无法从android中的自定义listview获取所选项目

我已经使用基本适配器创建了一个自定义列表视图。我想从listview中获取所选项目。我尝试过不同的解决方案，但都不管用。我的ListView代码如下所示：

class SingleRow {
        String mFetchedJobTitle;
        String mFetchedCompanyName;
        String mFetchedExperience;
        String mFetchedLocation;


        SingleRow(String mFetchedJobTitle, String mFetchedCompanyName, String mFetchedExperience, String mFetchedLocation) {
            this.mFetchedJobTitle = mFetchedJobTitle;
            this.mFetchedCompanyName = mFetchedCompanyName;
            this.mFetchedExperience = mFetchedExperience;
            this.mFetchedLocation = mFetchedLocation;

        }
    }

    class MyAdapter extends BaseAdapter {

        ArrayList<SingleRow> list;
        Context context;

        MyAdapter(Context c) {
            context = c;

            list = new ArrayList<SingleRow>();
            String[] mFetchedJobTitle1 = searchJobTitle;
            String[] mFetchedCompanyName1 = searchCompanyName;
            String[] mFetchedExperience1 = searchExperience;
            String[] mFetchedLocation1 = searchLocation;

            for (int i = 0; i < mArrayLength; i++) {

                list.add(new SingleRow(mFetchedJobTitle1[i], mFetchedCompanyName1[i], mFetchedExperience1[i], mFetchedLocation1[i] ));

            }

        }

        @Override
        public int getCount() {
            return list.size();
        }

        @Override
        public Object getItem(int position) {
            return list.get(position);
        }

        @Override
        public long getItemId(int position) {
            return position;
        }

        @Override
        public View getView(int position, View convertView, ViewGroup parent) {

            LayoutInflater inflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
            View row = inflater.inflate(R.layout.custom_search_row, parent, false);

            TextView title = (TextView) row.findViewById(R.id.textViewJobTitle);
            TextView companyName = (TextView) row.findViewById(R.id.textViewCompanyName);
            TextView experience = (TextView) row.findViewById(R.id.textViewExperience);
            TextView location = (TextView) row.findViewById(R.id.textViewLocation);


            SingleRow temp = list.get(position);
            title.setText(temp.mFetchedJobTitle);
            companyName.setText(temp.mFetchedCompanyName);
            experience.setText(temp.mFetchedExperience);
            location.setText(temp.mFetchedLocation);


            return row;
        }
    }

---

如何获得准确的字符串值。谁能给我提个建议吗。欢迎所有建议。

明白了，在您的每个列表项中，您将获得一个

单行

类实例。 喜欢吗

 mListView.getItemAtPosition(i).mFetchedJobTitle;

试试这个

    SingleRow mSelectedItem =  mListView.getItemAtPosition(i);       
    String mFetchedJobTitle = mSelectedItem.mFetchedJobTitle;
    String mFetchedCompanyName = mSelectedItem.mFetchedCompanyName;
    String mFetchedExperience = mSelectedItem.mFetchedExperience;
    String mFetchedLocation = mSelectedItem.mFetchedLocation;

---

getSelectedItem（）返回对象的引用，并在将其转换为字符串时返回包含类名和存储对象的内存位置的字符串。要获取所选项目，可以使用此方法

public Object getItem(int position) {
        return list.get(position);
    } 

---

mSelectedItem

    SingleRow mSelectedItem =  mListView.getItemAtPosition(i);       
    String mFetchedJobTitle = mSelectedItem.mFetchedJobTitle;
    String mFetchedCompanyName = mSelectedItem.mFetchedCompanyName;
    String mFetchedExperience = mSelectedItem.mFetchedExperience;
    String mFetchedLocation = mSelectedItem.mFetchedLocation;

public Object getItem(int position) {
        return list.get(position);
    }