Android截击错误D/截击：[486]基本网络.logSlowRequests:

我正在尝试使用Volley获取JSON对象以创建动态自动完成，但在使用Volley请求时，我在日志cat中看到：

D/Volley:[486]BasicNetwork.logSlowRequests:HTTP响应 请求=[lifetime=5648]，[size=363753]，[rc=200]， [retryCount=0]

这些并没有解决我的问题

下面是初始化请求队列的Singleton类：

import android.content.Context;

import com.android.volley.DefaultRetryPolicy;
import com.android.volley.Request;
import com.android.volley.RequestQueue;
import com.android.volley.toolbox.Volley;

public class SingleTon {
    private Context context;
    private RequestQueue requestQueue;
    public static SingleTon singleTon;
    public SingleTon(Context context){
        this.context=context;
        requestQueue=getRequestQueue();
    }
    private RequestQueue getRequestQueue(){
        if(requestQueue==null){
            requestQueue= Volley.newRequestQueue(context);
        }
        return requestQueue;
    }
    public synchronized static SingleTon getInstance(Context context){
        if(singleTon==null){
            singleTon=new SingleTon(context.getApplicationContext());
        }
        return singleTon;
    }
    public void addToRequestQueue(Request request){
        requestQueue.add(request).setRetryPolicy(new DefaultRetryPolicy([I have tried all possible combinations here]));
    }
}

发出请求的方法：

public Filter getFilter() {
    Filter filter=new Filter() {
        @Override
        protected FilterResults performFiltering(CharSequence charSequence) {
            FilterResults filterResults=new FilterResults();
            if(charSequence!=null){
                String partialName=charSequence.toString();
                String url="https://api.railwayapi.com/v2/suggest-train/train/"+partialName+"/apikey/xnlo6zq3yj/";
                HTTPConnector httpConnector=new HTTPConnector(url,context);
                JSONObject response=httpConnector.getJsonResponse();
                try {
                    JSONArray trains=response.getJSONArray("trains");
                    for(int i=0;i<trains.length();i++){
                        trainName.add(new Train(trains.getJSONObject(i).getString("number")));
                    }
                } catch (JSONException e) {
                    e.printStackTrace();
                }
                filterResults.values=trainName;
                filterResults.count=trainName.size();
            }
            return filterResults;
        }

公共过滤器getFilter（）{
过滤器过滤器=新过滤器（）{
@凌驾
受保护过滤器结果执行过滤（CharSequence CharSequence）{
FilterResults FilterResults=新的FilterResults（）；
if（charSequence！=null）{
String partialName=charSequence.toString（）；
字符串url=”https://api.railwayapi.com/v2/suggest-train/train/“+partialName+”/apikey/xnlo6zq3yj/”；
HTTPConnector HTTPConnector=新的HTTPConnector（url，上下文）；
JSONObject response=httpConnector.getJsonResponse（）；
试一试{
JSONArray trains=response.getJSONArray（“trains”）；
对于（inti=0；i这是一种奇怪的使用Volley的方式。Volley会发出异步HTTP请求。您的这两行代码不会每次都给出结果

 HTTPConnector httpConnector=new HTTPConnector(url,context);
 JSONObject response=httpConnector.getJsonResponse();

您正在发送async..request并立即调用
getJsonResponse
函数？在调用该函数时，您不能确定响应是否可用。当收到响应时，即
OnResponse
方法中的
JsonObjectRequest

因此，您应该正确地实现
HTTPConnector
类和包含
getFilter
方法的类之间的通信

您可以为此使用接口。在
HTTPConnector
类中声明接口，并在
活动中实现它

public class HTTPConnector {
    String url;
    JSONObject jsonResponse;
    Context context;
    IMyInterface  mListener;
    public interface IMyInterface
   {
    void sendResponse(JsonObject obj);
   }

    public HTTPConnector(String url,Context context,IMyInterface pListener){
        this.url=url;
        this.context=context;
        mListener=pListener
    }


    public void makeQuery(){
        JsonObjectRequest request=new JsonObjectRequest(Request.Method.GET, url, null, new Response.Listener<JSONObject>() {
            @Override
            public void onResponse(JSONObject response) {
                jsonResponse=response;
             if(mListener!=null)
           {
            mListener.sendResponse(response);
           }
             }
        }, new Response.ErrorListener() {
            @Override
            public void onErrorResponse(VolleyError error) {
                Toast.makeText(context,"ERROR",Toast.LENGTH_SHORT).show();
                Log.d("ERROR: ", error.toString());
               if(mListener!=null)
                {
                   mListener.sendResponse(null);
                }
            }
        });
        SingleTon.getInstance(context.getApplicationContext()).addToRequestQueue(request);
    }
}

你有没有试过在网页浏览器中点击url，需要多少时间才能得到结果？我已经提到过它没有帮助。@duggu是的，我试过了。没花多少时间。谢谢。它有帮助。很高兴帮助你
public class HTTPConnector {
    String url;
    JSONObject jsonResponse;
    Context context;
    IMyInterface  mListener;
    public interface IMyInterface
   {
    void sendResponse(JsonObject obj);
   }

    public HTTPConnector(String url,Context context,IMyInterface pListener){
        this.url=url;
        this.context=context;
        mListener=pListener
    }


    public void makeQuery(){
        JsonObjectRequest request=new JsonObjectRequest(Request.Method.GET, url, null, new Response.Listener<JSONObject>() {
            @Override
            public void onResponse(JSONObject response) {
                jsonResponse=response;
             if(mListener!=null)
           {
            mListener.sendResponse(response);
           }
             }
        }, new Response.ErrorListener() {
            @Override
            public void onErrorResponse(VolleyError error) {
                Toast.makeText(context,"ERROR",Toast.LENGTH_SHORT).show();
                Log.d("ERROR: ", error.toString());
               if(mListener!=null)
                {
                   mListener.sendResponse(null);
                }
            }
        });
        SingleTon.getInstance(context.getApplicationContext()).addToRequestQueue(request);
    }
}

public class MainActivity extends AppCompatActivity implements HTTPConnector.IMyInterface
{
  ...........
  ...........
  // Your other code of activity
  ...........
  ..........

  @Override
  public void sendResponse(JsonObject response)
  {
   try {
       JSONArray trains=response.getJSONArray("trains");
       for(int i=0;i<trains.length();i++){
                    trainName.add(new Train(trains.getJSONObject(i).getString("number")));
                }
               //Now you have response and filled the list, can call getFilter
            } catch (JSONException e) {
                e.printStackTrace();
            }

  }

}

String url="https://api.railwayapi.com/v2/suggest-train/train/"+partialName+"/apikey/xnlo6zq3yj/";
    HTTPConnector httpConnector=new HTTPConnector(url,context,this); // this will act as your listener
    httpConnector.makeQuery();