inode列(proc/net/tcp(6))中的值是什么意思?

inode列(proc/net/tcp(6))中的值是什么意思?,tcp,inode,uid,proc,Tcp,Inode,Uid,Proc,这是一个/proc/net/tcp文件: sl local_address rem_address st tx_queue rx_queue tr tm->当retrnsmt uid超时索引节点 6:1904A8C0:AC35 9603020A:1ED001 00000000:00000000:00000000 00000000 10055 0 8506 2 c1624900 129 0 0 10-1 7:1904A8C0:E8C4 13A11C1F:0050 06 00000000:00000

这是一个/proc/net/tcp文件:

sl local_address rem_address st tx_queue rx_queue tr tm->当retrnsmt uid超时索引节点

6:1904A8C0:AC35 9603020A:1ED001 00000000:00000000:00000000 00000000 10055 0 8506 2 c1624900 129 0 0 10-1
7:1904A8C0:E8C4 13A11C1F:0050 06 00000000:00000000 03:00001390 00000000 0 3 d6267780

有人能解释一下inode列中的值是什么意思吗?我对两件事感兴趣

8506 2 c1624900 129 0 10-1

0 3 d6267780


我只知道第一个值是inode number(唯一文件号)。

linux-2.6.35.6/net/ipv4/tcp\u ipv4.c

2358     seq_printf(f, "%4d: %08X:%04X %08X:%04X %02X %08X:%08X %02X:%08lX "
2359             "%08X %5d %8d %lu %d %p %lu %lu %u %u %d%n",
2360         i, src, srcp, dest, destp, sk->sk_state,
2361         tp->write_seq - tp->snd_una,
2362         rx_queue,
2363         timer_active,
2364         jiffies_to_clock_t(timer_expires - jiffies),
2365         icsk->icsk_retransmits,
2366         sock_i_uid(sk),
2367         icsk->icsk_probes_out,
2368         sock_i_ino(sk),
2369         atomic_read(&sk->sk_refcnt), sk, 
2370         jiffies_to_clock_t(icsk->icsk_rto),
2371         jiffies_to_clock_t(icsk->icsk_ack.ato),
2372         (icsk->icsk_ack.quick << 1) | icsk->icsk_ack.pingpong,
2373         tp->snd_cwnd,
2374         tcp_in_initial_slowstart(tp) ? -1 : tp->snd_ssthresh,
2375         len);
2358 seq_printf(f),“%4d:%08X:%04X%08X:%04X%02X%08X:%08X%02X:%08lX”
2359“%08X%5d%8d%lu%d%p%lu%lu%u%u%d%n”,
2360 i,src,srcp,dest,destp,sk->sk_状态,
2361 tp->写入顺序-tp->snd_una,
2362 rx_队列,
2363定时器_激活,
2364次计时至时钟(计时器到期-计时),
2365 icsk->icsk_重新传输,
2366袜子油(sk),
2367 icsk->icsk探头,
2368袜子(sk),
2369原子读取(&sk->sk refcnt),sk,
2370个时钟到时钟(icsk->icsk rto),
2371小时到时钟(icsk->icsk确认ato),
2372(icsk->icsk_ack.quick icsk_ack.pingpong),
2373 tp->snd\U cwnd,
2374 tcp在初始slowstart(tp)?-1:tp->snd ssthresh中,
2375 len);
答案就在这里:可能重复