Visual studio 2013 visual studio中对象属性的Typescript intellisense未显示

在我的typescript文件中，我有以下代码：

var Application = Application || {};

Application.Constants = angular.module("application.constants", []);
Application.Services = angular.module("application.services", []);
Application.Controllers = angular.module("application.controllers", []);
Application.Filters = angular.module("application.filters", []);
Application.Directives = angular.module("application.directives", []);


angular.module("application", ["application.filters", "application.services", "application.directives", "application.constants", "application.controllers"]);

var player = {};
player.intelligence = 10;
player.wisdom = 30;

if(desiredClass === "Barbarian") {
    player.strenght = 100;
} else {
    player.strength = 20;
}

Intellisense没有出现，如您所见：

但在实际生成的javascript中，这是相同的。。。我从visual studio获得了intellisense，正如您所看到的：

VisualStudioTypeScript有什么原因不能解决这个问题吗

我真的必须像这样创建自己的类型才能获得对象属性的intellisense吗

---

TypeScript不会从赋值推断类型。想一想为什么，考虑下面的代码：

var Application = Application || {};

Application.Constants = angular.module("application.constants", []);
Application.Services = angular.module("application.services", []);
Application.Controllers = angular.module("application.controllers", []);
Application.Filters = angular.module("application.filters", []);
Application.Directives = angular.module("application.directives", []);


angular.module("application", ["application.filters", "application.services", "application.directives", "application.constants", "application.controllers"]);

var player = {};
player.intelligence = 10;
player.wisdom = 30;

if(desiredClass === "Barbarian") {
    player.strenght = 100;
} else {
    player.strength = 20;
}

---

尽管它是程序中最常见的打字错误之一，但此处无法发出错误。

TypeScript不会从赋值推断类型。想一想为什么，考虑下面的代码：

var Application = Application || {};

Application.Constants = angular.module("application.constants", []);
Application.Services = angular.module("application.services", []);
Application.Controllers = angular.module("application.controllers", []);
Application.Filters = angular.module("application.filters", []);
Application.Directives = angular.module("application.directives", []);


angular.module("application", ["application.filters", "application.services", "application.directives", "application.constants", "application.controllers"]);

var player = {};
player.intelligence = 10;
player.wisdom = 30;

if(desiredClass === "Barbarian") {
    player.strenght = 100;
} else {
    player.strength = 20;
}

---

尽管这是程序中最常见的打字错误之一，但在这里无法发出错误。

因此，我在上一张图片中所做的是正确的吗，那么？我不明白你的例子是如何解释为什么TypeScript不能从赋值中推断类型的。那么，我在上一张图片中所做的是正确的吗？我不明白你的例子是如何解释为什么TypeScript不能从赋值中推断类型的。