Android SDK管理器：无法使用“启动”；安卓程序；在SDK（MAC）的tools文件夹中

很抱歉打扰您，但我对java SDK和android SDK还不熟悉。我正在尝试打开SDK管理器，进入tools文件夹并打开“android”程序后，我得到以下信息：

#!/bin/sh
# Copyright 2005-2007, The Android Open Source Project
#
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
#     http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS,
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
# See the License for the specific language governing permissions and
# limitations under the License.

# Set up prog to be the path of this script, including following symlinks,
# and set up progdir to be the fully-qualified pathname of its directory.
prog="$0"

    while [ -h "${prog}" ]; do
        newProg=`/bin/ls -ld "${prog}"`
        newProg=`expr "${newProg}" : ".* -> \(.*\)$"`
        if expr "x${newProg}" : 'x/' >/dev/null; then
            prog="${newProg}"
        else
            progdir=`dirname "${prog}"`
            prog="${progdir}/${newProg}"
        fi
    done
    oldwd=`pwd`
    progdir=`dirname "${prog}"`
    cd "${progdir}"
    progdir=`pwd`
    prog="${progdir}"/`basename "${prog}"`
    cd "${oldwd}"

    jarfile=sdkmanager.jar
    frameworkdir="$progdir"
    if [ ! -r "$frameworkdir/$jarfile" ]
    then
        frameworkdir=`dirname "$progdir"`/tools/lib
    fi
    if [ ! -r "$frameworkdir/$jarfile" ]
    then
        frameworkdir=`dirname "$progdir"`/framework
    fi
    if [ ! -r "$frameworkdir/$jarfile" ]
    then
        echo `basename "$prog"`": can't find $jarfile"
        exit 1
    fi


    # Check args.
    if [ debug = "$1" ]; then
        # add this in for debugging
        java_debug=-agentlib:jdwp=transport=dt_socket,server=y,address=8050,suspend=y
        shift 1
    else
        java_debug=
    fi

    java_cmd="java"

    # Mac OS X needs an additional arg, or you get an "illegal thread" complaint.
    if [ `uname` = "Darwin" ]; then
        os_opts="-XstartOnFirstThread"
    else
        os_opts=
    fi

    if [ `uname` = "Linux" ]; then
        export GDK_NATIVE_WINDOWS=true
    fi

    if [ "$OSTYPE" = "cygwin" ] ; then
        jarpath=`cygpath -w  "$frameworkdir/$jarfile"`
        jarpath="$jarpath;"`cygpath -w  "$frameworkdir/swtmenubar.jar"`
        progdir=`cygpath -w  "$progdir"`
    else
        jarpath="$frameworkdir/$jarfile:$frameworkdir/swtmenubar.jar"
    fi

    # Get the current content of java.ext.dirs so that we can add to it instead of replacing
    javaExtDirs=`"${java_cmd}" -jar "${frameworkdir}/archquery.jar" java.ext.dirs`

    # Figure out the path to the swt.jar for the current architecture.
    # if ANDROID_SWT is defined, then just use this.
    # else, if running in the Android source tree, then look for the correct swt folder in prebuilt
    # else, look for the correct swt folder in the SDK under tools/lib/
    swtpath=""
    if [ -n "$ANDROID_SWT" ]; then
        swtpath="$ANDROID_SWT"
    else
        vmarch=`"${java_cmd}" -jar "${frameworkdir}/archquery.jar"`
        if [ -n "$ANDROID_BUILD_TOP" ]; then
            osname=`uname -s | tr A-Z a-z`
            swtpath="${ANDROID_BUILD_TOP}/prebuilts/tools/${osname}-${vmarch}/swt"
        else
            swtpath="${frameworkdir}/${vmarch}"
        fi
    fi

    if [ ! -d "$swtpath" ]; then
        echo "SWT folder '${swtpath}' does not exist."
        echo "Please export ANDROID_SWT to point to the folder containing swt.jar for your platform."
        exit 1
    fi

        # need to use "java.ext.dirs" because "-jar" causes classpath to be ignored
        exec "$java_cmd" \
            -Xmx256M $os_opts $java_debug \
            -Dcom.android.sdkmanager.toolsdir="$progdir" \
            -classpath "$jarpath:$swtpath/swt.jar" \
            com.android.sdkmanager.Main "$@"

---

并且没有SDK管理器平台。我看了其他视频，其中一个人刚刚打开android程序，SDK管理器启动。有什么想法吗？感谢您抽出时间

这有点难说，但我猜您是在双击文件并在文本编辑器中查看其内容

---

所以，您的问题是脚本是用错误的程序打开的。它应该使用命令shell打开，而不是文本编辑器。查看您是否不熟悉更改用于打开文件的应用程序的过程。

就是这样。很抱歉我的无知，但谢谢你指出这一点，它治好了我的头痛！