Amazon web services 如何在cloudformation中将参数从主模板发送到子模板

我试图从一个用户那里获取两个参数，然后将其传递给我在主模板中寻址的模板。在我的主模板中，我有：

{
"Parameters": {
    "appName": {
        "Description": "enter the app name",
        "Type": "String",
        "Default": "bn-test-jun"
    },
    "appEnv": {
        "Description": "enter the app name",
        "Type": "String",
        "Default": "bn-test-jun"
    }
},
"Resources": {
    "CodeDeployEC2InstancesStack": {
        "Type": "AWS::CloudFormation::Stack",
        "Properties": {
            "TemplateURL": "https://s3.amazonaws.com/............../beanstalk.json",
            "TimeoutInMinutes": "60"
        }
    },
    "myS3": {
        "Type": "AWS::S3::Bucket",
        "Properties": {
            "AccessControl": "PublicRead",
            "BucketName": "ssssssss-test"
        }
    }
}
}

正如您所看到的，我正在处理beanstalk模板，并且我得到了我将要创建的beanstalk的环境和应用程序的名称，因此我需要将这些变量传递给beanstalk模板。以下是我的beanstalk模板：

{
"AWSTemplateFormatVersion": "2010-09-09",
"Parameters": {
    "appName": {
        "Description": "enter the app name",
        "Type": "String",
        "Default": "bn-test-jun"
    },
    "appEnv": {
        "Description": "enter the app name",
        "Type": "String",
        "Default": "bn-test-jun"
    }
},
"Resources": {
    "sampleApplication": {
        "Type": "AWS::ElasticBeanstalk::Application",
        "Properties": {
            "Description": "AWS Elastic Beanstalk Sample Application",
            "ApplicationName": {
                "Ref": "appName"
            }
        }
    },
    "sampleApplicationVersion": {
        "Type": "AWS::ElasticBeanstalk::ApplicationVersion",
        "Properties": {
            "ApplicationName": {
                "Ref": "sampleApplication"
            },
            "Description": "AWS ElasticBeanstalk Sample Application Version",
            "SourceBundle": {
                "S3Bucket": "hamed-test-war",
                "S3Key": "deployment.war"
            }
        }
    },
    "sampleConfigurationTemplate": {
        "Type": "AWS::ElasticBeanstalk::ConfigurationTemplate",
        "Properties": {
            "ApplicationName": {
                "Ref": "sampleApplication"
            },
            "Description": "AWS ElasticBeanstalk Sample Configuration Template",
            "OptionSettings": [{
                    "Namespace": "aws:autoscaling:asg",
                    "OptionName": "MinSize",
                    "Value": "2"
                },
                {
                    "Namespace": "aws:autoscaling:asg",
                    "OptionName": "MaxSize",
                    "Value": "3"
                },
                {
                    "Namespace": "aws:elasticbeanstalk:environment",
                    "OptionName": "EnvironmentType",
                    "Value": "LoadBalanced"
                }
            ],
            "SolutionStackName": "64bit Amazon Linux 2017.03 v2.6.1 running Tomcat 8 Java 8"
        }
    },
    "sampleEnvironment": {
        "Type": "AWS::ElasticBeanstalk::Environment",
        "Properties": {
            "ApplicationName": {
                "Ref": "sampleApplication"
            },
            "Description": "AWS ElasticBeanstalk Sample Environment",
            "TemplateName": {
                "Ref": "sampleConfigurationTemplate"
            },
            "VersionLabel": {
                "Ref": "sampleApplicationVersion"
            },
            "EnvironmentName": {
                "Ref": "appEnv"
            }
        }
    }
},
"Outputs": {
    "applicationName11": {
        "Description": "The application chosen by user is :",
        "Value": {
            "Ref": "appEnv"
        }
    }
}

}

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正如您所看到的，我试图使用Ref-appname来获取变量，但这不起作用，因为中的appname仅在父模板中可用。因此，我正在寻找将参数发送到beanstalk.template的方法。可以这样做吗？

似乎您正在使用嵌套堆栈来拉入模板。如果是，则可以使用Parameters属性将参数传递到子模板，如下所示：

{
   "AWSTemplateFormatVersion" : "2010-09-09",
   "Resources" : {
      "myStackWithParams" : {
         "Type" : "AWS::CloudFormation::Stack",
         "Properties" : {
            "TemplateURL" : "https://s3.amazonaws.com/cloudformation-templates-us-east-1/EC2ChooseAMI.template",
            "Parameters" : {
               "InstanceType" : "t1.micro",
               "KeyName" : "mykey"
            }
         }
      }
   }
}

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是的，太棒了。非常感谢。工作得很好。你也来看看这个。我真的被这件事困住了，我无法前进：