如何使用VBA查找某个范围是否包含在另一个范围中?
我在比较两个范围时遇到问题。为了简单起见,我将选取两个简单的范围如何使用VBA查找某个范围是否包含在另一个范围中?,vba,excel,range,inclusion,Vba,Excel,Range,Inclusion,我在比较两个范围时遇到问题。为了简单起见,我将选取两个简单的范围M6:M10和M6:M8,我想知道第二个范围是否包含在第一个范围内,我想做的第一件事是编写 Sub example() Dim range1, range2, inte As range Set range1 = range("M6:M10") Set range2 = range("M6:M8") Set intersec = Intersect(range1, ra
M6:M10
和M6:M8
,我想知道第二个范围是否包含在第一个范围内,我想做的第一件事是编写
Sub example()
Dim range1, range2, inte As range
Set range1 = range("M6:M10")
Set range2 = range("M6:M8")
Set intersec = Intersect(range1, range2)
If intersec = range2 Then
[if statement]
End If
End Sub
但此过程返回以下错误:
PRB:Error 13(类型不匹配)和Error 3061 w/SQL查询
所以也许我不能用这种方式使用“intersect”方法……关于如何测试范围的包含性有什么提示吗?
多谢各位 我使用它的方式如下:
If Application.Intersect(rng1, rng2) Is Nothing Then
'herecomesthecode
Else
'herecomesthecode
End if
您可以删除else或不写任何内容,这取决于您想要实现的目标。这里有一种方法:
Sub ProperSubSet()
Dim range1 As Range, range2 As Range, inte As Range
Dim r As Range
Set range1 = Range("M6:M10")
Set range2 = Range("M6:M8")
For Each r In range2
If Intersect(r, range1) Is Nothing Then
MsgBox "range2 is not a proper subset of range1"
Exit Sub
End If
Next r
MsgBox "range2 is a proper subset of range1"
End Sub
首先,将range1和range2变量声明为范围 然后,在比较intersec变量和range2变量时,使用range方法的address属性来比较内容 比如:
Sub example()
Dim range1 As Range, range2 As Range, intersec As Range
Set range1 = Range("M6:M10")
Set range2 = Range("M11:M12")
Set intersec = Intersect(range1, range2)
If Not intersec Is Nothing Then
If intersec.Address = range2.Address Then
'[CODE GOES HERE]
End If
End If
End Sub
以下是一些你可以尝试的东西:
Sub Test()
Dim R1 As Range, R2 As Range, R3 As Range
Set R1 = Application.InputBox("Select first range", , , , , , , 8)
Set R2 = Application.InputBox("Select second range", , , , , , , 8)
Set R3 = Intersect(R1, R2)
If Not R3 Is Nothing Then
If R3.Address = R1.Address Then
MsgBox "First Range is subset of second"
ElseIf R3.Address = R2.Address Then
MsgBox "Second Range is subset of first"
Else
MsgBox "Neither range contained in the other"
End If
Else
MsgBox "Ranges are disjoint"
End If
End Sub
另一个变体:
Sub ProperSubSet2()
Dim range1 As Range, range2 As Range
Set range1 = [M6:M10]
Set range2 = [M6:M8]
Set rComp = Intersect(range2, range1)
If Not rComp Is Nothing Then
If rComp.Cells.Count = range2.Cells.Count Then
MsgBox "range2 is a proper subset of range1"
Else
MsgBox "range2 is not a proper subset of range1"
End If
Else
MsgBox "Both ranges aren't intersected at all!"
End If
End Sub
可以将相交点与范围进行比较,以确定一个范围是否包含在另一个范围内。一些代码来显示这个
Sub TestExample()
Dim Range1 As Range: Set Range1 = Range("M6:M10")
Dim Range2 As Range: Set Range2 = Range("M6:M8")
MsgBox Example(Range1, Range2)
End Sub
Function Example(Range1 As Range, Range2 As Range) As Integer
Dim Overlay As Range: Set Overlay = Application.Intersect(Range1, Range2)
If Not Overlay Is Nothing Then
If Overlay.Address = Range1.Address Then Example = Example + 1
If Overlay.Address = Range2.Address Then Example = Example + 2
End If
End Function
如果没有范围完全包含在另一个范围内,则函数将返回0;如果第一个范围包含在第二个范围内,则函数将返回1;如果第二个范围包含在第一个范围内,则函数将返回2;如果范围相等,则函数将返回3,单元格数量非常大的区域(so.CountLarge,而不是.Count),那么这将起作用:
Function RangeContainsRange(BigRange As Range, SmallRange As Range) As Boolean
If BigRange.Parent Is SmallRange.Parent Then
RangeContainsRange = Application.Union(BigRange, SmallRange).Cells.CountLarge = BigRange.Cells.CountLarge
Else
RangeContainsRange = False
End If
End Function
Dim range1、range2、inte As range
将range1
和range2
声明为变体(这不是问题所在)——您提到的错误似乎与您显示的代码无关,但可能隐藏在方括号中。如果不相交,则intersect方法也不会返回任何结果,可能是个问题。你应该先检查intersect是否为空。你能确认哪一行产生了错误吗?如果intersec=range2,则怀疑它是,然后
。如果您试图确认intersec和range2完全重叠,请尝试:如果intersec.Address=range2.Address,则
。