Android 将XML资源传递给XMLReader

Android 将XML资源传递给XMLReader,android,xml,xml-parsing,sax,xmlreader,Android,Xml,Xml Parsing,Sax,Xmlreader,我试图将.xml文件从我的res文件夹传递到XMLReader,以便将其解析为对象: private void parseXML() { String parsedData = ""; try { Log.w("AndroidParseXMLActivity", "Start"); /** Handling XML */ SAXParserFactory spf = SAXParserFactory.newI

我试图将
.xml
文件从我的
res
文件夹传递到
XMLReader
,以便将其解析为对象:

private void parseXML() {
    String parsedData = "";
       try {
           Log.w("AndroidParseXMLActivity", "Start");
           /** Handling XML */
           SAXParserFactory spf = SAXParserFactory.newInstance();
           SAXParser sp = spf.newSAXParser();
           XMLReader xr = sp.getXMLReader();

           QuestionXMLHandler myXMLHandler = new QuestionXMLHandler();
           xr.setContentHandler(myXMLHandler);
           InputSource inStream = new InputSource();
           Log.w("AndroidParseXMLActivity", "Parse1");

           inStream.setCharacterStream(new StringReader(getResources().getXml(R.xml.questions).toString()));
           Log.w("AndroidParseXMLActivity", "Parse2");

           xr.parse(inStream);
           Log.w("AndroidParseXMLActivity", "Parse3");

           ArrayList<QuestionMaster> questionList = myXMLHandler.getQuestionsList();
           for(int i=0;i<questionList.size();i++){
                QuestionMaster question = questionList.get(i);
                parsedData = parsedData + "----->\n";
                parsedData = parsedData + "Queston No: " + question.getQuestionNo() + "\n";
                parsedData = parsedData + "QuestionText: " + question.getQuestionText() + "\n";
                parsedData = parsedData + "CorrectAnswer: " + question.getQuestionText() + "\n";
                parsedData = parsedData + "WrongAnswer1: " + question.getQuestionText() + "\n";
                parsedData = parsedData + "WrongAnswer2: " + question.getQuestionText() + "\n";
                parsedData = parsedData + "WrongAnswer3: " + question.getQuestionText() + "\n";
                parsedData = parsedData + "Answered: " + question.isAnswered() + "\n";
                parsedData = parsedData + "QuestionText: " + question.isAnsweredCorrectly() + "\n";
            }
            Log.w("AndroidParseXMLActivity", "Done");
        }catch (Exception e) {
            Log.w("AndroidParseXMLActivity",e );
        }
        xmlOutput.setText(parsedData);
    }
}
有人能指导我把这个
.xml
文件传给
XMLReader

编辑:

将其更改为:

InputSource inStream = new InputSource(getResources().openRawResource(R.raw.questions));

getXml()
返回
XmlPullParser
的实现,因此它已经设置为。将现有代码更改为使用
XmlPullParser
而不是SAX。

我认为应该将文件放在原始文件夹或资产文件夹中以使用SAX解析器,然后使用上下文从那里读取该文件

InputStream inStream = getResources().openRawResource(R.raw.questions);
xr.parse(inStream);
Android-从资产中读取文件

谢谢您的帮助,但是当我使用您的更改时,我得到了:XMLReader类型中的方法parse(InputSource)不适用于参数(InputStream)
InputStream inStream = getResources().openRawResource(R.raw.questions);
xr.parse(inStream);