使用activeAndroid更新多个列

我想用活动android更新单行的多个单元格。 像这样的事情,

    new Update(Question.class).set("UserAnswer ="+answerID,
                                    "UserAnswerType = "+userAnswerType)
                               .where("QID = ?", questionID).execute();

但这会给我带来错误。还有别的办法吗？还是我遗漏了什么

这是我的问题，请参考

@Table(name = "Questions")
public class Question extends Model {
@Expose
@Column(name = "QID")
private Integer ID;

@Expose
@Column(name = "AnswerID")
private Integer AnswerID;

@Expose
@Column(name = "UserAnswer")
private Integer UserAnswer;

@Expose
@Column(name = "UserAnswerType")
private Integer UserAnswerType;

//Getter and setter methods for fields

public Question() {
    // You have to call super in each constructor to create the table.
    super();
}
}

---

你可以像下面这样做。我在我的一个项目中做过，效果很好

 String updateSet = " UserAnswer = ? ," +
                    " UserAnswerType = ? ";

 new Update(Question.class)
     .set(updateSet, answerID, userAnswerType)
     .where(" QID = ? ", questionID)
     .execute();

---

对于任何数量的列，都可以使用类似的模式。如果您的表中有

Boolean

类型字段，我们可以帮助您。

我们可以这样实现。

String x="sent = 1,file = "+n.getString("file");
new Update(Messages.class)
    .set(x)
    .where("id = ?", lid)
    .execute();

            StringBuilder data=new StringBuilder();

            if (!TextUtils.isEmpty(name.getText().toString()))
            {
                data.append("Name = '"+name.getText().toString()+"',");
            }
            if (!TextUtils.isEmpty(age.getText().toString()))
            {
                data.append("Age = '"+age.getText().toString()+"',");
            }
            if (!TextUtils.isEmpty(empCode.getText().toString()))
            {
                data.append("EmployeeCode = '"+empCode.getText().toString()+"',");
            }
            if (!TextUtils.isEmpty(mobNum.getText().toString()))
            {
                data.append("MobileNumber = '"+mobNum.getText().toString()+"',");
            }
            if (!TextUtils.isEmpty(adress.getText().toString()))
            {
                data.append("address = '"+adress.getText().toString()+"'");
            }
            String str=data.toString();

    //-------------and update query like this-----------------

    new Update(EmpProfile.class).set(str).where("EmployeeCode = ?", empCode)
                    .execute();

---

你能插入问题吗。类？@Erik JanWestendorp，已更新我的问题以供参考