Android:如何获取bundle密钥
我想不出如何获得条件方法的绑定键&/下面的Toast消息 对于我的学习经验,任何帮助都将不胜感激。ThnxAndroid:如何获取bundle密钥,android,variables,arguments,bundle,Android,Variables,Arguments,Bundle,我想不出如何获得条件方法的绑定键&/下面的Toast消息 对于我的学习经验,任何帮助都将不胜感激。Thnx public class ListViewFragment extends ListFragment implements OnItemClickListener { private final String KEY_ADPTR_ID = "KEY_ADPTR_ID"; } @Override public void onActivityCreated(Bundle sa
public class ListViewFragment extends ListFragment implements OnItemClickListener {
private final String KEY_ADPTR_ID = "KEY_ADPTR_ID";
}
@Override
public void onActivityCreated(Bundle savedInstanceState) {
super.onActivityCreated(savedInstanceState):
Bundle args = this.getArguments();
args.getString(KEY_ADPTR_ID);
. . .
}
. . .
private void showData(String json) throws JSONException {
String adptrID = this.getBundle(KEY_ADPTR_ID);//<-HOW DO I ACCOMPLISH THIS CORRECTLY!!??
Toast.makeText(getActivity(), adptrID, Toast.LENGTH_SHORT).show();
if (adptrID == "3") {
. . .
}
}
public类ListViewFragment扩展了ListFragment实现了ListClickListener{
私有最终字符串KEY\u ADPTR\u ID=“KEY\u ADPTR\u ID”;
}
@凌驾
已创建ActivityState上的公共无效(Bundle savedInstanceState){
super.onActivityCreated(savedInstanceState):
Bundle args=this.getArguments();
args.getString(KEY\u ADPTR\u ID);
. . .
}
. . .
私有void showData(字符串json)抛出JSONException{
String adptrID=this.getBundle(KEY_ADPTR_ID);//如果在片段的参数中传递KEY_ADPTR_ID,则在ActivityCreated中编写的内容是正确的
Bundle args = this.getArguments();
String keyAdaptrId = args.getString(KEY_ADPTR_ID);
Thnx。我刚刚试了一次,它工作正常。我想我第一次运行它时是o型的,我认为我获取密钥的方法不正确。