组合并添加2个数组typescript、lodash和下划线

我有一个如下所示的对象数组：

[  
  {date: '2016-09-10', 'Post': 5, 'Pickup': 2},  
  {date: '2016-09-11', 'Post': 8, 'Pickup': 2},  
  {date: '2016-09-12', 'Post': 0, 'Pickup': 2},  
  {date: '2016-09-12', 'Post': 3, 'Pickup': 0},  
  {date: '2016-09-13', 'Post': 1, 'Pickup': 2},  
  {date: '2016-09-13', 'Post': 1, 'Pickup': 0},  
]

[  
  {date: '2016-09-10', 'Post': 5, 'Pickup': 2},  
  {date: '2016-09-11', 'Post': 8, 'Pickup': 2},  
  {date: '2016-09-12', 'Post': 3, 'Pickup': 2},  
  {date: '2016-09-13', 'Post': 2, 'Pickup': 2},  
] 

pickup = [  
      {date: '2016-09-11', 'Post': 8, 'Pickup': 2},  
      {date: '2016-09-12', 'Post': 3, 'Pickup': 0},  
      {date: '2016-09-13', 'Post': 1, 'Pickup': 0},  
    ]  

post = [  
      {date: '2016-09-10', 'Post': 5, 'Pickup': 2},  
      {date: '2016-09-12', 'Post': 0, 'Pickup': 2},  
      {date: '2016-09-13', 'Post': 1, 'Pickup': 2},  
    ]

我需要按日期组合对象，并添加post+post和PICKEP+PICKEP，如下所示：

[  
  {date: '2016-09-10', 'Post': 5, 'Pickup': 2},  
  {date: '2016-09-11', 'Post': 8, 'Pickup': 2},  
  {date: '2016-09-12', 'Post': 0, 'Pickup': 2},  
  {date: '2016-09-12', 'Post': 3, 'Pickup': 0},  
  {date: '2016-09-13', 'Post': 1, 'Pickup': 2},  
  {date: '2016-09-13', 'Post': 1, 'Pickup': 0},  
]

[  
  {date: '2016-09-10', 'Post': 5, 'Pickup': 2},  
  {date: '2016-09-11', 'Post': 8, 'Pickup': 2},  
  {date: '2016-09-12', 'Post': 3, 'Pickup': 2},  
  {date: '2016-09-13', 'Post': 2, 'Pickup': 2},  
] 

pickup = [  
      {date: '2016-09-11', 'Post': 8, 'Pickup': 2},  
      {date: '2016-09-12', 'Post': 3, 'Pickup': 0},  
      {date: '2016-09-13', 'Post': 1, 'Pickup': 0},  
    ]  

post = [  
      {date: '2016-09-10', 'Post': 5, 'Pickup': 2},  
      {date: '2016-09-12', 'Post': 0, 'Pickup': 2},  
      {date: '2016-09-13', 'Post': 1, 'Pickup': 2},  
    ]

我更喜欢lodash和/或下划线。 谢谢

我从以下两个阵列开始：

[  
  {date: '2016-09-10', 'Post': 5, 'Pickup': 2},  
  {date: '2016-09-11', 'Post': 8, 'Pickup': 2},  
  {date: '2016-09-12', 'Post': 0, 'Pickup': 2},  
  {date: '2016-09-12', 'Post': 3, 'Pickup': 0},  
  {date: '2016-09-13', 'Post': 1, 'Pickup': 2},  
  {date: '2016-09-13', 'Post': 1, 'Pickup': 0},  
]

[  
  {date: '2016-09-10', 'Post': 5, 'Pickup': 2},  
  {date: '2016-09-11', 'Post': 8, 'Pickup': 2},  
  {date: '2016-09-12', 'Post': 3, 'Pickup': 2},  
  {date: '2016-09-13', 'Post': 2, 'Pickup': 2},  
] 

pickup = [  
      {date: '2016-09-11', 'Post': 8, 'Pickup': 2},  
      {date: '2016-09-12', 'Post': 3, 'Pickup': 0},  
      {date: '2016-09-13', 'Post': 1, 'Pickup': 0},  
    ]  

post = [  
      {date: '2016-09-10', 'Post': 5, 'Pickup': 2},  
      {date: '2016-09-12', 'Post': 0, 'Pickup': 2},  
      {date: '2016-09-13', 'Post': 1, 'Pickup': 2},  
    ]

我使用了数据=u.unionBy post，pickup，'date'； 和uqby数据“日期”

您可以在结果数组中为新日期使用并创建一个新对象，或者仅添加到POST和PICKUP（如果已经有）：

var result = _.reduce(array, function (memo, el) {
  var d = _.find(memo, function(e) { return e.date === el.date });
  if (d) {
    d.Post += el.Post;
    d.Pickup += el.Pickup;
  } else {
    memo.push(_.clone(el));
  }
  return memo;
}, []);

变量数组=[ {日期：'2016-09-10'，'Post'：5'，'Picking'：2}， {日期：'2016-09-11'，'Post'：8'，'Picking'：2}， {日期：'2016-09-12'，'Post'：0'，'Pickup'：2}， {日期：'2016-09-12'，'Post'：3'，'Picking'：0}， {日期：'2016-09-13'，'Post'：1'，'Picking'：2}， {日期：'2016-09-13'，'Post'：1'，'Picking'：0} ]; 变量结果=\ u0.reducearray，函数备忘录，el{ var d=uu.findmemo，函数e{returne e.date==el.date}； 如果d{ d、 职位+=el.职位； d、 皮卡+=电动皮卡； }否则{ memo.push_.cloneel； } 返回备忘录； }, []; console.logresult；

---

@请参阅上面我的新编辑。我不熟悉lodash和下划线。如果这是一个问题，这将丢弃/覆盖数组中的原始对象。或者u.findWherememo，{date:el.date}，如果您愿意的话。