行取消逃避

---

然后我从我原来的问题中得到了答案，问题是转义的内部xml在某种意义上已经是错误的，它包含

&

字符（unicode），并且可能

根据Andreas的回答，我已经更改了函数

func unescapeXMLPredefinedCharacters(value:String?) -> String{

    var audioString = ""

    if value != nil{

        audioString = value!

        //Replace Unicode Decimal
        audioString = audioString.replacingOccurrences(of: """, with: """)
        audioString = audioString.replacingOccurrences(of: "&", with: "&")
        audioString = audioString.replacingOccurrences(of: "'", with: "'")
        audioString = audioString.replacingOccurrences(of: "<", with: "<")
        audioString = audioString.replacingOccurrences(of: ">", with: ">")

    }

    return audioString

}

您从哪里获得
xmlResponseString
？它似乎不是有效的xml-文本节点不能包含未替换的符号，因此它应该是“Ash&；Ice”。您是否说“&”不应该在那里？我已经编辑了我的问题是的，“转义”内部xml在某种意义上已经是错误的，一旦您取消转义它，就会出现一个“&”，应该是“&；”。这个“&；”然后将由xml解析器（SWXMLHash）处理。其他xml实体（如“>”（）等）也是如此，一旦它们位于xml文本元素的内容中，那么我是否必须取消对内部xml的扫描？内部xml是否被错误转义（内部xml为Unicode Decimal，内部xml为Unicode HTML实体）？您不应该取消对所有这些xml实体（如“&；”或”“等）的转义，您应该将“&；38；”等取消对“&；”的转义，而不是对“&；”（以及所有其他实体）的转义。然后，xml解析器将在内部处理这些“&；”内容
func unescapeXMLPredefinedCharacters(value:String?) -> String{

    var audioString = ""

    if value != nil{

        audioString = value!

        //Replace Unicode Decimal
        audioString = audioString.replacingOccurrences(of: """, with: """)
        audioString = audioString.replacingOccurrences(of: "&", with: "&")
        audioString = audioString.replacingOccurrences(of: "'", with: "'")
        audioString = audioString.replacingOccurrences(of: "<", with: "<")
        audioString = audioString.replacingOccurrences(of: ">", with: ">")

    }

    return audioString

}