Tsql 合并2行

我有一个这样的结果集。我想合计支付的金额，并将DTV拖车和平板组合成一排。我有什么办法可以完成吗

CaseServiceID   PurchaseOrderID PaidAmount  DTV TOW FLATBED
227                 15000227    19.20           1   0
227                 15000227    45.00           0   1

注：

DTV-TOW

和

flattbed

列来自数据透视表

编辑

Pivot如下所示：

select
*
from
(
    select
    cla.CaseServiceID
    ,cla.ServiceTypeProgKey
    ,cla.ClaimAmount
    ,cla.PaidAmount
    ,cla.ClaimQuantity
    from
    Claim cla
) as srcServiceType
pivot
(
    max(ServiceTypeProgKey) for ServiceTypeProgKey in ([FLATBED],[DTV TOW]
) as pvtServiceType

怎么样

SELECT CaseServiceID, 
       PurchaseOrderID, 
       SUM(PaidAmount) PaidAmount,
       SUM([DTV TOW]) [DTV TOW],
       SUM(FLATBED) FLATBED
FROM YourTable
GROUP BY CaseServiceID, PurchaseOrderID

怎么样

SELECT CaseServiceID, 
       PurchaseOrderID, 
       SUM(PaidAmount) PaidAmount,
       SUM([DTV TOW]) [DTV TOW],
       SUM(FLATBED) FLATBED
FROM YourTable
GROUP BY CaseServiceID, PurchaseOrderID

尝试此操作（假设PaidAmount和ClaimQuantity为bit TinyInt，不用作布尔值），否则将MAX更改为SUM：

SELECT *
FROM (
    SELECT cla.CaseServiceID,
        cla.ServiceTypeProgKey,
        SUM(cla.ClaimAmount) ClaimAmount,
        MAX(cla.PaidAmount) PaidAmount,
        MAX(cla.ClaimQuantity) ClaimQuantity
    FROM Claim cla
    GROUP BY cla.CaseServiceID,
        cla.ServiceTypeProgKey
    ) AS srcServiceType
pivot(max(ServiceTypeProgKey) FOR ServiceTypeProgKey IN (
            [FLATBED],
            [DTV TOW]
            ) AS pvtServiceType)

尝试此操作（假设PaidAmount和ClaimQuantity为bit TinyInt，不用作布尔值），否则将MAX更改为SUM：

SELECT *
FROM (
    SELECT cla.CaseServiceID,
        cla.ServiceTypeProgKey,
        SUM(cla.ClaimAmount) ClaimAmount,
        MAX(cla.PaidAmount) PaidAmount,
        MAX(cla.ClaimQuantity) ClaimQuantity
    FROM Claim cla
    GROUP BY cla.CaseServiceID,
        cla.ServiceTypeProgKey
    ) AS srcServiceType
pivot(max(ServiceTypeProgKey) FOR ServiceTypeProgKey IN (
            [FLATBED],
            [DTV TOW]
            ) AS pvtServiceType)

---

查询最终是什么样子的。我希望这对某人有帮助。谢谢

select
,sum(isnull([FLATBED], 0)) AS [FLATBED]
,sum(isnull([DTV TOW], 0)) AS [DTV TOW]
from
(
    select
    cla.ServiceTypeProgKey,
    ,sum(cla.PaidAmount) as 'PaidAmount'
    ,sum(cla.ClaimQuantity) as 'ClaimQuantity'
    ,sum(cla.PaidQuantity) as 'PaidQuantity'
    from
    Claim cla
    inner join CaseService cse on cla.CaseServiceID = cse.CaseServiceID
    group by cse.PurchaseOrderID
) as srcServiceType
pivot
(
     count(ServiceTypeProgKey) FOR ServiceTypeProgKey IN ([FLATBED],[DTV TOW])
) as pvtServiceType

…结果如何

CaseServiceID   PurchaseOrderID   PaidAmount  DTV   TOW FLATBED
227             15000227          64.20       1     1

---

查询最终是什么样子的。我希望这对某人有帮助。谢谢

select
,sum(isnull([FLATBED], 0)) AS [FLATBED]
,sum(isnull([DTV TOW], 0)) AS [DTV TOW]
from
(
    select
    cla.ServiceTypeProgKey,
    ,sum(cla.PaidAmount) as 'PaidAmount'
    ,sum(cla.ClaimQuantity) as 'ClaimQuantity'
    ,sum(cla.PaidQuantity) as 'PaidQuantity'
    from
    Claim cla
    inner join CaseService cse on cla.CaseServiceID = cse.CaseServiceID
    group by cse.PurchaseOrderID
) as srcServiceType
pivot
(
     count(ServiceTypeProgKey) FOR ServiceTypeProgKey IN ([FLATBED],[DTV TOW])
) as pvtServiceType

…结果如何

CaseServiceID   PurchaseOrderID   PaidAmount  DTV   TOW FLATBED
227             15000227          64.20       1     1

---

你能显示你的pivot查询吗？@DanAndrews，已经更新了。你能显示你的pivot查询吗？@DanAndrews，它已经更新了。ThxFYI，@AndriyM感谢您提供的信息，我总是使用TinyInts而不是bit（用于索引目的），因此其他人使用它们时我会错过问题。仅供参考，@AndriyM感谢您提供的信息，我总是使用TinyInts而不是bit（用于索引目的），因此其他人使用它们时我会错过问题。