Vba 将值复制到下一个空单元格
我想找到空单元格并复制这些值: 值:“2017年11月10日”和“是”应复制到第7行(colB和colC) 我所拥有的:Vba 将值复制到下一个空单元格,vba,excel,Vba,Excel,我想找到空单元格并复制这些值: 值:“2017年11月10日”和“是”应复制到第7行(colB和colC) 我所拥有的: Sub add_value() Dim wbA As Workbook Dim wsA As Worksheet Set wbA = ActiveWorkbook Set wsA = wbA.Worksheets("Sheet1") Dim nrow As Long nrow = 6 Do Until wsA.Range("B" & nrow).V
Sub add_value()
Dim wbA As Workbook
Dim wsA As Worksheet
Set wbA = ActiveWorkbook
Set wsA = wbA.Worksheets("Sheet1")
Dim nrow As Long
nrow = 6
Do Until wsA.Range("B" & nrow).Value = ""
wsA.Range("B" & nrow).Value = wsA.Range("B3").Value
wsA.Range("C" & nrow).Value = wsA.Range("C3").Value
Exit Sub
nrow = nrow + 1
Loop
End Sub
我的循环出现了问题,我不知道如何修复它。在找到一个空的行之前,无需在您的行中循环。可以使用以下内容替换整个子组件:
Sub add_value()
With ThisWorkbook.Worksheets("Sheet1")
.Cells(.Rows.Count, "B").End(xlUp).Offset(1, 0).Resize(1, 2).Value = .Range("B3:C3").Value
End With
End Sub
根据您的评论,要添加边框,您可以按如下方式重新组织代码:
Sub add_value()
Dim ws As Worksheet
Set ws = ThisWorkbook.Worksheets("Sheet1")
With ws.Cells(ws.Rows.Count, "B").End(xlUp).Offset(1, 0).Resize(1, 2)
.Value = ws.Range("B3:C3").Value
.Borders(xlEdgeLeft).LineStyle = xlContinuous
End With
End Sub
Sub FindFirstEmptyValue()
Dim lastRow As Long
With Worksheets("Sheet1")
lastRow = .Cells(.Rows.Count, 2).End(xlUp).Row + 1
.Cells(lastRow, 2) = .Range("B3").value
.Cells(lastRow, 3) = .Range("C3").value
End With
End Sub
我会这样做:
Sub add_value()
Dim ws As Worksheet
Set ws = ThisWorkbook.Worksheets("Sheet1")
With ws.Cells(ws.Rows.Count, "B").End(xlUp).Offset(1, 0).Resize(1, 2)
.Value = ws.Range("B3:C3").Value
.Borders(xlEdgeLeft).LineStyle = xlContinuous
End With
End Sub
Sub FindFirstEmptyValue()
Dim lastRow As Long
With Worksheets("Sheet1")
lastRow = .Cells(.Rows.Count, 2).End(xlUp).Row + 1
.Cells(lastRow, 2) = .Range("B3").value
.Cells(lastRow, 3) = .Range("C3").value
End With
End Sub
它给你最后一行,你用1递增它,在这一行你写下
B3
和C3
值。删除退出子项
?太好了,放在哪里:带Selection.Borders(xlEdgeLeft)。LineStyle=xlContinuous End with???@4est,请参阅更新--您可以如上所述将边框应用于目标范围如果B6可以为空,则需要xlUp
,而不是xlDown
--我已更新以允许出现这种情况。