Android 安卓：获得工作，发布不会

我目前正在测试一些用于android编程的代码。我在这里找到了一些测试项目：

但问题是，我可以毫无问题地读取数据库，但函数不适用于POST only GET。因此，当我尝试添加新产品时，它会向我的php脚本发出请求，但根本没有POST数据。我是这样测试的：

<?php 
header("content-type:application/json; charset=UTF-8");
//print("fda");
/*
 * Following code will create a new product row
 * All product details are read from HTTP Post Request
 */

// array for JSON response
$response = array();

// check for required fields
//if (isset($_POST['name']) && isset($_POST['price']) && isset($_POST['description'])) {
//if (isset($_POST['name'])){
    $name = "test";//$_POST['name'];
    $price = 123; //$_POST['price'];
    $description = "desc"; //$_POST['description'];

foreach ($_POST as $key => $value)
 $data = $data." Field ".htmlspecialchars($key)." is ".htmlspecialchars($value);
    // include db connect class
//echo $data;
$url = $_SERVER['REQUEST_URI'];
    require_once __DIR__ . '/db_connect.php';

    // connecting to db
    $db = new DB_CONNECT();

    // mysql inserting a new row
    $result = mysql_query("INSERT INTO products(name, price, description, url) VALUES('$name', '$price', '$description','$data')");

    // check if row inserted or not
    if ($result) {
        // successfully inserted into database
        $response["success"] = 1;
        $response["message"] = "Product successfully created!.";

        // echoing JSON response
        echo json_encode($response);
    } else {
        // failed to insert row
        $response["success"] = 0;
        $response["message"] = "Oops! An error occurred.";

        // echoing JSON response
        echo json_encode($response);

    }
//} else {
//    // required field is missing
//    $response["success"] = 0;
//    $response["message"] = "Required field(s) is missing";
//
//    // echoing JSON response
//    echo json_encode($response);
//}
?>

---

Hi User i使用以下代码调用post到web服务。它可能会帮助你



**public String doPost(Activity activity, String urlString, String method, String value) 
                                                throws ClientProtocolException, IOException 
    {
        String responseString="";
        HttpURLConnection urlConnection = null;
        retryCount++;
        try 
        {
            URL url = new URL(urlString+method);
            urlConnection = (HttpURLConnection) url.openConnection();
            urlConnection.setRequestMethod("POST");
            urlConnection.setRequestProperty("Content-Type", "application/json");  
            urlConnection.setRequestProperty("Content-Length",value.length()+"" );  
            urlConnection.setDoInput( true );
            urlConnection.setDoOutput( true );
            DataOutputStream dos = new DataOutputStream( urlConnection.getOutputStream() );
            byte[] bs = value.getBytes();
            Log.d(tag, "Sending JSON String ->"+new String(bs));
            dos.write(bs);
            dos.flush();
            dos.close();
            Log.d(tag,"Responce ->"+urlConnection.getResponseMessage());
            if(urlConnection.getResponseMessage().toLowerCase().equals("ok"))
            {
                InputStream is = urlConnection.getInputStream();
                int ch;
                StringBuffer b =new StringBuffer();
                while( ( ch = is.read() ) != -1 )
                {
                    b.append( (char)ch );
                }
                responseString = b.toString();
                Log.d(tag,method + "','" + responseString);
                return method + "','" + responseString;
            }
            else
            {

                Log.d(tag, tag1+urlConnection.getResponseMessage());
            }
            dos.close();
        } 
        catch (SocketException e) 
        {

            Log.d(tag, tag1+e);

    }
        catch (Exception e) 
        {

            Log.e(tag,"-->"+ e);
        }

        return "";
    }**


在这里，URL字符串和方法构成了web服务方法的整个URL。
Hi，谢谢你叫我用户，我看到我没有名字。但回到话题上来，我试过了，但实际上并没有成功。这一切似乎都没有发送任何POST消息。也许需要在某处导入一些额外的文件？可能是发送错误的句子？嗨，liquidacid，很抱歉打电话给你的用户bcoz，我正在处理一个名为user的类。我在里面贴了一个json标签。不，您不需要任何外部文件或jar来进行此调用。


**public String doPost(Activity activity, String urlString, String method, String value) 
                                                throws ClientProtocolException, IOException 
    {
        String responseString="";
        HttpURLConnection urlConnection = null;
        retryCount++;
        try 
        {
            URL url = new URL(urlString+method);
            urlConnection = (HttpURLConnection) url.openConnection();
            urlConnection.setRequestMethod("POST");
            urlConnection.setRequestProperty("Content-Type", "application/json");  
            urlConnection.setRequestProperty("Content-Length",value.length()+"" );  
            urlConnection.setDoInput( true );
            urlConnection.setDoOutput( true );
            DataOutputStream dos = new DataOutputStream( urlConnection.getOutputStream() );
            byte[] bs = value.getBytes();
            Log.d(tag, "Sending JSON String ->"+new String(bs));
            dos.write(bs);
            dos.flush();
            dos.close();
            Log.d(tag,"Responce ->"+urlConnection.getResponseMessage());
            if(urlConnection.getResponseMessage().toLowerCase().equals("ok"))
            {
                InputStream is = urlConnection.getInputStream();
                int ch;
                StringBuffer b =new StringBuffer();
                while( ( ch = is.read() ) != -1 )
                {
                    b.append( (char)ch );
                }
                responseString = b.toString();
                Log.d(tag,method + "','" + responseString);
                return method + "','" + responseString;
            }
            else
            {

                Log.d(tag, tag1+urlConnection.getResponseMessage());
            }
            dos.close();
        } 
        catch (SocketException e) 
        {

            Log.d(tag, tag1+e);

    }
        catch (Exception e) 
        {

            Log.e(tag,"-->"+ e);
        }

        return "";
    }**