如何在我的案例中比较字符串（android）

我有两个字符串，我用这个代码得到它们

final String encrypted_id = encryption.encryptOrNull(android_id);
final String preLoad = preferences.getString("pur", "no");

为了确保它们相等，我这样记录它们

Log.d("encrypted_id",encrypted_id);
Log.d("preferences.getString",preferences.getString("pur", "no"));

         D/encrypted_id﹕ wxgNDxqzNWNgYWrE0fxjaU07a54XBFnAToy56MAV1Y0=
D/preferences.getString﹕ wxgNDxqzNWNgYWrE0fxjaU07a54XBFnAToy56MAV1Y0=

if(preLoad.equals(encrypted_id))
    {
        Log.d("app","is premium");

    }
    else {
        Log.d("app","is not premium");
    }

LogCat的输出是这样的

Log.d("encrypted_id",encrypted_id);
Log.d("preferences.getString",preferences.getString("pur", "no"));

         D/encrypted_id﹕ wxgNDxqzNWNgYWrE0fxjaU07a54XBFnAToy56MAV1Y0=
D/preferences.getString﹕ wxgNDxqzNWNgYWrE0fxjaU07a54XBFnAToy56MAV1Y0=

if(preLoad.equals(encrypted_id))
    {
        Log.d("app","is premium");

    }
    else {
        Log.d("app","is not premium");
    }

所以我确保他们是平等的

现在我想这样比较它们

Log.d("encrypted_id",encrypted_id);
Log.d("preferences.getString",preferences.getString("pur", "no"));

         D/encrypted_id﹕ wxgNDxqzNWNgYWrE0fxjaU07a54XBFnAToy56MAV1Y0=
D/preferences.getString﹕ wxgNDxqzNWNgYWrE0fxjaU07a54XBFnAToy56MAV1Y0=

if(preLoad.equals(encrypted_id))
    {
        Log.d("app","is premium");

    }
    else {
        Log.d("app","is not premium");
    }

但是给我看看这个

D/app﹕ is not premium

有什么问题吗

PS：我试过了

1。预加载.equalsIgnoreCase（加密的\u id）

2。预加载。比较（加密的\u id）==0

if(preLoad.equals(encrypted_id))
    {
        Log.d("app","is premium");

    }
    else {
        Log.d("app","is not premium");
    }

到

试试这个

if(!preLoad.trim().equals(encrypted_id.trim()))
{
    Log.d("app","is not premium");

}
else {
    Log.d("app","is premium");
}

您可以尝试以下方法：

if(stringsCompare(preLoad.trim(),encrypted_id.trim()))
    {
        Log.d("app","is premium");

    }
    else {
        Log.d("app","is not premium");
    }

stringsCompare是我为字符串比较编写的一个过程：

    public boolean stringsCompare(String firstString, String secondString){
            if(firstString.length() != secondString.length()){
                //The length of the two strings are not equal
                return false;
            }else{
                for(int i = 0; i < firstString.length(); i++)
                {
                    if (firstString.charAt(i) != secondString.charAt(i))
                    {
                        //Let's log the difference:
                        Log.d("app","Difference at char: "+i+" its value in the first string is: "+firstString.charAt(i)+" and its value in the first string is: "+secondString.charAt(i));
                        //The strings are not equal
                        return false;
                    }
                }
                //All characters were equal
                return true;
            }
}

public boolean字符串比较（String firstString，String secondString）{
if（firstString.length（）！=secondString.length（））{
//这两个字符串的长度不相等
返回false；
}否则{
for（int i=0；i

在这种情况下，如果存在差异，您可以看到差异。
您是否尝试过预加载.trim（）.equals（加密的\u id.trim（））？？是否可以在else中打印
加密的\u id
和
预加载
？使用equalignore大小写并使用trim（），然后检查如果比较
预加载.equals，会发生什么(“wxgNDxqzNWNgYWrE0fxjaU07a54XBFnAToy56MAV1Y0=”）
和
加密的_id.equals（“wxgndxqzngywre0fxjau07a54xbfNatoy56mav1y0=”）
@user3676184 equalignore对他的代码不是必需的，id必须是唯一的谢谢。但我认为使用equals和trim更容易。没问题，你可以把它作为额外的答案：）