Android 我无法按关键字（其中KEY_TYPE=TYPE）和设置适配器ListView获取数据

我的代码有问题：

public class DBAdapter {

static final String TAG = "DBAdapter";

static final String KEY_ID = "_id";
static final String KEY_NAME = "name";
static final String KEY_ADDRESS = "formatted_address";
static final String KEY_TYPE = "type";
static final String KEY_LAT = "lat";
static final String KEY_LON = "lon";

static final String DATABASE_NAME = "MyDB";
static final String DATABASE_TABLE = "places";
static final int DATABASE_VERSION = 1;

static final String DATABASE_CREATE = "Create table places (_id integer primary key autoincrement, name text, formatted_address text, type text, lat text, lon text);";

final Context context;

DatabaseHelper DBHelper;
SQLiteDatabase db;

public DBAdapter(Context context){
    this.context = context;
    DBHelper = new DatabaseHelper(context);
}

//open database
public DBAdapter open() throws SQLException{
    db = DBHelper.getWritableDatabase();
    return this;
}

//close database
public void close(){
    DBHelper.close();
}

//get all places in database
public Cursor getAll(){
    return db.query(DATABASE_TABLE, new String[] {KEY_ID, KEY_NAME, KEY_TYPE, KEY_ADDRESS,
            KEY_LAT, KEY_LON}, null, null, null, null, null);
}

//get a place by id
public Cursor getPlaceById(String id) throws SQLException{
    Cursor cursor = db.query(true, DATABASE_TABLE, new String[] {KEY_ID, KEY_NAME, KEY_TYPE, KEY_ADDRESS,
            KEY_LAT, KEY_LON}, KEY_ID + "=" + id, null, null, null, null, null);
    if(cursor != null){
        cursor.moveToFirst();
    }
    return cursor;
}

//get places by type
public Cursor getPlaceByType(String type) throws SQLException{
    Cursor cursor = null;
    try{
        cursor = db.query(true, DATABASE_TABLE, new String[] {KEY_ID, KEY_NAME, KEY_TYPE, KEY_ADDRESS,
                KEY_LAT, KEY_LON}, KEY_TYPE + "=" + type, null, null, null, null, null);
        if(cursor != null){
            cursor.moveToFirst();
        }
        return cursor;
    }catch(Exception e){
        e.printStackTrace();
    }
    return cursor;
}

private static class DatabaseHelper extends SQLiteOpenHelper{
    DatabaseHelper(Context context){
        super(context, DATABASE_NAME, null, DATABASE_VERSION);
    }

    @Override
    public void onCreate(SQLiteDatabase db) {
        // TODO Auto-generated method stub
        try{
            db.execSQL(DATABASE_CREATE);
        }catch(SQLException e){
            e.printStackTrace();
        }
    }

    @Override
    public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
        // TODO Auto-generated method stub
        Log.w(TAG, "Upgrade database from version " + oldVersion + "to version " + newVersion + ", which will destroy all old data");
        db.execSQL("DROP TABLE IF EXISTS places");
        onCreate(db);
    }

}

}

有两个错误，包括：

//Get Place to show in ListView
    String type = spType.getSelectedItem().toString();
    Database db = new Database(this);
    try{
        arrPlaces = db.getPlaceByType(type);//Can not get data
    }catch(Exception e){
        e.printStackTrace();
    }

    /*
     *  ERROR CODE
     *  Can not show places in ListView
     */
    int length = arrPlaces.size();
    if(length > 0){
        for(int i=0; i<length; i++){
            Place place = arrPlaces.get(i);
            lstID.add(place.get_id());
            lstName.add(place.get_name() + "\n" + place.get_address());
        }


        ArrayAdapter<String> adapterName = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, lstName);
        adapterName.setNotifyOnChange(true);
        lstLocation.setAdapter(adapterName);    
    }

尝试按类型获取数据时出错：

android.database.sqlite.SQLiteException:near Places:语法错误：，编译时：从type=My Places的位置选择DISTINCT _id、名称、类型、格式化地址、lat、lon

我无法在ListView中显示数据。我犯了错误

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非常感谢您提供的任何帮助。

您的查询中缺少引号。当您使用的是字符串而不是数字时，需要将其括在引号中。您的查询代码应该如下所示，添加了`:

        cursor = db.query(true, DATABASE_TABLE, new String[] {KEY_ID, KEY_NAME, KEY_TYPE, KEY_ADDRESS, 
            KEY_LAT, KEY_LON}, KEY_TYPE + "='" + type + "'", null, null, null, null, null); 

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至于您的列表，您是否使用findViewById设置位置？如果您这样做了，您就不会在发布的代码中显示它…

发布完整的堆栈跟踪，并尝试将代码缩小到重要部分。对不起，我只是想清楚地显示代码。我剪了一个不需要的。非常感谢。这很有用。我使用findViewById在onCreate final ListView lstlocation=ListView findViewByIdR.id.lstlocation；中设置lstlocation；。我不知道我的错在哪里。

        cursor = db.query(true, DATABASE_TABLE, new String[] {KEY_ID, KEY_NAME, KEY_TYPE, KEY_ADDRESS, 
            KEY_LAT, KEY_LON}, KEY_TYPE + "='" + type + "'", null, null, null, null, null);