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Android 按任意项从sqlite查找id_Android_Sqlite_Find_Android Sqlite - Fatal编程技术网

Android 按任意项从sqlite查找id

Android 按任意项从sqlite查找id,android,sqlite,find,android-sqlite,Android,Sqlite,Find,Android Sqlite,我必须在数据库中找到“id”,我尝试了这种方法,但我无法解决它。你能帮我吗。非常感谢 listview.setOnItemClickListener(new AdapterView.XouOnItemClickListener() { @Override public void onItemClick(AdapterView<?> arg0, View arg1, int arg2, l

我必须在数据库中找到“id”,我尝试了这种方法,但我无法解决它。你能帮我吗。非常感谢

listview.setOnItemClickListener(new AdapterView.XouOnItemClickListener() {

        @Override
        public void onItemClick(AdapterView<?> arg0, View arg1, int arg2,
                                long arg3) {

            String text = (String) listview.getItemAtPosition(arg2);


            Database db = new Database(getApplicationContext());
            String query = "SELECT name, id FROM tableDB WHERE name = '" + text + "'"; // I think problem is here
            Cursor cursor = db.rawQuery(query, null);
            cursor.moveToFirst();

             id_position = cursor.getInt(cursor.getColumnIndex("id"));

            go_detail();
        }
    });

我认为错误在您的
go\u detail
函数中。尝试添加一个参数,例如
go_detail(int id_position){….}
现在,如果没有参数,它无法获取id

否。我一行一行地尝试。明确的问题是这行字符串query=“SELECT def,id FROM tuncDB,其中def=”+second+”;但是您希望如何在
go\u detail
函数中获得
id\u position
的值呢
private void go_detail(){
            Intent intent = new Intent(getApplicationContext(), Detail_page.class);
            intent.putExtra("id", (int) name_ids[id_position]);
            startActivity(intent);
}