将字符串转换为cllocationcoordinate2d swift的数组

我使用的API返回一个包含坐标的

字符串。如何转换此响应：

“线路引脚”：
"#30.0539983,30.943465#30.0539033,30.9434167#30.05379,30.9434467#30.0536117,30.943865#30.0535133,30.9439867#30.0534633,30.9440967#30.05353,30.94428#30.053675,30.944525#30.0539933,30.9449667#30.0541517,30.9452317#30.0542917,30.9454717#30.054365,30.9455717#30.0544667,30.945725#30.05471,30.9460733#30.0548667,30.94631#30.0550417,30.9465683#30.0553733,30.9471133#30.0557133,30.9476383#30.0558667,30.947905#30.0560083,30.9481767#30.0562517,30.94872#30.0564917,30.9492217#30.0565783,30.949494567#30.056645,30.9496883#30.0566167 30.9501883”

进入
CLLocationCoordinate2D的
数组
，使用
MapKit
绘制一条线，使用：

let polyLine = MKPolyline(coordinates: Locations , count: Locations.count)
busMapView.add(polyLine)

您可以通过组合
组件（由
和
map


按字符
#
拆分字符串，并删除第一个（空）项
通过用逗号拆分字符串，将每个项目映射到
CLLocationCoordinate2D
，将字符串转换为
CLLocationCoordinate2D
，并创建坐标


结果是
[CLLocationCoordinate2D]
让dic:Dictionary=[“线路针脚”："#30.0539983,30.943465#30.0539033,30.9434167#30.05379,30.9434467#30.0536117,30.943865#30.0535133,30.9439867#30.0534633,30.9440967#30.05353,30.94428#30.053675,30.944525#30.0539933,30.9449667#30.0541517,30.9452317#30.0542917,30.9454717#30.054365,30.9455717#30.0544667,30.945725#30.05471,30.9460733#30.0548667,30.94631#30.0550417,30.9465683#30.0553733,30.9471133#30.0557133,30.9476383#30.0558667,30.947905#30.0560083,30.9481767#30.0562517,30.94872#30.0564917,30.9492217#30.0565783,30.9494567#30.056645,30.9496883#30.0566167,30.9501883"]
let dic:Dictionary<String,Any> = ["route_pins": "#30.0539983,30.943465#30.0539033,30.9434167#30.05379,30.9434467#30.0536117,30.943865#30.0535133,30.9439867#30.0534633,30.9440967#30.05353,30.94428#30.053675,30.944525#30.0539933,30.9449667#30.0541517,30.9452317#30.0542917,30.9454717#30.054365,30.9455717#30.0544667,30.945725#30.05471,30.9460733#30.0548667,30.94631#30.0550417,30.9465683#30.0553733,30.9471133#30.0557133,30.9476383#30.0558667,30.947905#30.0560083,30.9481767#30.0562517,30.94872#30.0564917,30.9492217#30.0565783,30.9494567#30.056645,30.9496883#30.0566167,30.9501883"]


let strLatLng = dic["route_pins"] as! String
let arrayOflatLng = strLatLng.components(separatedBy: "#")
var testcoords = [CLLocationCoordinate2D]()
for latLngStr in arrayOflatLng {
    if let strLat = latLngStr.components(separatedBy: ",") as? [String], strLat.count == 2 {
        testcoords.append(CLLocationCoordinate2D(latitude: CLLocationDegrees(strLat[0])!, longitude: CLLocationDegrees(strLat[1])!))
     }
}

print("testcoords \(testcoords.count)")
let polyLine = MKPolyline(coordinates: testcoords , count: testcoords.count)
busMapView.add(polyLine)

将strLatLng=dic[“布线引脚”]设为！字符串
设ArrayFlatlng=strLatLng.组件（以“#”分隔）
var testcoords=[CLLocationCoordinate2D]（）
用于阵列中的latLngStr{
如果将strLat=latLngStr.components（以“，”分隔）设为？[String]，则strLat.count==2{
追加（CLLocationCoordinate2D（纬度：CLLocationDegrees（strLat[0]）！，经度：CLLocationDegrees（strLat[1]）！）
}
}
打印（“testcoords\（testcoords.count）”）
设polyLine=MKPolyline（坐标：testcoords，计数：testcoords.count）
busMapView.add（多段线）
API字符串使用两级解析进行解析，首先我们将API字符串拆分为位置字符串，然后使用for循环将每个位置拆分为其坐标，并将坐标保存到CLLocationCoordinate2D，并将其附加到结果数组中

  let routePins = "#30.0539983,30.943465#30.0539033,30.9434167#30.05379,30.9434467#30.0536117,30.943865#30.0535133,30.9439867#30.0534633,30.9440967#30.05353,30.94428#30.053675,30.944525#30.0539933,30.9449667#30.0541517,30.9452317#30.0542917,30.9454717#30.054365,30.9455717#30.0544667,30.945725#30.05471,30.9460733#30.0548667,30.94631#30.0550417,30.9465683#30.0553733,30.9471133#30.0557133,30.9476383#30.0558667,30.947905#30.0560083,30.9481767#30.0562517,30.94872#30.0564917,30.9492217#30.0565783,30.9494567#30.056645,30.9496883#30.0566167,30.9501883"
        let pins = routePins.components(separatedBy: "#")//first step is splitting the fetched array to pins array 
        var LocationsArray = [CLLocationCoordinate2D]()//this is the result array
        for location in pins {
        if(location.contains(",")){//checking that the location is containing lat ,long separtor
        let coordinates = location.components(separatedBy: ",")//splitting the location to lat ,long 
        //safe parsing the string value to double vale for coordinates 
        let lat = Double(coordinates[0]) ?? 0.0
        let long = Double( coordinates[1]) ?? 0.0
        LocationsArray.append(CLLocationCoordinate2D(latitude: lat
        ,longitude: long))// appending new coordinates to locations array
        }
        }

这正是我所需要的。非常感谢您，瓦迪安先生，您刚刚救了我，非常感谢您
让latLng=pin.components（以“，”分隔）。compactMap（CLLocationDegrees.init）
尝试为您的代码添加一些上下文，以帮助未来的读者更好地理解其含义。
  let routePins = "#30.0539983,30.943465#30.0539033,30.9434167#30.05379,30.9434467#30.0536117,30.943865#30.0535133,30.9439867#30.0534633,30.9440967#30.05353,30.94428#30.053675,30.944525#30.0539933,30.9449667#30.0541517,30.9452317#30.0542917,30.9454717#30.054365,30.9455717#30.0544667,30.945725#30.05471,30.9460733#30.0548667,30.94631#30.0550417,30.9465683#30.0553733,30.9471133#30.0557133,30.9476383#30.0558667,30.947905#30.0560083,30.9481767#30.0562517,30.94872#30.0564917,30.9492217#30.0565783,30.9494567#30.056645,30.9496883#30.0566167,30.9501883"
        let pins = routePins.components(separatedBy: "#")//first step is splitting the fetched array to pins array 
        var LocationsArray = [CLLocationCoordinate2D]()//this is the result array
        for location in pins {
        if(location.contains(",")){//checking that the location is containing lat ,long separtor
        let coordinates = location.components(separatedBy: ",")//splitting the location to lat ,long 
        //safe parsing the string value to double vale for coordinates 
        let lat = Double(coordinates[0]) ?? 0.0
        let long = Double( coordinates[1]) ?? 0.0
        LocationsArray.append(CLLocationCoordinate2D(latitude: lat
        ,longitude: long))// appending new coordinates to locations array
        }
        }