XPath 1-后一个同级与前一个同级之间的独占同级匹配（非贪婪匹配）

在这辆车上，我的头撞到了车内表面：

<table class="magic">
  <tbody>
    <!-- previous sections here -->

    <!-- uninteresting section example begin -->
    <tr class="head">
      <th colspan="2">Spain</th>
    </tr>
    <!-- ... -->
    <tr class="section-break"></tr>
    <!-- uninteresting section example end -->

    <!-- begin interesting section (position not fixed) -->
    <tr class="head">
      <th colspan="2">United States</th>
    </tr>
    <tr></tr>  <!-- match here begin (length not fixed) -->
    <tr></tr> 
    <!-- ... -->
    <tr></tr>  <!-- match here end -->
    <tr class="section-break"></tr>
    <!-- end interesting section -->

    <!-- next sections -->
    <!-- ... -->
    <tr class="section-break"></tr>
    <!-- ... -->
    <tr class="section-break"></tr>
    <!-- ... -->
  </tbody>
<table>

---

但是如何在

美国之后找到第一个
分节符
？
可以将
/th[包含（，“美国”）]
替换为
th=“美国”
。
//table[@class="magic"]//tr[@class="head"  and ./th[contains(., "United States")]]/following-sibling::tr[@class="section-break"][1]

//table[@class="magic"]//tr[@class="head"  and ./th[contains(., "United States")]]/following-sibling::tr[@class="section-break"][1]