powershell:更改windows 7计算机上服务的启动类型
我写了一个脚本来获取一台机器的服务,我想把StartMode镜像到另一台机器上。我想不出如何实现后者:在远程机器上设置服务。以下是我迄今为止写的一个剧本:powershell:更改windows 7计算机上服务的启动类型,windows,powershell,service,Windows,Powershell,Service,我写了一个脚本来获取一台机器的服务,我想把StartMode镜像到另一台机器上。我想不出如何实现后者:在远程机器上设置服务。以下是我迄今为止写的一个剧本: #List of Issue of services $NamesOfIssueServices = "Browser", "Dhcp", "Dnscache", "dwmrcs", "iphlpsvc", "LanmanServer", "LanmanWorkstation", "MMCSS", "MpsSvc", "Netlogon",
#List of Issue of services
$NamesOfIssueServices = "Browser", "Dhcp", "Dnscache", "dwmrcs", "iphlpsvc", "LanmanServer", "LanmanWorkstation", "MMCSS", "MpsSvc", "Netlogon", "Netman", "netprofm", "NlaSvc", "nsi", "p2pimsvc","PNRPsvc","PolicyAgent", "SessionEnv", "stisvc", "W32Time", "WinHttpAutoProxySvc", "WinRM"
#get all services
$W32Services = Get-WmiObject Win32_Service
#filter wanted services
$IssueServices = $W32Services | Where-Object {$NamesOfIssueServices -contains $_.name}
#display wanted services
$IssueServices | Sort-Object name | ft Name, DisplayName, State, StartMode, StartName
如果您使用的是PowerShell v2.0,则可以通过使用cmdlet轻松做到这一点:
条件语句是由于从
StartMode
属性获取的值“Auto”
与-StartupType
参数所需的参数“Automatic”
之间不兼容。如果您使用的是PowerShell v2.0,则可以通过使用cmdlet轻松做到这一点:
条件语句是由于从
StartMode
属性获得的值“Auto”
与-StartupType
参数所期望的参数“Automatic”
之间不兼容。+1因为在win32\u服务中看到了Auto与set服务中Automatic的区别+1感谢您看到了win32_服务中的自动和set服务中的自动的区别!
foreach ($service in $issueServices) {
$startMode = $service.StartMode
if ($service.StartMode -eq "Auto") {
$startMode = "Automatic"
}
Set-Service -ComputerName TheRemoteMachine -Name $service.Name -StartupType $startMode
}