android的web服务客户端

我使用本教程在eclipse中编写了一个简单的Web服务。现在我必须为这个web服务编写客户端。 这是我的代码：

public class MainActivity extends Activity {
/** Called when the activity is first created. */
private static final String SOAP_ACTION = "http://wsServer.myfirst.com/getGreeting";
private static final String METHOD_NAME = "getGreeting";
private static final String NAMESPACE = "http://wsServer.myfirst.com/";
private static final String URL = "http://10.0.2.2:8080/wsServerExample?wsdl";

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    try {
        SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
        request.addProperty("arg0","Nicola");            

        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
        envelope.setOutputSoapObject(request);

        HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);           

        androidHttpTransport.call(SOAP_ACTION, envelope);
        SoapObject response = (SoapObject)envelope.getResponse();
        String r =  (response.getProperty(0).toString());           
    }
    catch (Exception e) {
        System.out.println(e.getMessage());
    }
    }

当执行“SoapObject response=（SoapObject）envelope.getResponse（）；”时，我有一个异常“org.ksoap2.serialization.SoapPrimitive”，并且我有以下消息：

com.sun.xml.internal.ws.transport.http.HttpAdapter fixQuotesAroundSoapAction
Received WS-I BP non-conformant Unquoted SoapAction HTTP header: http://ws.myfirst.com/getGreeting/

问题在哪里？ 这是我的web服务的代码： SayHello.java

package com.myfirst.wsServer;
import javax.jws.WebService;

@WebService
public class SayHello { 
    private static final String SALUTATION = "Hello"; 
public String getGreeting( String name ) { 
    return SALUTATION + " " + name; 
}
public String get() { 
    return "ciao!"; 
}
}

RunService.java

package com.myfirst.wsServer;
import javax.xml.ws.Endpoint;

public class RunService { 
public static void main(String[] args) { 
    System.out.println("SayHello Web Service started."); 
    Endpoint.publish("http://localhost:8080/wsServerExample", new SayHello()); 
}
}

GetGreeting.java

package com.myfirst.wsServer.jaxws;

import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlType;

@XmlRootElement(name = "getGreeting", namespace = "http://wsServer.myfirst.com/")
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "getGreeting", namespace = "http://wsServer.myfirst.com/")
public class GetGreeting {
    @XmlElement(name = "arg0", namespace = "")
    private String arg0;

    public String getArg0() {
        return this.arg0;
    }

    public void setArg0(String arg0) {
        this.arg0 = arg0;
    }
}

GetGreetingResponse.java

package com.myfirst.wsServer.jaxws;

import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlType;

@XmlRootElement(name = "getGreetingResponse", namespace = "http://wsServer.myfirst.com/")
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "getGreetingResponse", namespace = "http://wsServer.myfirst.com/")
public class GetGreetingResponse {

    @XmlElement(name = "return", namespace = "")
    private String _return;

    public String getReturn() {
        return this._return;
    }

    public void setReturn(String _return) {
        this._return = _return;
    }
}

试试这个。（添加了行

envelope.dotNet=true；

）

---

在这种情况下，您能告诉我您的服务在WSDL中的定义吗？也许把它附在问题本身上？：）以及用于定义服务的java代码。可能有两个问题。您的请求转换会弹出一些不需要的字符，这会破坏SOAP\u操作。另外，可能是您在@WebParam中缺少targetNamespace属性。我不太确定这一点，但getGreetingResponse.java中@XmlElement（name=“return”，namespace=”“）这一行的namespace字段是否应该留空？如果我更改它，情况也是一样的

SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet = true;
envelope.setOutputSoapObject(request);