oracleplsql:如何解析XML并插入到表中
如何将嵌套的xml文件加载到数据库表中oracleplsql:如何解析XML并插入到表中,xml,oracle,plsql,insert,xml-parsing,Xml,Oracle,Plsql,Insert,Xml Parsing,如何将嵌套的xml文件加载到数据库表中 <?xml version="1.0" ?> <person> <row> <name>Tom</name> <Address> <State>California</State> <City>Los angeles</City> </Ad
<?xml version="1.0" ?>
<person>
<row>
<name>Tom</name>
<Address>
<State>California</State>
<City>Los angeles</City>
</Address>
</row>
<row>
<name>Jim</name>
<Address>
<State>California</State>
<City>Los angeles</City>
</Address>
</row>
</person>
在这个xml中,person是表名,name是文件名,Tom是它的文件值。
Address是一个子表,state和city是地址中的两列。我想将person行插入person表,如果失败,请不要插入address表。这个xml可能非常大。最好的解决方案是什么 您可以将XML文档加载到XMLType中,然后查询它,例如:
DECLARE
x XMLType := XMLType(
'<?xml version="1.0" ?>
<person>
<row>
<name>Tom</name>
<Address>
<State>California</State>
<City>Los angeles</City>
</Address>
</row>
<row>
<name>Jim</name>
<Address>
<State>California</State>
<City>Los angeles</City>
</Address>
</row>
</person>');
BEGIN
FOR r IN (
SELECT ExtractValue(Value(p),'/row/name/text()') as name
,ExtractValue(Value(p),'/row/Address/State/text()') as state
,ExtractValue(Value(p),'/row/Address/City/text()') as city
FROM TABLE(XMLSequence(Extract(x,'/person/row'))) p
) LOOP
-- do whatever you want with r.name, r.state, r.city
END LOOP;
END;
试试这个我得到了一些不同的xml树,请帮助:这可能会有帮助,但一个大问题是我可能不知道标记名,输入是动态xml,具有所有不同的表名和文件名。好吧,你需要知道标记是什么,否则,代码应该如何知道在哪里插入数据呢?我已经通过使用dbms_xmldom API解决了这个问题。感谢您的帮助,当我有多个地址标签内的it是越来越失败。我应该修改什么来循环使用相同名称的多个标记?如果要访问第一个,则xpath将类似:“./Address[1]/City”
CREATE OR REPLACE PROCEDURE ADDEMP
(xml IN CLOB)
AS
BEGIN
INSERT INTO EMPLOYEE (EMPID,EMPNAME,EMPDETAIL,CREATEDBY,CREATED)
SELECT
ExtractValue(column_value,'/ROOT/EMPID') AS EMPID
,ExtractValue(column_value,'/ROOT/EMPNAME') AS EMPNAME
,ExtractValue(column_value,'/ROOT/EMPDETAIL') AS EMPDETAIL
,ExtractValue(column_value,'/ROOT/CREATEDBY') AS CREATEDBY
,ExtractValue(column_value,'/ROOT/CREATEDDATE') AS CREATEDDATE
FROM TABLE(XMLSequence( XMLType(xml))) XMLDUMMAY;
COMMIT;
END;
select *
FROM XMLTABLE('/person/row'
PASSING
xmltype('
<person>
<row>
<name>Tom</name>
<Address>
<State>California</State>
<City>Los angeles</City>
</Address>
</row>
<row>
<name>Jim</name>
<Address>
<State>California</State>
<City>Los angeles</City>
</Address>
</row>
</person>
')
COLUMNS
--describe columns and path to them:
name varchar2(20) PATH './name',
state varchar2(20) PATH './Address/State',
city varchar2(20) PATH './Address/City'
) xmlt
;