Tsql 使用带有groupby的CASE
我在T-SQL中有以下查询:Tsql 使用带有groupby的CASE,tsql,group-by,case,Tsql,Group By,Case,我在T-SQL中有以下查询: SELECT dbo.table2.device, dbo.table2.CREATETIME AS create_time, CASE WHEN dbo.table1.ACTIONID = 1 THEN dbo.table1.startstop END AS start_time, CASE WHEN dbo.table1.ACTIONID = 2 THEN dbo.table1.start
SELECT dbo.table2.device,
dbo.table2.CREATETIME AS create_time,
CASE WHEN dbo.table1.ACTIONID = 1
THEN dbo.table1.startstop
END AS start_time,
CASE WHEN dbo.table1.ACTIONID = 2
THEN dbo.table1.startstop
END AS stop_time,
dbo.table2.collect_time
FROM dbo.table2
JOIN dbo.table1 ON dbo.table1.CREATETIME = dbo.table2.CREATETIME;
…这给了我一个包含多行的结果表,每一行都有一个重复的开始时间-结束时间(sql时间-为简单起见缩短)-另一行为空-例如:
device | create_time | start_time | stop_time | collect_time
1 | 0000001 | 0000001 | NULL | 0000001
1 | 0000001 | NULL | 0000002 | 0000001
我想将这两行(以create_time作为ID)分组,以便将它们放在一行中。。。。谢谢 您可以聚合(SUM
)这些列:
SELECT dbo.table2.device,
dbo.table2.CREATETIME AS create_time,
SUM(CASE WHEN dbo.table1.ACTIONID = 1
THEN dbo.table1.startstop ELSE 0
END) AS start_time,
SUM(CASE WHEN dbo.table1.ACTIONID = 2
THEN dbo.table1.startstop ELSE 0
END) AS stop_time,
dbo.table2.collect_time
FROM dbo.table2
JOIN dbo.table1 ON dbo.table1.CREATETIME = dbo.table2.CREATETIME
GROUP BY dbo.table2.device, dbo.table2.CREATETIME, dbo.table2.collect_time;
此外,我认为使用子查询也会奏效
SELECT
X.Device
,sum(X.start_time)
,sum(X.stop_time)
,X.collect_time
from(
SELECT dbo.table2.device,
dbo.table2.CREATETIME AS create_time,
CASE WHEN dbo.table1.ACTIONID = 1
THEN dbo.table1.startstop
END AS start_time,
CASE WHEN dbo.table1.ACTIONID = 2
THEN dbo.table1.startstop
END AS stop_time,
dbo.table2.collect_time
FROM dbo.table2
JOIN dbo.table1 ON dbo.table1.CREATETIME = dbo.table2.CREATETIME) AS X
group by
X.Device, X.collect_time
我可能会比较这两个版本的性能。。。谢谢你的意见!