Warning: file_get_contents(/data/phpspider/zhask/data//catemap/0/xml/14.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181

Warning: file_get_contents(/data/phpspider/zhask/data//catemap/8/xslt/3.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Xml 如何获取元素中属性的值_Xml_Xslt - Fatal编程技术网

Xml 如何获取元素中属性的值

Xml 如何获取元素中属性的值,xml,xslt,Xml,Xslt,我想从另一个元素获取属性 例如 显然,上面的XSLT不起作用,但逻辑上应该是这样的。有人能帮我吗 谢谢 只需要在XPath中@name前面加一个斜杠 只需要在XPath中@name前面加一个斜杠 <xsl:template match="tag1"> Test: <xsl:value-of select="inner[@class='test']@name"/> </xsl:template> <xml> <tag1>

我想从另一个元素获取属性

例如

显然,上面的XSLT不起作用,但逻辑上应该是这样的。有人能帮我吗

谢谢

只需要在XPath中@name前面加一个斜杠

只需要在XPath中@name前面加一个斜杠

<xsl:template match="tag1">
  Test: <xsl:value-of select="inner[@class='test']@name"/>
</xsl:template>
<xml>
  <tag1>
    <inner class="something" name="123"/>
    <inner class="test" name="456"/>
  </tag1>
</xml>
Test: 456
<xsl:value-of select="inner[@class='test']/@name"/>