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Amazon web services AWS Opsworks-忽略自定义厨师属性_Amazon Web Services_Chef Infra_Aws Opsworks - Fatal编程技术网

Amazon web services AWS Opsworks-忽略自定义厨师属性

Amazon web services AWS Opsworks-忽略自定义厨师属性,amazon-web-services,chef-infra,aws-opsworks,Amazon Web Services,Chef Infra,Aws Opsworks,我在/deploy/attributes/rails\u stack.rb中处理了一个新的堆栈名 如果我尝试使用它,它会失败,错误堆栈跟踪指向默认opsworks rails_堆栈中的一行,而不是我的 我在这里看到了原件的副本: /var/lib/aws/opsworks/cache.stage1 /opt/aws/opsworks/releases/20170401093533_3444-20170401093533/cookbooks/deploy/attributes/rails_stac

我在/deploy/attributes/rails\u stack.rb中处理了一个新的堆栈名

如果我尝试使用它,它会失败,错误堆栈跟踪指向默认opsworks rails_堆栈中的一行,而不是我的

我在这里看到了原件的副本:
/var/lib/aws/opsworks/cache.stage1

/opt/aws/opsworks/releases/20170401093533_3444-20170401093533/cookbooks/deploy/attributes/rails_stack.rb

我在这里看到了我的:
/var/lib/aws/opsworks/cache.stage2

/opt/aws/opsworks/releases/20170401093533_3444-20170401093533/merged cookbook/deploy/attributes/rails_stack.rb

/opt/aws/opsworks/releases/20170401093533_3444-20170401093533/site cookbook/deploy/attributes/rails_stack.rb

文件表明它应该使用我的


为什么不呢?

您可以发布堆栈跟踪和尽可能多的rails\u stack.rb细节吗?您可以发布堆栈跟踪和尽可能多的rails\u stack.rb细节吗