SwiftUI：如何将@Published变量传递给函数参数并获取值

下面的代码工作并将

topLeftGameState

分配给计时器。如果

globalGameState

更改为

running

，则

topLeftGameState

会相应更改

@Published var topLeftGameState: GameState = .notReady
@Published var topRightGameState: GameState = .notReady
@Published var bottomLeftGameState: GameState = .notReady

private let timerPublisher = Timer.publish(every: 0.01, on: .main, in: .common)    
// ...
 timerPublisher.autoconnect().sink(receiveValue: { currentDate in
        switch self.globalGameState {
        case .running(startDate: let startDate):
            let elapsedTime = currentDate - startDate
            if self.topLeftGameState == .ready { //,   {
                self.topLeftGameState = .running(elapsedTime: elapsedTime.timeInterval)
            }
            if case .running(elapsedTime: _) = self.topLeftGameState {
                self.topLeftGameState = .running(elapsedTime: elapsedTime.timeInterval)
            }
            
            if self.topRightGameState == .ready { //,   {
                self.topRightGameState = .running(elapsedTime: elapsedTime.timeInterval)
            }
            if case .running(elapsedTime: _) = self.topRightGameState {
                self.topRightGameState = .running(elapsedTime: elapsedTime.timeInterval)
            }
            
            if self.bottomLeftGameState == .ready { //,   {
                self.bottomLeftGameState = .running(elapsedTime: elapsedTime.timeInterval)
            }
            if case .running(elapsedTime: _) = self.bottomLeftGameState {
                self.bottomLeftGameState = .running(elapsedTime: elapsedTime.timeInterval)
            }
        default: ()
        }
    }).store(in: &cancellables)

因此，这段代码看起来非常难看，我想为所有发布的

@变量编写一个函数：

    addTimePublisher(for: topLeftGameState)
    addTimePublisher(for: topRightGameState)
        //...
    private func addTimePublisher(for gameState: Published<GameState>.Publisher) {
        timerPublisher.autoconnect().sink(receiveValue: { currentDate in
            switch self.globalGameState {
            case .running(startDate: let startDate):
                let elapsedTime = currentDate - startDate
                if self.gameState == .ready {
                    self.gameState = .running(elapsedTime: elapsedTime.timeInterval)
                }
                if case .running(elapsedTime: _) = self.gameState {
                    self.gameState = .running(elapsedTime: elapsedTime.timeInterval)
                }
                
            default: ()
            }
            print(currentDate)
        }).store(in: &cancellables)
    }

addTimePublisher（适用于：topLeftGameState）
addTimePublisher（适用于：topRightGameState）
//...
私有func addTimePublisher（适用于游戏状态：Published.Publisher）{
timerPublisher.autoconnect（）.sink（接收值：{currentDate in
开关自发光{
案例运行（开始日期：让开始日期）：
设elapsedTime=currentDate-startDate
如果self.gameState==.ready{
self.gameState=.running（elapsedTime:elapsedTime.timeInterval）
}
如果case.running（elapsedTime:u）=self.gameState{
self.gameState=.running（elapsedTime:elapsedTime.timeInterval）
}
默认值：（）
}
打印（当前日期）
}).store（在：&可取消项中）
}

这将引发一个错误：
无法推断引用成员“ready”的上下文基础。

我不知道如何从出版商那里获得适当的价值？
有人对我有什么建议吗

编辑：
如何编写函数并传递
@Published
变量？
将Published属性作为EnvironmentObject注入整个viewModel将更有意义，而不是尝试传递单个
@Published
属性。我不清楚您在做什么。“连接到
计时器发布器”
“是什么意思？您试图如何以及在何处调用
addTimePublisher
，在同一视图模型中，所有这些都发生在何处？你可能在问一个X-Y问题。但要回答您的最后一个问题-从您需要订阅的发布服务器获取值（使用
.sink
，就像使用计时器发布服务器一样）。我猜这不是你真正需要的对不起，我更新了我的问题。