Android在服务方法中显示通知

感谢您阅读我的问题。
我编写了一个简单的应用程序，向运行后台的服务显示通知：
我将其写入服务类以显示简单通知：

NotificationCompat.Builder mBuilder =   new NotificationCompat.Builder(getBaseContext())
                        .setSmallIcon(R.drawable.maleki) // notification icon
                        .setContentTitle("آذر گشت") // title for notification
                        .setContentText("شما"+" "+jsonArray.length()+" "+"خبر جدید دارید") // message for notification
                        .setAutoCancel(true); // clear notification after click

但不要给我看通知，会发生什么事？谢谢

我的完整服务类别代码为：

public class newsservice extends Service {
    @Override
    public int onStartCommand(Intent intent, int flags, int startId) {
        // your code
        new HttpAsyncTask().execute("http://tour.maxitem.org/newslenght.aspx");
        //this.stopSelf();

        return Service.START_FLAG_REDELIVERY;
    }

    @Override
    public IBinder onBind(Intent intent) {
        return null;
    }
    //************************************************************
    //***************************************AsyncTask

    private class HttpAsyncTask extends AsyncTask<String, Void, String> {
        @Override
        protected String doInBackground(String... urls) {

            TourMyCountry country=new TourMyCountry();
            country.id="jamalnews";//.setName(etName.getText().toString());
            return POST(urls[0],country);
        }
        // onPostExecute displays the results of the AsyncTask.
        // onPostExecute displays the results of the AsyncTask.
        @Override
        protected void onPostExecute(String result) {


            try {
                JSONArray jsonArray=new JSONArray(result);
                /*for(int i=0;i<jsonArray.length();i++)
                {
                    JSONObject JsonObj=jsonArray.getJSONObject(i);
                    String countryname=JsonObj.getString("countryname");

                }*/

                /*NotificationCompat.Builder mBuilder =   new NotificationCompat.Builder(getBaseContext())
                        .setSmallIcon(R.drawable.maleki) // notification icon
                        .setContentTitle("آذر گشت") // title for notification
                        .setContentText("شما"+" "+jsonArray.length()+" "+"خبر جدید دارید") // message for notification
                        .setAutoCancel(true); // clear notification after click*/

            } catch (JSONException e) {
                e.printStackTrace();
            }

        }
    }//END OF ASYNCTASK

    //**************************************POST LEVEL
    public static String POST(String url, TourMyCountry myCountry){
        InputStream inputStream = null;
        String result = "";
        try {
            // 1. create HttpClient
            HttpClient httpclient = new DefaultHttpClient();
            // 2. make POST request to the given URL
            HttpPost httpPost = new HttpPost(url);
            String json = "";
            // 3. build jsonObject
            JSONObject jsonObject = new JSONObject();
            jsonObject.accumulate("id", myCountry.id);
            // 4. convert JSONObject to JSON to String
            json = jsonObject.toString();
            // 5. set json to StringEntity
            StringEntity se = new StringEntity(json);

            // 6. set httpPost Entity
            httpPost.setEntity(se);

            // 7. Set some headers to inform server about the type of the content
            httpPost.setHeader("Accept", "application/json");
            httpPost.setHeader("Content-type", "application/json");

            // 8. Execute POST request to the given URL
            HttpResponse httpResponse = httpclient.execute(httpPost);

            // 9. receive response as inputStream
            inputStream = httpResponse.getEntity().getContent();

            // 10. convert inputstream to string
            if(inputStream != null)
                result = convertInputStreamToString(inputStream);
            else
                result = "Did not work!";
            Log.d("behzad in the service:",result);

        } catch (Exception e) {
            Log.d("InputStream", e.getLocalizedMessage());
        }

        // 11. return result
        return result;
    }//END OF POST BACK TO RETURN

    //************************************************convertInputStreamToString
    private static String convertInputStreamToString(InputStream inputStream) throws IOException {
        BufferedReader bufferedReader = new BufferedReader( new InputStreamReader(inputStream));
        String line = "";
        String result = "";
        while((line = bufferedReader.readLine()) != null)
            result += line;

        inputStream.close();
        return result;

    }
    //***************************************************************


    public class TourMyCountry{
        String id;
    }

}

公共类新闻服务扩展服务{
@凌驾
公共int onStartCommand（Intent Intent、int标志、int startId）{
//你的代码
新建HttpAsyncTask（）。执行（“http://tour.maxitem.org/newslenght.aspx");
//这个。stopSelf（）；
退货服务。开始\标志\重新交付；
}
@凌驾
公共IBinder onBind（意向）{
返回null；
}
//************************************************************
//***************************************异步任务
私有类HttpAsyncTask扩展了AsyncTask{
@凌驾
受保护的字符串doInBackground（字符串…URL）{
TourMyCountry国家=新TourMyCountry（）；
country.id=“jamalnews”//.setName（etName.getText（）.toString（））；
回帖（URL[0]，国家）；
}
//onPostExecute显示异步任务的结果。
//onPostExecute显示异步任务的结果。
@凌驾
受保护的void onPostExecute（字符串结果）{
试一试{
JSONArray JSONArray=新JSONArray（结果）；
/*对于（int i=0；i试试这个

NotificationManager mNotifyMgr = (NotificationManager)   getSystemService(Context.NOTIFICATION_SERVICE);

// your code for notification builder
mNotifyMgr.notify(1, mBuilder.build());

我看不到实际设置通知的方法。它应该如下所示：

mBuilder.setContentIntent(resultPendingIntent);
NotificationManager mNotificationManager =
    (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);
// mId allows you to update the notification later on.
mNotificationManager.notify(mId, mBuilder.build());

查看此链接，该链接描述了如何发送通知：

总而言之，您的代码不完整。
您包含的源代码不够。请共享更多信息，例如您必须实际显示通知的呼叫。请包含更多代码，或者我建议在没有足够信息的情况下关闭此呼叫。@Booger I update questionyou have call notify（）方法，它在哪里？@davidjons我怎么能称之为？为什么您的服务类中有一个AsyncTask？！这已经脱离UI线程，所以您不需要或不想要它。