Windows 7 蚂蚁罐头'；不能写入目录

由于以下错误，我似乎无法在tomcat 7上安装spring mvc应用程序：

BUILD FAILED C:\Users\xxxx\Work\My side projects\FreedomSpring\build.xml:106: java.io.FileNotFoundException: C:\spring (Access is denied) 我注意到，每次我进行构建、deply、deploywar和安装时，c:/spring文件夹总是被设置为只读？我试图手动更改该文件夹的权限，只是尝试从我的构建中运行install ant目标，但没有成功。build.xml成功地创建了WAR文件和文件夹，其中包含c:/spring中的二进制类文件，但它无法将其保存在tomcat7上

有什么建议吗

顺便说一下，我使用的是64位windows 7

我遵循这个指南

下面是m web.xml（如果有帮助）：

<?xml version="1.0" encoding="UTF-8"?>

<web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
         http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">

    <servlet>
        <servlet-name>FreedomSpring</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>FreedomSpring</servlet-name>
        <url-pattern>*.htm</url-pattern>
    </servlet-mapping>

    <welcome-file-list>
        <welcome-file>
      index.jsp
    </welcome-file>
    </welcome-file-list>

    <context-param>
        <param-name>log4jConfigLocation</param-name>
        <param-value>/WEB-INF/log4j.xml</param-value>
    </context-param>
    <listener>
        <listener-class>org.springframework.web.util.Log4jConfigListener</listener-class>
    </listener>

</web-app>

自由泉
org.springframework.web.servlet.DispatcherServlet
1.
自由泉
*.htm
index.jsp
log4jConfigLocation
/WEB-INF/log4j.xml
org.springframework.web.util.Log4jConfigListener

这是我的servlett.xml

<?xml version="1.0" encoding="UTF-8"?>

<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xsi:schemaLocation="http://www.springframework.org/schema/beans
       http://www.springframework.org/schema/beans/spring-beans-2.5.xsd">

  <!-- the application context definition for the springapp DispatcherServlet -->

  <bean name="/hello.htm" class="springapp.web.HelloController"/>

</beans>

那么ant如何获得写入路径的权限呢？有人吗？正如我所说，我已经编辑了c:/spring的权限，甚至关闭了UAC，但它仍然不工作？

<?xml version="1.0" encoding="UTF-8"?>

<web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
         http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">

    <servlet>
        <servlet-name>FreedomSpring</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>FreedomSpring</servlet-name>
        <url-pattern>*.htm</url-pattern>
    </servlet-mapping>

    <welcome-file-list>
        <welcome-file>
      index.jsp
    </welcome-file>
    </welcome-file-list>

    <context-param>
        <param-name>log4jConfigLocation</param-name>
        <param-value>/WEB-INF/log4j.xml</param-value>
    </context-param>
    <listener>
        <listener-class>org.springframework.web.util.Log4jConfigListener</listener-class>
    </listener>

</web-app>

<?xml version="1.0" encoding="UTF-8"?>

<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xsi:schemaLocation="http://www.springframework.org/schema/beans
       http://www.springframework.org/schema/beans/spring-beans-2.5.xsd">

  <!-- the application context definition for the springapp DispatcherServlet -->

  <bean name="/hello.htm" class="springapp.web.HelloController"/>

</beans>