Tsql 如何获取第一个不为null的列
如果标题不好,很抱歉。但我不知道如何解决这个问题。 我一直在努力处理sql中的查询。我不知道以前是否有人问过这个问题。但是我需要得到第一个非空的列。我有一张这样的桌子:Tsql 如何获取第一个不为null的列,tsql,sql-server-2005,null,sql-server-2008-r2,Tsql,Sql Server 2005,Null,Sql Server 2008 R2,如果标题不好,很抱歉。但我不知道如何解决这个问题。 我一直在努力处理sql中的查询。我不知道以前是否有人问过这个问题。但是我需要得到第一个非空的列。我有一张这样的桌子: ID 0 1 2 3 4 5 6 7 8 9 59 NULL NULL NULL NULL NULL NULL NULL NULL NULL text1 185
ID 0 1 2 3 4 5 6 7 8 9
59 NULL NULL NULL NULL NULL NULL NULL NULL NULL text1
185 NULL NULL NULL NULL NULL text1 text2 text3 text4 text5
428 NULL NULL NULL NULL NULL NULL text1 text2 text3 text4
53 NULL NULL NULL NULL NULL NULL NULL NULL text1 text2
452 NULL NULL NULL NULL NULL NULL NULL NULL NULL text1
267 text1 text2 text3 text4 text5 text6 text7 text8 text9 text10
ID 0 1 2 3 4 5 6 7 8 9
59 text1 NULL NULL NULL NULL NULL NULL NULL NULL NULL
185 text1 text2 text3 text4 text5 NULL NULL NULL NULL NULL
428 text1 text2 text3 text4 NULL NULL NULL NULL NULL NULL
53 text1 text2 NULL NULL NULL NULL NULL NULL NULL NULL
452 text1 NULL NULL NULL NULL NULL NULL NULL NULL NULL
267 text1 text2 text3 text4 text5 text6 text7 text8 text9 text10
CREATE FUNCTION GetCulumnsThatIsNotNull
(
@column1 VARCHAR(500),
@column2 VARCHAR(500),
@column3 VARCHAR(500),
@column4 VARCHAR(500),
@column5 VARCHAR(500),
@column6 VARCHAR(500),
@column7 VARCHAR(500),
@column8 VARCHAR(500),
@column9 VARCHAR(500),
@column10 VARCHAR(500)
)
RETURNS VARCHAR(500)
AS
BEGIN
RETURN
COALESCE(@column1,
COALESCE(@column2,
COALESCE(@column3,
COALESCE(@column4,
COALESCE(@column5,
COALESCE(@column6,
COALESCE(@column8,
COALESCE(@column9,
COALESCE(@column10,null)))))))))
END
ID 0 1 2 3 4 5 6 7 8 9
59 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
185 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
428 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
53 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
452 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
267 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
我希望输出是这样的:
ID 0 1 2 3 4 5 6 7 8 9
59 NULL NULL NULL NULL NULL NULL NULL NULL NULL text1
185 NULL NULL NULL NULL NULL text1 text2 text3 text4 text5
428 NULL NULL NULL NULL NULL NULL text1 text2 text3 text4
53 NULL NULL NULL NULL NULL NULL NULL NULL text1 text2
452 NULL NULL NULL NULL NULL NULL NULL NULL NULL text1
267 text1 text2 text3 text4 text5 text6 text7 text8 text9 text10
ID 0 1 2 3 4 5 6 7 8 9
59 text1 NULL NULL NULL NULL NULL NULL NULL NULL NULL
185 text1 text2 text3 text4 text5 NULL NULL NULL NULL NULL
428 text1 text2 text3 text4 NULL NULL NULL NULL NULL NULL
53 text1 text2 NULL NULL NULL NULL NULL NULL NULL NULL
452 text1 NULL NULL NULL NULL NULL NULL NULL NULL NULL
267 text1 text2 text3 text4 text5 text6 text7 text8 text9 text10
CREATE FUNCTION GetCulumnsThatIsNotNull
(
@column1 VARCHAR(500),
@column2 VARCHAR(500),
@column3 VARCHAR(500),
@column4 VARCHAR(500),
@column5 VARCHAR(500),
@column6 VARCHAR(500),
@column7 VARCHAR(500),
@column8 VARCHAR(500),
@column9 VARCHAR(500),
@column10 VARCHAR(500)
)
RETURNS VARCHAR(500)
AS
BEGIN
RETURN
COALESCE(@column1,
COALESCE(@column2,
COALESCE(@column3,
COALESCE(@column4,
COALESCE(@column5,
COALESCE(@column6,
COALESCE(@column8,
COALESCE(@column9,
COALESCE(@column10,null)))))))))
END
ID 0 1 2 3 4 5 6 7 8 9
59 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
185 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
428 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
53 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
452 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
267 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
ID
列每行都是唯一的
我失败的尝试是创建一个scalared函数并为每个列运行它。函数如下所示:
ID 0 1 2 3 4 5 6 7 8 9
59 NULL NULL NULL NULL NULL NULL NULL NULL NULL text1
185 NULL NULL NULL NULL NULL text1 text2 text3 text4 text5
428 NULL NULL NULL NULL NULL NULL text1 text2 text3 text4
53 NULL NULL NULL NULL NULL NULL NULL NULL text1 text2
452 NULL NULL NULL NULL NULL NULL NULL NULL NULL text1
267 text1 text2 text3 text4 text5 text6 text7 text8 text9 text10
ID 0 1 2 3 4 5 6 7 8 9
59 text1 NULL NULL NULL NULL NULL NULL NULL NULL NULL
185 text1 text2 text3 text4 text5 NULL NULL NULL NULL NULL
428 text1 text2 text3 text4 NULL NULL NULL NULL NULL NULL
53 text1 text2 NULL NULL NULL NULL NULL NULL NULL NULL
452 text1 NULL NULL NULL NULL NULL NULL NULL NULL NULL
267 text1 text2 text3 text4 text5 text6 text7 text8 text9 text10
CREATE FUNCTION GetCulumnsThatIsNotNull
(
@column1 VARCHAR(500),
@column2 VARCHAR(500),
@column3 VARCHAR(500),
@column4 VARCHAR(500),
@column5 VARCHAR(500),
@column6 VARCHAR(500),
@column7 VARCHAR(500),
@column8 VARCHAR(500),
@column9 VARCHAR(500),
@column10 VARCHAR(500)
)
RETURNS VARCHAR(500)
AS
BEGIN
RETURN
COALESCE(@column1,
COALESCE(@column2,
COALESCE(@column3,
COALESCE(@column4,
COALESCE(@column5,
COALESCE(@column6,
COALESCE(@column8,
COALESCE(@column9,
COALESCE(@column10,null)))))))))
END
ID 0 1 2 3 4 5 6 7 8 9
59 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
185 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
428 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
53 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
452 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
267 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
但是这个函数的问题是,它只是选择了第一列null
。结果如下:
ID 0 1 2 3 4 5 6 7 8 9
59 NULL NULL NULL NULL NULL NULL NULL NULL NULL text1
185 NULL NULL NULL NULL NULL text1 text2 text3 text4 text5
428 NULL NULL NULL NULL NULL NULL text1 text2 text3 text4
53 NULL NULL NULL NULL NULL NULL NULL NULL text1 text2
452 NULL NULL NULL NULL NULL NULL NULL NULL NULL text1
267 text1 text2 text3 text4 text5 text6 text7 text8 text9 text10
ID 0 1 2 3 4 5 6 7 8 9
59 text1 NULL NULL NULL NULL NULL NULL NULL NULL NULL
185 text1 text2 text3 text4 text5 NULL NULL NULL NULL NULL
428 text1 text2 text3 text4 NULL NULL NULL NULL NULL NULL
53 text1 text2 NULL NULL NULL NULL NULL NULL NULL NULL
452 text1 NULL NULL NULL NULL NULL NULL NULL NULL NULL
267 text1 text2 text3 text4 text5 text6 text7 text8 text9 text10
CREATE FUNCTION GetCulumnsThatIsNotNull
(
@column1 VARCHAR(500),
@column2 VARCHAR(500),
@column3 VARCHAR(500),
@column4 VARCHAR(500),
@column5 VARCHAR(500),
@column6 VARCHAR(500),
@column7 VARCHAR(500),
@column8 VARCHAR(500),
@column9 VARCHAR(500),
@column10 VARCHAR(500)
)
RETURNS VARCHAR(500)
AS
BEGIN
RETURN
COALESCE(@column1,
COALESCE(@column2,
COALESCE(@column3,
COALESCE(@column4,
COALESCE(@column5,
COALESCE(@column6,
COALESCE(@column8,
COALESCE(@column9,
COALESCE(@column10,null)))))))))
END
ID 0 1 2 3 4 5 6 7 8 9
59 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
185 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
428 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
53 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
452 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
267 text1 text1 text1 text1 text1 text1 text1 text1 text1 text1
有什么建议吗
编辑
这是行不通的
COALESCE(pvt.[0],
pvt.[1],
pvt.[2],
pvt.[3],
pvt.[4],
pvt.[5],
pvt.[6],
pvt.[7],
pvt.[8],
pvt.[9])
因为它将产生相同的输出我将规范化视图、CTE或其他内容中的数据,然后运行普通透视。这样,如果您真的规范化了表,您将能够重用代码
-- Setup test data
declare @texts table (
ID int not null primary key
, Col0 varchar(10) null
, Col1 varchar(10) null
, Col2 varchar(10) null
, Col3 varchar(10) null
, Col4 varchar(10) null
, Col5 varchar(10) null
, Col6 varchar(10) null
, Col7 varchar(10) null
, Col8 varchar(10) null
, Col9 varchar(10) null
)
insert into @texts select 59, NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL, 'text1'
insert into @texts select 185, NULL, NULL, NULL, NULL, NULL, 'text1', 'text2', 'text3', 'text4', 'text5'
insert into @texts select 428, NULL, NULL, NULL, NULL, NULL, NULL, 'text1', 'text2', 'text3', 'text4'
insert into @texts select 53, NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL, 'text1', 'text2'
insert into @texts select 452, NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL, 'text1'
insert into @texts select 267, 'text1', 'text2', 'text3', 'text4', 'text5', 'text6', 'text7', 'text8', 'text9', 'text10'
-- Normalize and get new column in a CTE
;with cte as (
select *
, row_number() over (partition by ID order by Col) - 1 as NewCol
from (
select ID, 0 as Col
, (select Col0 from @texts where ID = a.ID) as Val
from @texts a
union all
select ID, 1 as Col
, (select Col1 from @texts where ID = a.ID) as Val
from @texts a
union all
select ID, 2 as Col
, (select Col2 from @texts where ID = a.ID) as Val
from @texts a
union all
select ID, 3 as Col
, (select Col3 from @texts where ID = a.ID) as Val
from @texts a
union all
select ID, 4 as Col
, (select Col4 from @texts where ID = a.ID) as Val
from @texts a
union all
select ID, 5 as Col
, (select Col5 from @texts where ID = a.ID) as Val
from @texts a
union all
select ID, 6 as Col
, (select Col6 from @texts where ID = a.ID) as Val
from @texts a
union all
select ID, 7 as Col
, (select Col7 from @texts where ID = a.ID) as Val
from @texts a
union all
select ID, 8 as Col
, (select Col8 from @texts where ID = a.ID) as Val
from @texts a
union all
select ID, 9 as Col
, (select Col9 from @texts where ID = a.ID) as Val
from @texts a
) as b
where b.Val is not null
)
-- Run a pivot of the CTE
select ID
, (select Val from cte where ID = a.ID and NewCol = 0) as Col0
, (select Val from cte where ID = a.ID and NewCol = 1) as Col1
, (select Val from cte where ID = a.ID and NewCol = 2) as Col2
, (select Val from cte where ID = a.ID and NewCol = 3) as Col3
, (select Val from cte where ID = a.ID and NewCol = 4) as Col4
, (select Val from cte where ID = a.ID and NewCol = 5) as Col5
, (select Val from cte where ID = a.ID and NewCol = 6) as Col6
, (select Val from cte where ID = a.ID and NewCol = 7) as Col7
, (select Val from cte where ID = a.ID and NewCol = 8) as Col8
, (select Val from cte where ID = a.ID and NewCol = 9) as Col9
from cte a
group by ID
order by ID
试试看这里的第一个例子似乎就是您想要的。这表明数据结构不好。如果您的数据元素具有相同的含义(看起来是这样的)(即0-9都表示类似的内容),则应该对其进行规范化,在这种情况下,这样的查询将非常简单。使用
值可以在SQL Server 2008上工作。替换为SQL Server 2005中的select C0,0 union all select C1,1….
。