Windows 在大型CSV文件中搜索和修改列

我有一些大的CSV文件，格式如下（用逗号分隔）

现在我想完成这项任务

• 第2列和第3列的倍数为100

结果应该是这样的

2014.03.11 14:59:59.146,6715.47,6715.507,0.02,0.02
2014.03.11 14:59:59.206,6715.405,6715.437,0.02,0.02
2014.03.11 14:59:59.506,6715.552,6715.589,0.02,0.02
2014.03.11 14:59:59.707,6715.581,6715.616,0.02,0.02

---

非常感谢您的帮助。谢谢

这个

awk

应该可以：

awk '{$2*=100;$3*=100}1' FS=, OFS=, file
2014.03.11 14:59:59.146,6715.47,6715.51,0.02,0.02
2014.03.11 14:59:59.206,6715.4,6715.44,0.02,0.02
2014.03.11 14:59:59.506,6715.55,6715.59,0.02,0.02
2014.03.11 14:59:59.707,6715.58,6715.62,0.02,0.02

---

您可以使用

$2=$2*100

或仅使用

$2*=100

将列乘以

100

此

awk

应执行以下操作：

awk '{$2*=100;$3*=100}1' FS=, OFS=, file
2014.03.11 14:59:59.146,6715.47,6715.51,0.02,0.02
2014.03.11 14:59:59.206,6715.4,6715.44,0.02,0.02
2014.03.11 14:59:59.506,6715.55,6715.59,0.02,0.02
2014.03.11 14:59:59.707,6715.58,6715.62,0.02,0.02

perl -F/,/ -lape "$F[$_] *= 100 for (1,2); $_ = join',', @F;" < input.csv > output.csv

您可以使用

$2=$2*100

或仅使用

$2*=100

将列乘以

100

perl-F/，/-lape“$F[$\]*=100表示（1,2）；$\=join'，，@F；”output.csv
perl -F/,/ -lape "$F[$_] *= 100 for (1,2); $_ = join',', @F;" < input.csv > output.csv

perl-F/，/-lape“$F[$\u]*=100表示（1,2）；$\uz=join'，'，@F；”output.csv

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